Problem occured while sending mail

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  • sui
    #1

    Problem occured while sending mail

    this is my code

    import sys, os, glob, datetime, time
    import smtplib
    ## Parameters for SMTP session
    port=587
    SMTPserver= 'smtp.gmail.com '
    SMTPuser= '...@gmail.com'
    pw= 'fill in here'
    SENDER= SMTPuser

    ## Message details
    FROM= SENDER
    TO= 'notgm...@a.com '
    CC=FROM
    ##RECEIVERS= (TO, CC) ##proper way to send to both TO and CC
    RECEIVERS= (TO,) ## ignore the CC address

    subject= 'Test 1a'
    message='*** Email test *** '

    print 'Starting SMTP mail session on %s as %s ' %
    (SMTPserver,SMT Puser)
    session = smtplib.SMTP(SM TPserver,port)
    session.set_deb uglevel(0) # set debug level to 1 to see details
    session.ehlo(SM TPuser) # say hello
    session.starttl s() # TLS needed
    session.ehlo(SM TPuser) # say hello again, not sure why
    session.login(S MTPuser, pw)

    ##Create HEADER + MESSAGE
    HEADER= 'From: %s\r\n' % FROM
    HEADER= HEADER + 'To: %s\r\n' % TO
    HEADER= HEADER + 'Cc: %s\r\n' % CC
    HEADER= HEADER + 'Subject: %s\r\n' % subject
    BODY= HEADER + '\r\n' + message
    print BODY

    SMTPresult = session.sendmai l(SENDER, RECEIVERS, BODY) ## send email

    session.close()

    Now when i run this .py file...as python mail.py
    i can see only statement
    starting smtp mail......n details
    then nothing on screen after few minutes or after pressing ctrl +c
    Traceback (most recent call last):
    File "mail4.py", line 21, in <module>
    session = smtplib.SMTP(SM TPserver,port)
    File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
    (code, msg) = self.connect(ho st, port)
    File "/usr/local/lib/python2.5/smtplib.py", line 301, in connect
    self.sock.conne ct(sa)
    File "<string>", line 1, in connect
    or may be conncetion time out

    wats the solution for this
    Tags: None
    • sui
      #2
      Re: Problem occured while sending mail

      On Sep 17, 5:04 pm, sui <gogtesuy...@gm ail.comwrote:
      this is my code
      >
      import sys, os, glob, datetime, time
      import smtplib
      ## Parameters for SMTP session
      port=587
      SMTPserver= 'smtp.gmail.com '
      SMTPuser= '...@gmail.com'
      pw= 'fill in here'
      SENDER= SMTPuser
      >
      ## Message details
      FROM= SENDER
      TO= 'notgm...@a.com '
      CC=FROM
      ##RECEIVERS= (TO, CC) ##proper way to send to both TO and CC
      RECEIVERS= (TO,) ## ignore the CC address
      >
      subject= 'Test 1a'
      message='*** Email test *** '
      >
      print 'Starting SMTP mail session on %s as %s ' %
      (SMTPserver,SMT Puser)
      session = smtplib.SMTP(SM TPserver,port)
      session.set_deb uglevel(0) # set debug level to 1 to see details
      session.ehlo(SM TPuser) # say hello
      session.starttl s() # TLS needed
      session.ehlo(SM TPuser) # say hello again, not sure why
      session.login(S MTPuser, pw)
      >
      ##Create HEADER + MESSAGE
      HEADER= 'From: %s\r\n' % FROM
      HEADER= HEADER + 'To: %s\r\n' % TO
      HEADER= HEADER + 'Cc: %s\r\n' % CC
      HEADER= HEADER + 'Subject: %s\r\n' % subject
      BODY= HEADER + '\r\n' + message
      print BODY
      >
      SMTPresult = session.sendmai l(SENDER, RECEIVERS, BODY) ## send email
      >
      session.close()
      >
      Now when i run this .py file...as python mail.py
      i can see only statement
      starting smtp mail......n details
      then nothing on screen after few minutes or after pressing ctrl +c
      Traceback (most recent call last):
      File "mail4.py", line 21, in <module>
      session = smtplib.SMTP(SM TPserver,port)
      File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
      (code, msg) = self.connect(ho st, port)
      File "/usr/local/lib/python2.5/smtplib.py", line 301, in connect
      self.sock.conne ct(sa)
      File "<string>", line 1, in connect
      or may be conncetion time out
      >
      wats the solution for this
      if i dont press cntrl + c then it shows
      Starting SMTP mail session on smtp.gmail.com as gogtesuyash@gma il.com
      Traceback (most recent call last):
      File "mail4.py", line 21, in <module>
      session = smtplib.SMTP(SM TPserver,port)
      File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
      (code, msg) = self.connect(ho st, port)
      File "/usr/local/lib/python2.5/smtplib.py", line 310, in connect
      raise socket.error, msg
      socket.error: (110, 'Connection timed out')

