How do I isolate individual digits of numbers in python?

[kevow123]

If i had the number 123 how would i make it 321?

[bvdet]

I'll bite

>>> int(str('123')[::-1])
321
>>>

[dwblas]

Add 2 to the first digit and subtract 2 from the last digit?
or add 198 to the first number??
This code was done for some reason some time ago but I don't remember why.

from collections import deque

x = 123
new_x = 0
while x > 0:
    x, y = divmod(x, 10)
    new_x = new_x*10 + y
print new_x

x = 123
d = deque()
for num in str(x):
   d.appendleft(num)
print "using deque",
print "".join(d)

[bvdet]

I like that dwblas.

[kevow123]

thanks

thanks guys.

[dwblas]

One more for the sake of completeness for any searchers.

x = 12345
new_str = ""
for ch in str(x):
    new_str = ch + new_str
print int(new_str)

[bvdet]

Here's another way, also using built-in function divmod():

>>> def digits(n):
... 	results = []
... 	while n:
... 		n, x = divmod(n, 10)
... 		results.insert(0, x)
... 	return results
... 
>>> digits(123456789)
[1, 2, 3, 4, 5, 6, 7, 8, 9]
>>> sum([d*10**i for i, d in enumerate(digits(123456789))])
987654321
>>>