the str.split(sep,maxsplit) function

[david2031]

given:
my = 'my name is david'

i would like to make this into a list with 2 values
i would like the list to be:
mylist = ['my name is','david']

so i try using:
mylist = my.split(' ',1)

but i soon find it splits left to right which returns:
mylist = ['my','name is david']

to avoid having to use alot of other code, i am wondering if there is a way to make it split right to left or reverse of the way its splitting?

[bvdet]

Following are a couple of ways, but each requires additional code.

>>> s = 'my name is david'
>>> s.split()
['my', 'name', 'is', 'david']
>>> s1 = 'my david'
>>> s2 = 'david'
>>> def split_once_rightmost(s):
... 	seq = s.split()
... 	if len(seq) > 1:
... 		return [" ".join(seq[0:-1]), seq[-1]]
... 	return seq
... 
>>> split_once_rightmost(s)
['my name is', 'david']
>>> split_once_rightmost(s1)
['my', 'david']
>>> split_once_rightmost(s2)
['david']
>>> seq = s.replace(" ", "***", s.count(" ")-1).split(" ")
>>> seq[0] = seq[0].replace("***", " ")
>>> seq
['my name is', 'david']
>>>

[basilho]

>>> my = 'my name is david'
>>> import re
>>> re.findall('(.*)\s(.*)', my)
[('my name is', 'david')]

or

>>> my
'my name is david'
>>> lst = my.split(' ')
>>> lst
['my', 'name', 'is', 'david']
>>> result = []
>>> result.append(' '.join(lst[:-1]))
>>> result.append(lst[-1])
>>> result
['my name is', 'david']

[bvdet]

I knew there would be a re solution. Thanks for posting basilho. You can use match object method group to create the OP's mylist.

>>> my = 'my name is david'
>>> import re
>>> patt = re.compile('(.*)\s(.*)')
>>> m = patt.match(my)
>>> [m.group(1), m.group(2)]
['my name is', 'david']
>>>

[papin]

The very basics of lists:

>>> my = my.split()
>>> print (' '.join(my[:-1]), my[-1])
('my name is', 'david')