How to use brackets in Python?

[Thebuilderofdoom]

nubr1 = 0
s = open("C:/DsE2/T1.txt").read()

while nubr1 <=5:
    lib1l[nubr1] = open("C:/DsE2/lib001.txt").readlines()[nubr1]
    lib2l[nubr1] = open("C:/DsE2/lib002.txt").readlines()[nubr1]
    s = s.replace( lib1l[nubr1] ,lib2l[nubr1] )
    nubr1 = nubr1 + 1


f = open("C:/DsE2/T1.txt", 'w')
f.write(s)
f.close()

is this how you use brackets?

---How this program works---
reads C:/DsE2/lib002.txt,C:/DsE2/lib001.txt,C:/DsE2/T1.txt
replace words in C:/DsE2/T1.txt with line one in C:/DsE2/lib001.txt to line one in
C:/DsE2/lib002.txt then replaces words in C:/DsE2/T1.txt with line two in C:/DsE2/lib001.txt to line two in C:/DsE2/lib002.txt and soo on...
-------------------------------------------

[bvdet]

Brackets are tokens used as delimiters for lists, index of sequence types, and the slicing operator. I don't think your method will achieve the results you want. file method read() reads the entire file as one string. You could iterate on the file object (for line in fileObj:) and use file method next() on the other two files, so you could do whatever you need to line 1 of each file, then line 2 of each file, and so on.

[Thebuilderofdoom]

i don't know half of what you saying? please explain in a more simpler

[bvdet]

A list:

[1,2,3,4,]

An element of a list and string accessed by index:

>>> [1,2,3,4][1]
2
>>> '12345'[-1]
'5'
>>>

A slice of a sequence type (list, tuple, string)

>>> [1,2,3,4][1]
2
>>> '12345'[-1]
'5'
>>> [1,2,3,4][1:3]
[2, 3]
>>> '12345'[::-1]
'54321'
>>> '12345'[1:3]
'23'
>>>

Here's an example of reading two text files at the same time:

f1 = open("file1.txt")
f2 = open("file2.txt")
for line in f1:
    print line.strip()
    try:
        line2 = f2.next()
        print line2.strip()
    except StopIteration, e:
        print "Reached end of file 2"
        break

f1.close()
f2.close()

Of course, iteration will cease when the end of file 1 is reached, or the try/except block will catch the StopIteration exception raised by the next() method. Iteration on the file object in a for loop uses the next() method behind the scenes and catches the StopIteration exception.

[Thebuilderofdoom]

um... how come this would work then?

nubr1 = 0
s = open("C:/DsE2/T1.txt").read()
f = open("C:/DsE2/T1.txt", 'w')

while 1==1:
if nubr1 <=5:
lib1l+`nubr1` = open("C:/DsE2/lib001.txt").readlines()[nubr1]
lib2l+`nubr1` = open("C:/DsE2/lib002.txt").readlines()[nubr1]
s = s.replace( lib1l+`nubr1` ,`lib2l+nubr1` )
nubr1 = nubr1 + 1
f.write(s)
else:

f.close()

[bvdet]

You have no indentation in your code. How will you know what to replace in "T1.txt" if you read the entire file into a string? You cannot make an assignment like this:

lib1l+`nubr1` = ........

There is no need in reading lib001.txt and lib002.txt over and over again. Read each file once outside the while loop.

[Thebuilderofdoom]

so how you read once? then replace all?

[bvdet]

I am unsure what you are trying to accomplish. Could you be more specific, post a sample from the files and what the results are supposed to look like?

[Thebuilderofdoom]

ok here is what i am trying.. to do
Example:
lib001

hello
hi
how
are
you

lib002

:D
hello
:)
hi
o

Target File:Before

hi how are you?how's it going?hello?

Target File:After

hello :) o hi?hello's it going?:D

--Example--
get all lines in lib001 replaces it it with the lines in lib002 in the target file

[bvdet]

Now I understand what you are trying to do. Read file1 into a string as you did. Open the two data files and use readlines() to create two lists. Remember that the list elements will have newline characters that need to be stripped. Assuming the string is name s1 and the lists are s2List and s3List:

for i, word in enumerate(s2List):
    s1 = s1.replace(word.strip(), s3List[i].strip())

[Glenton]

#First create dictionary for replacements:
myD={}
L1=open("lib001")
L2=open("lib002")
for l1,l2 in zip(L1,L2):
    myD[l1.strip()]=l2.strip()
L1.close()
L2.close()
print myD

Gives this:
{'how': ':)', 'you': 'o', 'hi': 'hello', 'hello': ':D', 'are': 'hi'}

#Next get the text you want to replace
T1=open("T1.txt","r")  #read only mode
mytxt=T1.readline().strip()
T1.close()
print mytxt

Gives this:
hi how are you?how's it going?hello?

#Thirdly, do replaces on the text
for t1 in myD:
    mytxt=mytxt.replace(t1,myD[t1])
print mytxt

Gives this:
:D :) hi o?:)'s it going?:D?
(NOTE: this may not work properly because it might substitute hi for hello, and then hello for :D - this can be fixed by using two lists instead of a dictionary so that you can control the order of substitution)

#Finally, write the new text to file
T2=open("T2.txt","w")  #write mode
T2.write(mytxt)
T2.close()

This creates a file called T2.txt with :D :) hi o?:)'s it going?:D? as the content. Of course, you could just use T1.txt if you wanted to over-write the original T1.txt file, but during the development phase that's probably not the best plan!

[Thebuilderofdoom]

um.... it breaks after around 100 lines in the lib001 and lib002

[Glenton]

It's possible that it would run out of memory at some point, but not after 100 lines. So they must have the same number of lines. And some characters might cause a problem, I guess.

"it breaks" is, I'm afraid, simply woefully inadequate. My program wasn't trying to solve it for you, but rather to show you a method for solving it yourself. If you'd like help debugging, please post the issue.

[Thebuilderofdoom]

the lib001 and the lib002 both have 58112 words each(not together)
Error
<open file 'C:/DsE2/lib001.txt', mode 'r' at 0x010242F0>
<open file 'C:/DsE2/lib002.txt', mode 'r' at 0x010242F0>
and then when it put
L1=open("C:/DsE2/lib001.txt").re ad()
L2=open("C:/DsE2/lib002.txt").re ad()
it put rubbish into C:/DsE2/T2.txt

[bvdet]

Did Python raise an exception? Why did you execute file method read() on L1 and L2? That was not in Glenton's example nor mine.