Syntax error in python 2.3.4

[akilasekaran]

oh sorry.. i am new to the forum.. ll use code tag :)

[akilasekaran]

i tried using indentation.. but the error comes in the print line following the client accept code. i.e 2nd line from try. :(

[bvdet]

No problem. Code formatting does not display properly unless code tags are used. You can easily add them by selecting the text you want to wrap in tags and picking the "#" button at the top of the reply widget.

[akilasekaran]

i rectified the error myself :) thanku sooo much.. :)

[akilasekaran]

the error was all about indentation and proper port mentioning :-)

[bvdet]

I suspect it is still an indentation problem. Your indentation should look like this:

from socket import *
s = socket(AF_INET,SOCK_STREAM) 
h=gethostbyname(gethostname())
print 'host is ',h
s.bind((h,9000))
s.listen(1)
while 1:
    try:
        client, address = s.accept()
        print 'connection from', address
        data = client.recv(1024)
        if not data:
            break 
        client.send(data) 
        client.close()
 
    except IOError:
        print'IOError is there !'
        client.close()

Note that the number of spaces representing an indentation is a matter of preference but should be consistent. I prefer 4 spaces. Also note it is bad practice to mix spaces and tabs.

[akilasekaran]

oh okays :) got it :)