removing numbers from string

[Thekid]

Hi.....if I have a long string of numbers, letters, symbols, how can I remove the numbers but put them aside for use later on in the code? Example of string:

e#pf3$@hzfvlkfs yx?1pdidasifkck yil@#6s0sod#9$u qwnb5u95f@0c9m0 99@tt?3

-Thanks

[bvdet]

If you have multiple strings to extract the digits, you can save them in a list. Otherwise, save the result by creating a single object reference. Example:

>>> s = 'e#pf3$@hzfvlkfsyx?1pdidasifkckyil@#6s0sod#9$uqwnb5 u95f@0c9m099@tt?3'
>>> sdigits = ''.join([letter for letter in s if letter.isdigit()])
>>> sdigits
'31609595090993'
>>>

[Thekid]

That works just fine :) Thank you I was trying some ''.join but couldn't get it right.

[Thekid]

I have one more question on this.....after I 'print sdigits' and get the numbers, I try to 'print s' and the numbers are still there. How can I get it to where the numbers are removed from the string so I have 2 separate lists, one containing the numbers and one containing whats left? I've tried things like:

s.replace
s.split
s.lstrip

I can get it to take away one number with s.replace("1"," ") but that's it. If I try to make it:
s.replace("('1' ,'2','3','4','5 ','6','7','8',' 9')", "")
it doesn't work.

[bvdet]

Do it the same way, but add Python keyword not.

>>> s = 'e#pf3$@hzfvlkfsyx?1pdidasifkckyil@#6s0sod#9$uqwnb5 u95f@0c9m099@tt?3'
>>> sdigits = ''.join([letter for letter in s if letter.isdigit()])
>>> severythingelse = ''.join([letter for letter in s if not letter.isdigit()])
>>> severythingelse
'e#pf$@hzfvlkfsyx?pdidasifkckyil@#ssod#$uqwnb uf@cm@tt?'
>>>

[Thekid]

Oh ok! Thanks again.