How to loop to make many .csv files?

[ronparker]

Hey guy!
I have a couple questions, which I don't think are too advanced. I created an algorithm called "Best" for simplicity I will not include the mathematical details of it. I ask the user to input 6 values: Stock, min,win,Stop,GO , and end. Looking at the last 5 inputs, they are all integer inputs eg: 1,2,3.
This code will take my algorithm and spit out a csv file called "boom.csv" with two columns of numbers based on the input values. My questions are as follow:

-Can a loop be made so i input 3 integers for each user input, then spit out one .csv file for each combination of user input values?
I know I would need to some how create a way to name the .csv files for each combination of user inputs, but how would I do that?
Also how would I make a loop that can look at each combination of the user input values?
So with 3 integers per 5 input values, that should be 3^5 outputs.

Thank you for any help!
Ron Parker

#!/usr/bin/python
import  numpy
import csv



def Best(seq):
	ALGORITHM

Stock=raw_input('Stock Symbol: ' )

min=raw_input('Start time (min away from open) : ' )
win=raw_input('Window (min): ' )
Stop=raw_input('SL: ' )
Go=raw_input('PL: ' )
end=raw_input('End time (min away from open) : ' )


Entry=[ Best(something1[ i:i+120]) for i in range(0, len(something1), 120)]
Entry2=[float(item[0]) for item in Entry]
Entry3=[float(item[1]) for item in Entry]



myFile= open( "Boom.csv", "wb" )
wtr= csv.writer( myFile )
for Start, Exit, in zip(Entry2,Entry3):
	aRow=Start
	bRow=Exit
	cRow=[aRow,bRow]
	wtr.writerow(cRow)
	
myFile.close()

[bvdet]

I think you need a way to calculate all the possible permutations. A function that returns the permutations can be found here.

If you have a list of letters, a file name can be constructed thus:

>>> ext = "csv"
>>> seq = ['a','b','c','d','e']
>>> '.'.join(["".join(seq), ext])
'abcde.csv'
>>>

OR

>>> "%s.%s" % ("".join(seq), ext)
'abcde.csv'
>>>