Output strings to directory locally

[flawrence]

Is it possible to output strings created from a print statement into a directory locally?
If so, would you use sysstdout module?

[bvdet]

You can assign sys.stdout to an open file object.

f = open("test.txt", 'w')
sys.stdout = f

Subsequent print statements will direct the output to the open file.

[flawrence]

Thank you! However, my files do not have a .etc extension. They are unique and I need them to actually be propagated straight into a directory. Is this possible?

[bvdet]

It's a good idea to save the old value of sys.stdout and restore it when you are done.

stdout_old = sys.stdout
sys.stdout = open("test.txt", 'a')
# do stuff
sys.stdout = stdout_old

[bvdet]

Not that I know of. Information is stored on disc in files. A directory is not a file. BTW, File objects don't have to have extensions.

[dwblas]

If you are running linux you can pipe standard output to a file directly

program_name.py > output_print_fi le.txt

[flawrence]

So I tried the sysstd output with this code

import os

path = '/Users/felishalawrence/testswps/vol1'  
for file in os.listdir(path):
        newFile = file[:file.rindex("v")]+"v20"
sys.stdout =  '/Users/felishalawrence/testswps/vol1'
print newFile

and got nothing. No errors and it did not print out my results in ipython notebook when I removed line 5 and ran it again. The output was also not in the folder specified. What did I do wrong? Can I reset it? If so, how?

[bvdet]

In your for loop, you define a value to identifier "newfile", but you perform no action with this value. After the for loop, you assign sys.stdout to a directory when it should be assigned to an open file object. The following print statement goes nowhere.