Splitting a file into multiple file based on some pattern

[rokstar24]

the text file is like:
shfhsgfkshkjg
gkjsfkgkjfgkfg
model1
lkgjhllghfjgh
kjfgkjjfghg
endmodel
model2
jfhkjhcgbkcjg
xhbgkxfkgh
endmodel

i want between each model and endmodel ,what is the text should be in the new file.and file name should be like model1,model2.. ..model may be 100 or more.please help me.

[sicarie]

Between the two, it looks like "model" is the same between. You could either write a regex or parse the file for matching characters.

[rokstar24]

but how to write for making the new text file each time.

[bvdet]

The file could be written something like:

fn = "model1"
f = open(fn, "w")
f.write("\n".join(content))
f.close()

"content" would be a list of the text items between "modelX" and "endmodel".

A possible regex pattern could be:

import re
patt = re.compile(r"(model\d+)\n([0-9a-zA-Z\n]+?)endmodel",  re.MULTILINE)

Then the file names and content could be extracted to a list of lists:

contents = patt.findall(s)

[rokstar24]

bro does it give 100 FILE if 100 models are there...

[bvdet]

rokstar24,

Yes, if the models are uniquely identified.

[rokstar24]

can anyone give me proper code which will run directly..becau se i m trying but i am not getting it.

[rokstar24]

f=open("E:\pra.txt","r+")


import re,sys
k= re.findall(r"(model\d+)\n([0-9a-zA-Z\n]+?)endmodel",f.read())

count = 1
fwrite = open("filename%s" %(count), 'w')
for line in f:
    if k in line:
        # close open file object, increment count, open new file object
        
        count += 1
        fwrite = open("filename%s" %(count), 'w')
        fwrite.write(k)
fwrite.close()
f.close()

i have written this..tell me where i m wrong??

[rokstar24]

how to make this k to be written in new file..because it is showing k is not string.

[bvdet]

You are right - 'k' is not a string. It is a list of lists, and you have to get the appropriate individual elements, which are strings, and write them to disk. 'k' may look something like this:

[('model1', 'lkgjhllghfjgh\nkjfgkjjfghg\n'), ('model2', 'jfhkjhcgbkcjg\nxhbgkxfkgh\n')]

[dwblas]

k= re.findall(r"(m odel\d+)\n([0-9a-zA-Z\n]+?)endmodel",f. read())

and
if k in line:

are redundant. Forget the findall and just use if "model" in line, or since the line starts with "model" and we don't want "endmodel"
if line.startswith (model)

test_data = """the text file is like:
 shfhsgfkshkjg
 gkjsfkgkjfgkfg
 model1
 lkgjhllghfjgh
 kjfgkjjfghg
 endmodel
 model2
 jfhkjhcgbkcjg
 xhbgkxfkgh
 endmodel"""

file_input = test_data.split("\n")
model_list = []
ctr = 0
for line in file_input:
    line = line.strip()
    if line.startswith("model"):
        if ctr:     ## first group is junk & not copied
            with open(model_list[0], "w") as fp_out:
                for rec in model_list:
                    fp_out.write("%s \n" % (rec))
        ctr += 1
        model_list = []
    model_list.append(line)

## final list
with open(model_list[0], "w") as fp_out:
    for rec in model_list:
        fp_out.write("%s \n" % (rec))

[rokstar24]

can anyone tell
if i have to give if condition for

model        1

means 8 spaces exactly are between model and 1.then what should i do exactly to give condition for finding it.

[bvdet]

Assuming you want to use the regex solution:

patt = re.compile(r"(model *\d+)\n([0-9a-zA-Z\n]+?)endmodel",  re.MULTILINE)

[dwblas]

Or use split and join which is also a "standard" way.

test_string="model        1"
print test_string
print  "becomes", "".join(test_string.split())