Here is one way to return all duplicate rows based on the two columns (SQL
Server 2005):
;WITH Dups
AS
(SELECT reference_, suppliercode_, value_,
COUNT(*) OVER(
PARTITION BY reference_,
value_) AS cnt
FROM #TMP)
SELECT reference_, suppliercode_, value_
FROM Dups
WHERE cnt 1;
HTH,
Plamen Ratchev
Server 2005):
;WITH Dups
AS
(SELECT reference_, suppliercode_, value_,
COUNT(*) OVER(
PARTITION BY reference_,
value_) AS cnt
FROM #TMP)
SELECT reference_, suppliercode_, value_
FROM Dups
WHERE cnt 1;
HTH,
Plamen Ratchev