      plz help me its urgent.....i want to complete it as early as possible

        Comment

        • Peter Pearson
          #3
          Re: Problem occured while sending mail

          On Wed, 17 Sep 2008 05:28:05 -0700 (PDT), sui <gogtesuyash@gm ail.comwrote:
          On Sep 17, 5:04 pm, sui <gogtesuy...@gm ail.comwrote:
          >this is my code
          >>
          >import sys, os, glob, datetime, time
          >import smtplib
          >## Parameters for SMTP session
          >port=587
          >SMTPserver= 'smtp.gmail.com '
          >SMTPuser= '...@gmail.com'
          >pw= 'fill in here'
          >SENDER= SMTPuser
          >>
          >## Message details
          >FROM= SENDER
          >TO= 'notgm...@a.com '
          >CC=FROM
          >##RECEIVERS= (TO, CC) ##proper way to send to both TO and CC
          >RECEIVERS= (TO,) ## ignore the CC address
          >>
          >subject= 'Test 1a'
          >message='*** Email test *** '
          >>
          >print 'Starting SMTP mail session on %s as %s ' %
          >(SMTPserver,SM TPuser)
          >session = smtplib.SMTP(SM TPserver,port)
          >session.set_de buglevel(0) # set debug level to 1 to see details
          >session.ehlo(S MTPuser) # say hello
          >session.startt ls() # TLS needed
          >session.ehlo(S MTPuser) # say hello again, not sure why
          >session.login( SMTPuser, pw)
          >>
          >##Create HEADER + MESSAGE
          >HEADER= 'From: %s\r\n' % FROM
          >HEADER= HEADER + 'To: %s\r\n' % TO
          >HEADER= HEADER + 'Cc: %s\r\n' % CC
          >HEADER= HEADER + 'Subject: %s\r\n' % subject
          >BODY= HEADER + '\r\n' + message
          >print BODY
          >>
          >SMTPresult = session.sendmai l(SENDER, RECEIVERS, BODY) ## send email
          >>
          >session.close( )
          >>
          >Now when i run this .py file...as python mail.py
          >i can see only statement
          >starting smtp mail......n details
          >then nothing on screen after few minutes or after pressing ctrl +c
          >Traceback (most recent call last):
          > File "mail4.py", line 21, in <module>
          > session = smtplib.SMTP(SM TPserver,port)
          > File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
          > (code, msg) = self.connect(ho st, port)
          > File "/usr/local/lib/python2.5/smtplib.py", line 301, in connect
          > self.sock.conne ct(sa)
          > File "<string>", line 1, in connect
          >or may be conncetion time out
          >>
          >wats the solution for this
          >
          if i dont press cntrl + c then it shows
          Starting SMTP mail session on smtp.gmail.com as gogtesuyash@gma il.com
          Traceback (most recent call last):
          File "mail4.py", line 21, in <module>
          session = smtplib.SMTP(SM TPserver,port)
          File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
          (code, msg) = self.connect(ho st, port)
          File "/usr/local/lib/python2.5/smtplib.py", line 310, in connect
          raise socket.error, msg
          socket.error: (110, 'Connection timed out')
          >
          plz help me its urgent.....i want to complete it as early as possible
          I pasted your code into a file named temp.py,
          and (perhaps superstitiously ) added a backslash to this line:
          >print 'Starting SMTP mail session on %s as %s ' %
          Here's what it does (long line wrapped manually):

          peter@eleodes:~ $ python temp.py
          Starting SMTP mail session on smtp.gmail.com as ...@gmail.com
          Traceback (most recent call last):
          File "temp.py", line 27, in ?
          session.login(S MTPuser, pw)
          File "/usr/lib/python2.4/smtplib.py", line 591, in login
          raise SMTPAuthenticat ionError(code, resp)
          smtplib.SMTPAut henticationErro r: (535, \
          '5.7.1 Username and Password not accepted. Learn more at\n' \
          '5.7.1 http://mail.google.com/support/bin/answer.py?answe r=' \
          '14257 a8sm34686663poa .12')
          peter@eleodes:~ $

