Sorting a list

[RC]

unsortedList = list(["XYZ","ABC"])

sortedList = unsortedList.so rt()
print sortedList


Why this return None?
How do I get return as ["ABC", "XYZ"]?

[Steve Holden]

Re: Sorting a list

RC wrote:

unsortedList = list(["XYZ","ABC"])
>
sortedList = unsortedList.so rt()
print sortedList
>
>
Why this return None?
How do I get return as ["ABC", "XYZ"]?

The list's .sort method returns None because it modifies the list
in-place, so after the call it is sorted. So you can either not assign
the list and use unsortedList (whose name now belies its sorted
condition) or you can use

sprtedList = sorted(unsorted List)

since the sorted() function returns a sorted copy of its argument.

regards
Steve
--
Steve Holden +1 571 484 6266 +1 800 494 3119
Holden Web LLC http://www.holdenweb.com/

[duncan smith]

Re: Sorting a list

RC wrote:

unsortedList = list(["XYZ","ABC"])
>
sortedList = unsortedList.so rt()
print sortedList
>
>
Why this return None?

Because the sort method sorts the list in place (and returns None).

How do I get return as ["ABC", "XYZ"]?

>>unsortedLis t = ["XYZ","ABC"]
>>unsortedList. sort()
>>unsortedLis t

['ABC', 'XYZ']

or if you want a distinct sorted list (leaving the original list unchanged)

>>unsortedLis t = ["XYZ","ABC"]
>>sortedList = sorted(unsorted List)
>>unsortedLis t

['XYZ', 'ABC']

>>sortedList

['ABC', 'XYZ']

>>>

Duncan