MySQL Select, from tuple to list

[sithlordkyle]

Hopefully I can explain this correctly. I am trying to take a MySQL select statement, get the output into a list, then upload that list back to the MySQL server.

cursor.execute("SELECT stuff FROM place WHERE thing = 3 ORDER BY track_id ASC")

This spits out a tuple of integers ...

((1L,), (2L,), (3L,), (4L,), (5L,), (6L,), (7L,), (8L,), (9L,), (10L,), (11L,))

... with an 'L' following each one.

But I want to update the database with this set as:

1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11

At first I thought I had it, but each converted row of tuples was the same thing even though the actually data pulled had changed. Anyone have any ideas how to do this?

[Glenton]

It sounds like you want to convert something from a tuple containing a long integer into an integer?

for t in ((1L,), (2L,), (3L,), (4L,), (5L,), (6L,), (7L,), (8L,), (9L,), (10L,), (11L,)):
    print int(t[0])

[sithlordkyle]

Glenton, thanks for the response. I actually got it to give me the list without the L in it. But that's half the thing. I need to dump those numbers back into a list and insert that list into a MySQL database.

I think that PHP will provide a better solution than Python at this point.

[sithlordkyle]

Actually, I figured it out myself...

for n in range(0,75):
  cursor.execute("SELECT row FROM table WHERE column = %s ORDER BY column ASC", (n))
  result = cursor.fetchall()
  List = list()
  for t in result:
    List.append(int(t[0]))
  List = ",".join(map(str,List))
  ListUpdate = cursor.execute("UPDATE table SET column = %s WHERE column = %s", (str(List),n))

This will take the SELECT statement from MySQL as a tuple, format it into a list without the L or parenthesis, then UPDATE the MySQL with the list.