Writting a function

[Fernando T]

How would i write a function that prints all numbers in the range a to b(inclusive) that have all digits belonging to the set (1,3,4,8,9). The function takes two integer arguments:A and B...


I understood the question and i have seen an example with the (dictionary.txt ), but it was to check vowels in words. So for this one i don't know how i would check for those numbers in the range which the user wishes....Lets say from 10000 to 1,000,000

[bvdet]

The first hurdle is to convert the number to a list of the individual digits and create a set object from the list. Then you can do set1.issubset(s 0) to determine if all the digits are in the set (1,3,4,8,9). There are a couple of ways to do this off the top of my head. This is probably the easiest:

>>> n = 1234567890
>>> list(str(n))
['1', '2', '3', '4', '5', '6', '7', '8', '9', '0']
>>> map(int, list(str(n)))
[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
>>> [int(i) for i in list(str(n))]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 0]
>>> set([int(i) for i in list(str(n))])

The other way is a loop using divmod():

def numtodigits(n):
    output = []
    while True:
        a,b = divmod(n, 10)
        output.insert(0, b)
        n = a
        if not a: return output
'''
>>> numtodigits(1230)
[1, 2, 3, 0]
>>> 
'''