inspect feature

[Aaron \Castironpi\ Brady]

Hello,

The 'inspect' module has this method:

inspect.getargv alues(frame)

It takes a frame and returns the parameters used to call it, including
the locals as defined in the frame, as shown.

>>def f( a, b, d= None, *c, **e ):

.... import inspect
.... return inspect.getargv alues( inspect.current frame() )
....

>>f( 0, 1, 'abc', 'def', ( 3, 2 ), h= 'ghi' )

(['a', 'b', 'd'], 'c', 'e', {'a': 0, 'c': ('def', (3, 2)), 'b': 1,
'e': {'h': 'g
hi'}, 'd': 'abc', 'inspect': <module 'inspect' from 'C:\Programs
\Python26\lib\i n
spect.pyc'>})

However, if you wanted a decorator that examines the parameters to a
function, you're out of luck. By the time you have a frame, you're
already in the function.

Perhaps it would not be as common as something like 'join' for
example, or even the rest of the functions in 'inspect', but do you
think something similar to 'getargvalues' that accepted a function and
an argument list, and returned a dictionary mapping parameters to
values, could be useful?

[Bruno Desthuilliers]

Re: inspect feature

Aaron "Castironpi " Brady a écrit :

Hello,
>
The 'inspect' module has this method:
>
inspect.getargv alues(frame)
>
It takes a frame and returns the parameters used to call it, including
the locals as defined in the frame, as shown.
>

>>>def f( a, b, d= None, *c, **e ):

... import inspect
... return inspect.getargv alues( inspect.current frame() )
...

>>>f( 0, 1, 'abc', 'def', ( 3, 2 ), h= 'ghi' )

(['a', 'b', 'd'], 'c', 'e', {'a': 0, 'c': ('def', (3, 2)), 'b': 1,
'e': {'h': 'g
hi'}, 'd': 'abc', 'inspect': <module 'inspect' from 'C:\Programs
\Python26\lib\i n
spect.pyc'>})
>
However, if you wanted a decorator that examines the parameters to a
function, you're out of luck. By the time you have a frame, you're
already in the function.

Hem...

def decorator(func) :
def _decorator(*arg s, *kw):
print "func args are ", *args, **kw
return func(*args, **kw)
return _decorator

[Aaron \Castironpi\ Brady]

Re: inspect feature

On Oct 9, 3:48 am, Bruno Desthuilliers <bruno.
42.desthuilli.. .@websiteburo.i nvalidwrote:

Aaron "Castironpi " Brady a écrit :
>
>
>

Hello,

>

The 'inspect' module has this method:

>

inspect.getargv alues(frame)

>

It takes a frame and returns the parameters used to call it, including
the locals as defined in the frame, as shown.

>

>>def f( a, b, d= None, *c, **e ):

...     import inspect
...     return inspect.getargv alues( inspect.current frame() )
...

>>f( 0, 1, 'abc', 'def', ( 3, 2 ), h= 'ghi' )

(['a', 'b', 'd'], 'c', 'e', {'a': 0, 'c': ('def', (3, 2)), 'b': 1,
'e': {'h': 'g
hi'}, 'd': 'abc', 'inspect': <module 'inspect' from 'C:\Programs
\Python26\lib\i n
spect.pyc'>})

>

However, if you wanted a decorator that examines the parameters to a
function, you're out of luck.  By the time you have a frame, you're
already in the function.

>
Hem...
>
def decorator(func) :
     def _decorator(*arg s, *kw):
         print "func args are ", *args, **kw
         return func(*args, **kw)
     return _decorator

It is less of a problem without tuple unpacking, but you still have
code like:

if len( args )>= 2:
b= args[ 1 ]
else:
try:
b= (somehow check b's default val.)
except NoDefaultVal:
raise ArgumentError

Worse yet, you have it for each parameter. Unless I missed something,
this is the only way to mimic/recreate the signature of the decoratee.