          This indicates that it got much farther than when you ran it, since
          your timeout message comes from the smtplib.SMTP call several lines
          before the session.login call.

          As a simple connectivity test, you might see whether you can connect
          using telnet:

          peter@eleodes:~ $ telnet smtp.gmail.com 587
          Trying 72.14.253.109.. .
          Connected to gmail-smtp.l.google.c om.
          Escape character is '^]'.
          220 mx.google.com ESMTP m27sm34789033po f.6
          ^]c

          telnetc
          Connection closed.
          peter@eleodes:~ $

          --
          To email me, substitute nowhere->spamcop, invalid->net.

            Comment

            • sui
              #4
              Re: Problem occured while sending mail

              On Sep 17, 8:04 pm, Peter Pearson <ppear...@nowhe re.invalidwrote :
              On Wed, 17 Sep 2008 05:28:05 -0700 (PDT), sui <gogtesuy...@gm ail.comwrote:
              On Sep 17, 5:04 pm, sui <gogtesuy...@gm ail.comwrote:
              this is my code
              >
              import sys, os, glob, datetime, time
              import smtplib
              ## Parameters for SMTP session
              port=587
              SMTPserver= 'smtp.gmail.com '
              SMTPuser= '...@gmail.com'
              pw= 'fill in here'
              SENDER= SMTPuser
              >
              ## Message details
              FROM= SENDER
              TO= 'notgm...@a.com '
              CC=FROM
              ##RECEIVERS= (TO, CC) ##proper way to send to both TO and CC
              RECEIVERS= (TO,) ## ignore the CC address
              >
              subject= 'Test 1a'
              message='*** Email test *** '
              >
              print 'Starting SMTP mail session on %s as %s ' %
              (SMTPserver,SMT Puser)
              session = smtplib.SMTP(SM TPserver,port)
              session.set_deb uglevel(0) # set debug level to 1 to see details
              session.ehlo(SM TPuser) # say hello
              session.starttl s() # TLS needed
              session.ehlo(SM TPuser) # say hello again, not sure why
              session.login(S MTPuser, pw)
              >
              ##Create HEADER + MESSAGE
              HEADER= 'From: %s\r\n' % FROM
              HEADER= HEADER + 'To: %s\r\n' % TO
              HEADER= HEADER + 'Cc: %s\r\n' % CC
              HEADER= HEADER + 'Subject: %s\r\n' % subject
              BODY= HEADER + '\r\n' + message
              print BODY
              >
              SMTPresult = session.sendmai l(SENDER, RECEIVERS, BODY) ## send email
              >
              session.close()
              >
              Now when i run this .py file...as python mail.py
              i can see only statement
              starting smtp mail......n details
              then nothing on screen after few minutes or after pressing ctrl +c
              Traceback (most recent call last):
              File "mail4.py", line 21, in <module>
              session = smtplib.SMTP(SM TPserver,port)
              File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
              (code, msg) = self.connect(ho st, port)
              File "/usr/local/lib/python2.5/smtplib.py", line 301, in connect
              self.sock.conne ct(sa)
              File "<string>", line 1, in connect
              or may be conncetion time out
              >
              wats the solution for this
              >
              if i dont press cntrl + c then it shows
              Starting SMTP mail session on smtp.gmail.com as gogtesuy...@gma il.com
              Traceback (most recent call last):
              File "mail4.py", line 21, in <module>
              session = smtplib.SMTP(SM TPserver,port)
              File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
              (code, msg) = self.connect(ho st, port)
              File "/usr/local/lib/python2.5/smtplib.py", line 310, in connect
              raise socket.error, msg
              socket.error: (110, 'Connection timed out')
              >
              plz help me its urgent.....i want to complete it as early as possible
              >
              I pasted your code into a file named temp.py,
              and (perhaps superstitiously ) added a backslash to this line:
              >
              print 'Starting SMTP mail session on %s as %s ' %
              >
              Here's what it does (long line wrapped manually):
              >
              peter@eleodes:~ $ python temp.py
              Starting SMTP mail session on smtp.gmail.com as ....@gmail.com
              Traceback (most recent call last):
              File "temp.py", line 27, in ?
              session.login(S MTPuser, pw)
              File "/usr/lib/python2.4/smtplib.py", line 591, in login
              raise SMTPAuthenticat ionError(code, resp)
              smtplib.SMTPAut henticationErro r: (535, \
              '5.7.1 Username and Password not accepted. Learn more at\n' \
              '5.7.1http://mail.google.com/support/bin/answer.py?answe r='\
              '14257 a8sm34686663poa .12')
              peter@eleodes:~ $
              >
              This indicates that it got much farther than when you ran it, since
              your timeout message comes from the smtplib.SMTP call several lines
              before the session.login call.
              >
              As a simple connectivity test, you might see whether you can connect
              using telnet:
              >
              peter@eleodes:~ $ telnet smtp.gmail.com 587
              Trying 72.14.253.109.. .
              Connected to gmail-smtp.l.google.c om.
              Escape character is '^]'.
              220 mx.google.com ESMTP m27sm34789033po f.6
              ^]c
              >
              telnetc
              Connection closed.
              peter@eleodes:~ $
              >
              --
              To email me, substitute nowhere->spamcop, invalid->net.
              Actually i m working at place where proxy server has been
              working......so is it problem caused by that proxy server..peter thnks
              for suggestion but still its not working......

