Help on simple input output thing in python.

[Jeremy Rohrer]

Ok, so what I need to is just have it simply print out if the number is between 7 or 13 to print out whats in the quotes... I'm stuck at this point and I can't figure it out cause it won't print anything out. PLEASE HELP :)

if num_correct < 7 or > 13:
    print 'You got a check in the lab.'
elif num_correct < 3 or > 6:
    print 'You got a minus in the lab.'
elif num_correct < 0 or > 2:
    print 'You got a zero in the lab.'

#This is to show the values in the range.
if num_correct == "14":
    print 'You got a plus for the lab.'
elif num_correct == "7" or num_correct == "8" or\
num_correct == "9" or num_correct == "10" or\
num_correct == "11" or num_correct == "12" or\
num_correct == "13":
    print 'You got a check for the lab.'
elif num_correct == "3" or num_correct == "4" or\
num_correct == "5" or num_correct == "6":
    print 'You got a minus for the lab.'
elif num_correct == "0" or num_correct == "1":
    print 'You got a zero for the lab.'

[dwblas]

Note the difference between these two statements

if num_correct < 7 or > 13:
elif num_correct == "7" or num_correct == "8"

An "or" statement is simply an if() + elif()

if num_correct == "7" or num_correct == "8":
   print "num_correct"
#
# can be expressed as
if num_correct == "7":
    print "num_correct"
elif num_correct == "8":
    print "num_correct"

so the code you posted breaks down into

if num_correct < 7 or > 13:
#
# can also be expressed by
if num_correct < 7:
    print "#1 num_correct:
elif > 13:
    print "#2 num_correct"

[Jeremy Rohrer]

Ok thank you so much... I also talked to my teacher about it and he pretty much said the same thing. thanks for you help.