[Bruno Desthuilliers]

Re: inspect feature

Aaron "Castironpi " Brady a écrit :

On Oct 9, 3:48 am, Bruno Desthuilliers <bruno.
42.desthuilli.. .@websiteburo.i nvalidwrote:

>Aaron "Castironpi " Brady a écrit :
>>
>>
>>

>>Hello,
>>The 'inspect' module has this method:
>>inspect.getar gvalues(frame)
>>It takes a frame and returns the parameters used to call it, including
>>the locals as defined in the frame, as shown.
>>>>>def f( a, b, d= None, *c, **e ):
>>... import inspect
>>... return inspect.getargv alues( inspect.current frame() )
>>...
>>>>>f( 0, 1, 'abc', 'def', ( 3, 2 ), h= 'ghi' )
>>(['a', 'b', 'd'], 'c', 'e', {'a': 0, 'c': ('def', (3, 2)), 'b': 1,
>>'e': {'h': 'g
>>hi'}, 'd': 'abc', 'inspect': <module 'inspect' from 'C:\Programs
>>\Python26\lib \in
>>spect.pyc'> })
>>However, if you wanted a decorator that examines the parameters to a
>>function, you're out of luck. By the time you have a frame, you're
>>already in the function.

>Hem...
>>
>def decorator(func) :
> def _decorator(*arg s, *kw):
> print "func args are ", *args, **kw
> return func(*args, **kw)
> return _decorator

>
It is less of a problem without tuple unpacking, but you still have
code like:
>
if len( args )>= 2:
b= args[ 1 ]
else:
try:
b= (somehow check b's default val.)
except NoDefaultVal:
raise ArgumentError
>
Worse yet, you have it for each parameter. Unless I missed something,
this is the only way to mimic/recreate the signature of the decoratee.

I don't get what you're after ??? The decorator has full access to both
the actual params *and* the function's signature (via
inspect.getargs pec). So your initial question "if you wanted a decorator
that examines the parameters to a function" seems fully answered. You
will indeed have to write a couple lines of code if you want the same
formating as the one you'd get with inspect.current frame(), but what ?

FWIW, Michele Simionato's decorator module has some trick to allow for
signature-preserving decorators, so you may want to have a look - but
I'm not sure if this would solve your problem - at least in a sane way.

[Aaron \Castironpi\ Brady]

Re: inspect feature

On Oct 10, 3:36 am, Bruno Desthuilliers <bruno.
42.desthuilli.. .@websiteburo.i nvalidwrote:

Aaron "Castironpi " Brady a écrit :
>
>
>

On Oct 9, 3:48 am, Bruno Desthuilliers <bruno.
42.desthuilli.. .@websiteburo.i nvalidwrote:

Aaron "Castironpi " Brady a écrit :

>

>Hello,
>The 'inspect' module has this method:
>inspect.getarg values(frame)
>It takes a frame and returns the parameters used to call it, including
>the locals as defined in the frame, as shown.
>>>>def f( a, b, d= None, *c, **e ):
>...     import inspect
>...     return inspect.getargv alues( inspect.current frame() )
>...
>>>>f( 0, 1, 'abc', 'def', ( 3, 2 ), h= 'ghi' )
>(['a', 'b', 'd'], 'c', 'e', {'a': 0, 'c': ('def', (3, 2)), 'b': 1,
>'e': {'h': 'g
>hi'}, 'd': 'abc', 'inspect': <module 'inspect' from 'C:\Programs
>\Python26\lib\ in
>spect.pyc'>} )
>However, if you wanted a decorator that examines the parameters to a
>function, you're out of luck.  By the time you have a frame, you're
>already in the function.
Hem...

>

def decorator(func) :
     def _decorator(*arg s, *kw):
         print "func args are ", *args, **kw
         return func(*args, **kw)
     return _decorator

>

It is less of a problem without tuple unpacking, but you still have
code like:

>

if len( args )>= 2:
   b= args[ 1 ]
else:
   try:
      b= (somehow check b's default val.)
   except NoDefaultVal:
      raise ArgumentError

>

Worse yet, you have it for each parameter.  Unless I missed something,
this is the only way to mimic/recreate the signature of the decoratee.

>
I don't get what you're after ??? The decorator has full access to both
the actual params *and* the function's signature (via
inspect.getargs pec). So your initial question "if you wanted a decorator
that examines the parameters to a function" seems fully answered. You
will indeed have to write a couple lines of code if you want the same
formating as the one you'd get with inspect.current frame(), but what ?
>
FWIW, Michele Simionato's decorator module has some trick to allow for
signature-preserving decorators, so you may want to have a look - but
I'm not sure if this would solve your problem - at least in a sane way.

It's not exactly the next Millennium problem, but there are some
substantial checks you have to do on a per-parameter basis to see the
same thing that a function sees, when all you have is *args, **kwargs.