                Comment

                • sui
                  #5
                  Re: Problem occured while sending mail

                  On Sep 17, 8:04 pm, Peter Pearson <ppear...@nowhe re.invalidwrote :
                  On Wed, 17 Sep 2008 05:28:05 -0700 (PDT), sui <gogtesuy...@gm ail.comwrote:
                  On Sep 17, 5:04 pm, sui <gogtesuy...@gm ail.comwrote:
                  this is my code
                  >
                  import sys, os, glob, datetime, time
                  import smtplib
                  ## Parameters for SMTP session
                  port=587
                  SMTPserver= 'smtp.gmail.com '
                  SMTPuser= '...@gmail.com'
                  pw= 'fill in here'
                  SENDER= SMTPuser
                  >
                  ## Message details
                  FROM= SENDER
                  TO= 'notgm...@a.com '
                  CC=FROM
                  ##RECEIVERS= (TO, CC) ##proper way to send to both TO and CC
                  RECEIVERS= (TO,) ## ignore the CC address
                  >
                  subject= 'Test 1a'
                  message='*** Email test *** '
                  >
                  print 'Starting SMTPmailsession on %s as %s ' %
                  (SMTPserver,SMT Puser)
                  session = smtplib.SMTP(SM TPserver,port)
                  session.set_deb uglevel(0) # set debug level to 1 to see details
                  session.ehlo(SM TPuser) # say hello
                  session.starttl s() # TLS needed
                  session.ehlo(SM TPuser) # say hello again, not sure why
                  session.login(S MTPuser, pw)
                  >
                  ##Create HEADER + MESSAGE
                  HEADER= 'From: %s\r\n' % FROM
                  HEADER= HEADER + 'To: %s\r\n' % TO
                  HEADER= HEADER + 'Cc: %s\r\n' % CC
                  HEADER= HEADER + 'Subject: %s\r\n' % subject
                  BODY= HEADER + '\r\n' + message
                  print BODY
                  >
                  SMTPresult = session.sendmai l(SENDER, RECEIVERS, BODY) ## send email
                  >
                  session.close()
                  >
                  Now when i run this .py file...as pythonmail.py
                  i can see only statement
                  starting smtpmail......n details
                  then nothing on screen after few minutes or after pressing ctrl +c
                  Traceback (most recent call last):
                  File "mail4.py", line 21, in <module>
                  session = smtplib.SMTP(SM TPserver,port)
                  File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
                  (code, msg) = self.connect(ho st, port)
                  File "/usr/local/lib/python2.5/smtplib.py", line 301, in connect
                  self.sock.conne ct(sa)
                  File "<string>", line 1, in connect
                  or may be conncetion time out
                  >
                  wats the solution for this
                  >
                  if i dont press cntrl + c then it shows
                  Starting SMTPmailsession on smtp.gmail.com as gogtesuy...@gma il.com
                  Traceback (most recent call last):
                  File "mail4.py", line 21, in <module>
                  session = smtplib.SMTP(SM TPserver,port)
                  File "/usr/local/lib/python2.5/smtplib.py", line 244, in __init__
                  (code, msg) = self.connect(ho st, port)
                  File "/usr/local/lib/python2.5/smtplib.py", line 310, in connect
                  raise socket.error, msg
                  socket.error: (110, 'Connection timed out')
                  >
                  plz help me its urgent.....i want to complete it as early as possible
                  >
                  I pasted your code into a file named temp.py,
                  and (perhaps superstitiously ) added a backslash to this line:
                  >
                  print 'Starting SMTPmailsession on %s as %s ' %
