weird string problem

[Boni]

Dear all,

I need to replace in a long string all chr(10) to chr(10)chr(13) if 13 is
not behind 10.

dim str as string=....

If str.Chars(i) = vbLf And str.Chars(i + 1) <> vbCr Then

str.Insert(i, vbCr)

i = i + 1

End If



But if set a breakpoint on insert and look on str before and after insert I
can see, that vbCr is just not inserted!!! ascii(str.Chars (i) ) and
str.Chars(i+/-1) are not 13!!!

What is wrong??

Thanks,

Boni

[Chris Dunaway]

Re: weird string problem

The answer is that strings are immutable, meaning they cannot change.
The insert method returns a new strings with your changes, therefore
you need to assign it back to your string variable:

str = str.Insert(i,vb Cr)

[Boni]

Re: weird string problem

Or noooo. Soo simple. I might need some sleep !
Thanks Chris
"Chris Dunaway" <dunawayc@gmail .com> schrieb im Newsbeitrag
news:1124809487 .148083.308100@ f14g2000cwb.goo glegroups.com.. .[color=blue]
> The answer is that strings are immutable, meaning they cannot change.
> The insert method returns a new strings with your changes, therefore
> you need to assign it back to your string variable:
>
> str = str.Insert(i,vb Cr)
>[/color]

[Dragon]

Re: weird string problem

Hi,

String.Insert doesn't change the original string (as well as other
String methods), but generates a new
one instead.

So,
1. Use str = str.Insert(i,vb Cr) - or -
2. Use StringBuilder for that.

BTW, have you considered using RegEx for this kind of job? It's pretty
simple:
str = System.Text.Reg ularExpressions .Regex.Replace( str, "\x0a(?!\x0 d)",
Chr(10) & Chr(13))

Roman

[Boni]

Re: weird string problem

Hi Dragon,
I was thinking about regexes, but my feeling was to avoid regexes for simple
things because of performance reasons. But as I see the building of temp
string objects seems to take time too. So I switch to regex. I don't think
that I will mention timing difference.

Thank you for an advice,
Boni
"Dragon" <no@spam.please > schrieb im Newsbeitrag
news:eFi2qX$pFH A.3424@TK2MSFTN GP14.phx.gbl...[color=blue]
> Hi,
>
> String.Insert doesn't change the original string (as well as other
> String methods), but generates a new
> one instead.
>
> So,
> 1. Use str = str.Insert(i,vb Cr) - or -
> 2. Use StringBuilder for that.
>
> BTW, have you considered using RegEx for this kind of job? It's pretty
> simple:
> str = System.Text.Reg ularExpressions .Regex.Replace( str, "\x0a(?!\x0 d)",
> Chr(10) & Chr(13))
>
> Roman
>
>
>[/color]