calculating the roots of ax**2+bx+c

[MR 010]

hello :

This is my code :

------------------------------------------

while True :
    try:
        ' enter the coefficients of the equation :'

        a=input('a=' )
        b=input('b=' )
        c=input('c=' )

        r=b**2-4*a*c
        import cmath
        sq=cmath.sqrt

        if r==0 :
            x=(-b)/(2*a)
            y=(-b)/(2*a)
            print 'the roots are :',x,',',y

        elif r>0 :
            x=((-b)+sq(r))/(2*a)
            y=((-b)-sq(r))/(2*a)
            print 'the roots are :',x,',',y

        if r<-1 :
            i=sq(-1)
            x=(-b+(sq(r*(i**2))))/(2*a)
            y=(-b-(sq(r*(i**2))))/(2*a)
            print 'the roots are :',x,',',y
    except :
        print 'wrong inputs , please enter numbers only'

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when r<-1
############### ############### ############### ########
### the results are not like the casio calculater ###
############### ############### ############### ########

[MR 010]

I found it myself :)

i should use abs(r) :) , thanks for giving me a chance to ask you :)

[bvdet]

MR 010 - Kudos to you for finding the issue. Thanks for the update.