                  >
                  Here's what it does (long line wrapped manually):
                  >
                  peter@eleodes:~ $ python temp.py
                  Starting SMTPmailsession on smtp.gmail.com as ....@gmail.com
                  Traceback (most recent call last):
                  File "temp.py", line 27, in ?
                  session.login(S MTPuser, pw)
                  File "/usr/lib/python2.4/smtplib.py", line 591, in login
                  raise SMTPAuthenticat ionError(code, resp)
                  smtplib.SMTPAut henticationErro r: (535, \
                  '5.7.1 Username and Password not accepted. Learn more at\n' \
                  '5.7.1http://mail.google.com/support/bin/answer.py?answe r='\
                  '14257 a8sm34686663poa .12')
                  peter@eleodes:~ $
                  >
                  This indicates that it got much farther than when you ran it, since
                  your timeout message comes from the smtplib.SMTP call several lines
                  before the session.login call.
                  >
                  As a simple connectivity test, you might see whether you can connect
                  using telnet:
                  >
                  peter@eleodes:~ $ telnet smtp.gmail.com 587
                  Trying 72.14.253.109.. .
                  Connected to gmail-smtp.l.google.c om.
                  Escape character is '^]'.
                  220 mx.google.com ESMTP m27sm34789033po f.6
                  ^]c
                  >
                  telnetc
                  Connection closed.
                  peter@eleodes:~ $
                  >
                  --
                  To email me, substitute nowhere->spamcop, invalid->net.
                  even i couldnt connect using telnet....
                  msg comes host is down

                    Comment

                    • Peter Pearson
                      #6
                      Re: Problem occured while sending mail

                      On Wed, 17 Sep 2008 23:53:36 -0700 (PDT), sui <gogtesuyash@gm ail.comwrote:
                      On Sep 17, 8:04 pm, Peter Pearson <ppear...@nowhe re.invalidwrote :
                      >On Wed, 17 Sep 2008 05:28:05 -0700 (PDT), sui <gogtesuy...@gm ail.comwrote:
                      [snip]
                      socket.error: (110, 'Connection timed out')
                      [snip]
                      >As a simple connectivity test, you might see whether you can connect
                      >using telnet:
                      [snip]
                      even i couldnt connect using telnet....
                      msg comes host is down
                      Then your problem is a networking problem. I know even less about
                      networking than I know about Python. Can you ping the destination?
                      Perhaps tracepath or traceroute will help you find where your
                      messages are being refused. Perhaps you are trying to work through
                      an internet access provider (e.g., ISP) that doesn't allow direct
                      connections to remote mail servers.

                      If I might add a grouchy comment, you really should learn a
                      little about netiquette. When you don't bother to trim the
                      quoted context or even to punctuate your text, you broadcast
                      a conspicuous implication that you value your own time much
                      more than you value the time of the people whose help you're
                      soliciting, which is incongruous and insulting. A more
                      carefully presented request might have gotten a response
                      from someone more knowledgeable -- and less grouchy -- than
                      me.

                      --
                      To email me, substitute nowhere->spamcop, invalid->net.

                        Comment

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