making a list with leading zeros

[Miguel Valenzue]

I am using the range function tomake a list of jpgs between 1 and 200 but want there to be leading zeros in the list.
My current code is like this.

myList=[]

for i in range (0,10):
     myList.append (("00%s.jpg)%(i))

for i in range (10,100):
     myList.append (("0%s.jpg)%(i))

for i in range (100,200):
     myList.append (("%s.jpg)%(i))

the result is as follows:

000.jpg
001.jpg
etc.

It basically adds the leading zeros in three different steps. It works but I wanted to know if there is a more elegant solution.
Thanks

[Rabbit]

1) Append 2 zeroes to the string.
2) Take the right 3 characters.
3) Append the .jpg.

[bvdet]

String formatting can accomplish that on one range.

>>> for i in range(1, 201):
... 	print "%03d.jpg" % (i)
... 	
001.jpg
002.jpg
003.jpg
004.jpg
005.jpg
006.jpg
007.jpg
008.jpg
009.jpg
010.jpg
011.jpg
012.jpg
013.jpg
014.jpg
015.jpg
016.jpg
017.jpg
018.jpg
019.jpg
020.jpg
021.jpg
022.jpg
023.jpg
024.jpg
025.jpg
....snip....
199.jpg
200.jpg
>>>