You are wrapping a function with this signature:

def f( a, b, c= None, *d, **e ):

You want to find out the values of 'a', 'b', and 'c' in a decorator.
You have these calls:

f( 0, 1, 'abc', 'def', h= 'ghi' )
f( 0, 1 )
f( 0, 1, h= 'abc' )
f( 0, 1, 'abc', c= 'def' ) #raise TypeError: multiple values

How do you determine 'a', 'b', and 'c'?

[Gabriel Genellina]

Re: inspect feature

En Fri, 10 Oct 2008 14:18:53 -0300, Aaron "Castironpi " Brady
<castironpi@gma il.comescribió:

On Oct 10, 3:36 am, Bruno Desthuilliers <bruno.
42.desthuilli.. .@websiteburo.i nvalidwrote:

>I don't get what you're after ??? The decorator has full access to both
>the actual params *and* the function's signature (via
>inspect.getarg spec). So your initial question "if you wanted a decorator
>that examines the parameters to a function" seems fully answered. You
>will indeed have to write a couple lines of code if you want the same
>formating as the one you'd get with inspect.current frame(), but what ?
>>
>FWIW, Michele Simionato's decorator module has some trick to allow for
>signature-preserving decorators, so you may want to have a look - but
>I'm not sure if this would solve your problem - at least in a sane way.

>
It's not exactly the next Millennium problem, but there are some
substantial checks you have to do on a per-parameter basis to see the
same thing that a function sees, when all you have is *args, **kwargs.
>
You are wrapping a function with this signature:
>
def f( a, b, c= None, *d, **e ):
>
You want to find out the values of 'a', 'b', and 'c' in a decorator.
You have these calls:
>
f( 0, 1, 'abc', 'def', h= 'ghi' )
f( 0, 1 )
f( 0, 1, h= 'abc' )
f( 0, 1, 'abc', c= 'def' ) #raise TypeError: multiple values
>
How do you determine 'a', 'b', and 'c'?

I'm afraid you'll have to duplicate the logic described here:

http://docs.python.org/reference/expressions.html#id9

To my knowledge, there is no available Python code (in the stdlib or
something) that already does that.

--
Gabriel Genellina

[George Sakkis]

Re: inspect feature

On Oct 14, 3:06 am, "Gabriel Genellina" <gagsl-...@yahoo.com.a r>
wrote:

En Fri, 10 Oct 2008 14:18:53 -0300, Aaron "Castironpi " Brady
<castiro...@gma il.comescribió:
>
>
>

On Oct 10, 3:36 am, Bruno Desthuilliers <bruno.
42.desthuilli.. .@websiteburo.i nvalidwrote:

I don't get what you're after ??? The decorator has full access to both
the actual params *and* the function's signature (via
inspect.getargs pec). So your initial question "if you wanted a decorator
that examines the parameters to a function" seems fully answered. You
will indeed have to write a couple lines of code if you want the same
formating as the one you'd get with inspect.current frame(), but what ?

>

FWIW, Michele Simionato's decorator module has some trick to allow for
signature-preserving decorators, so you may want to have a look - but
I'm not sure if this would solve your problem - at least in a sane way..

>

It's not exactly the next Millennium problem, but there are some
substantial checks you have to do on a per-parameter basis to see the
same thing that a function sees, when all you have is *args, **kwargs.

>

You are wrapping a function with this signature:

>

def f( a, b, c= None, *d, **e ):

>

You want to find out the values of 'a', 'b', and 'c' in a decorator.
You have these calls:

>

f( 0, 1, 'abc', 'def', h= 'ghi' )
f( 0, 1 )
f( 0, 1, h= 'abc' )
f( 0, 1, 'abc', c= 'def' ) #raise TypeError: multiple values

>

How do you determine 'a', 'b', and 'c'?

>
I'm afraid you'll have to duplicate the logic described here: http://docs.python.org/reference/expressions.html#id9
To my knowledge, there is no available Python code (in the stdlib or
something) that already does that.

I wrote such a beast some time ago; it's hairy but to the best of my
knowledge it seems to reproduce the standard Python logic:

http://code.activestate.com/recipes/551779/

George

[Aaron \Castironpi\ Brady]

Re: inspect feature

On Oct 14, 9:42 am, George Sakkis <george.sak...@ gmail.comwrote:

On Oct 14, 3:06 am, "Gabriel Genellina" <gagsl-...@yahoo.com.a r>
wrote:
>
>
>

En Fri, 10 Oct 2008 14:18:53 -0300, Aaron "Castironpi " Brady
<castiro...@gma il.comescribió:

>

On Oct 10, 3:36 am, Bruno Desthuilliers <bruno.
42.desthuilli.. .@websiteburo.i nvalidwrote:
>I don't get what you're after ??? The decorator has full access to both
>the actual params *and* the function's signature (via
>inspect.getarg spec). So your initial question "if you wanted a decorator
>that examines the parameters to a function" seems fully answered. You
>will indeed have to write a couple lines of code if you want the same
>formating as the one you'd get with inspect.current frame(), but what?

