How do I convert the sequential day of the year to a date?

[Charlie Day]

I have the sequential day of the year (e.g. 295). I want to convert that to it's equivalent, October 22.

[bvdet]

You can calculate the date with the datetime module. Example:

>>> import datetime
>>> datetime.datetime(2010,1,1)
datetime.datetime(2010, 1, 1, 0, 0)
>>> print datetime.datetime(2010,1,1)
2010-01-01 00:00:00
>>> dt = datetime.datetime(2010,1,1)
>>> dtdelta = datetime.timedelta(days=295)
>>> dt + dtdelta
datetime.datetime(2010, 10, 23, 0, 0)
>>>