>

>FWIW, Michele Simionato's decorator module has some trick to allow for
>signature-preserving decorators, so you may want to have a look - but
>I'm not sure if this would solve your problem - at least in a sane way.

>

It's not exactly the next Millennium problem, but there are some
substantial checks you have to do on a per-parameter basis to see the
same thing that a function sees, when all you have is *args, **kwargs..

>

You are wrapping a function with this signature:

>

def f( a, b, c= None, *d, **e ):

>

You want to find out the values of 'a', 'b', and 'c' in a decorator.
You have these calls:

>

f( 0, 1, 'abc', 'def', h= 'ghi' )
f( 0, 1 )
f( 0, 1, h= 'abc' )
f( 0, 1, 'abc', c= 'def' ) #raise TypeError: multiple values

>

How do you determine 'a', 'b', and 'c'?

>

I'm afraid you'll have to duplicate the logic described here:  http://docs.python.org/reference/expressions.html#id9
To my knowledge, there is no available Python code (in the stdlib or
something) that already does that.

>
I wrote such a beast some time ago; it's hairy but to the best of my
knowledge it seems to reproduce the standard Python logic:http://code.activestate.com/recipes/551779/
>
George

I didn't see a 'got a duplicate argument for keyword "d"' error, but I
can add one if I need to.

Is there some reason why the built-in behavior should not be made
available, such as it's poorly defined outside the function? Or is it
just the fact that it's complicated that keeps it out of 'inspect'?

[George Sakkis]

Re: inspect feature

On Oct 14, 2:35 pm, "Aaron \"Castironpi \" Brady"
<castiro...@gma il.comwrote:

On Oct 14, 9:42 am, George Sakkis <george.sak...@ gmail.comwrote:
>
>
>

On Oct 14, 3:06 am, "Gabriel Genellina" <gagsl-...@yahoo.com.a r>
wrote:

>

En Fri, 10 Oct 2008 14:18:53 -0300, Aaron "Castironpi " Brady
<castiro...@gma il.comescribió:

>

On Oct 10, 3:36 am, Bruno Desthuilliers <bruno.
42.desthuilli.. .@websiteburo.i nvalidwrote:
I don't get what you're after ??? The decorator has full access toboth
the actual params *and* the function's signature (via
inspect.getargs pec). So your initial question "if you wanted a decorator
that examines the parameters to a function" seems fully answered. You
will indeed have to write a couple lines of code if you want the same
formating as the one you'd get with inspect.current frame(), but what ?

>

FWIW, Michele Simionato's decorator module has some trick to allowfor
signature-preserving decorators, so you may want to have a look - but
I'm not sure if this would solve your problem - at least in a saneway.

>

It's not exactly the next Millennium problem, but there are some
substantial checks you have to do on a per-parameter basis to see the
same thing that a function sees, when all you have is *args, **kwargs.

>

You are wrapping a function with this signature:

>

def f( a, b, c= None, *d, **e ):

>

You want to find out the values of 'a', 'b', and 'c' in a decorator..
You have these calls:

>

f( 0, 1, 'abc', 'def', h= 'ghi' )
f( 0, 1 )
f( 0, 1, h= 'abc' )
f( 0, 1, 'abc', c= 'def' ) #raise TypeError: multiple values

>

How do you determine 'a', 'b', and 'c'?

>

I'm afraid you'll have to duplicate the logic described here: http://docs.python.org/reference/expressions.html#id9
To my knowledge, there is no available Python code (in the stdlib or
something) that already does that.

>

I wrote such a beast some time ago; it's hairy but to the best of my
knowledge it seems to reproduce the standard Python logic:http://code.activestate.com/recipes/551779/

>

George

>
I didn't see a 'got a duplicate argument for keyword "d"' error, but I
can add one if I need to.

Why don't you try it out:

>>def f( a, b, c= None, *d, **e ): pass
>>getcallargs(f , 0, 1, 'abc', c= 'def' )

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
File "getcallargs.py ", line 53, in getcallargs
"argument '%s'" % (f_name,arg))
TypeError: f() got multiple values for keyword argument 'c'

George