problem with execv command

[dudeja.rajat@gmail.com]

Hi,

I'm facing problem with the execv command:

my command is :
os.execv(' C:\Program Files\Subversio n\bin\svn ', ( 'list', ' \"
http://subversion.stv.abc.com/svn/Eng \" ' ) )

The error I'm getting is :
OSError: [Errno 22] Invalid argument


I tried using a variable for http path but still I'm getting the same error

Please help.
--
Regards,
Rajat

[Diez B. Roggisch]

Re: problem with execv command

dudeja.rajat@gm ail.com wrote:

Hi,
>
I'm facing problem with the execv command:
>
my command is :
os.execv(' C:\Program Files\Subversio n\bin\svn ', ( 'list', ' \"
http://subversion.stv.abc.com/svn/Eng \" ' ) )
>
The error I'm getting is :
OSError: [Errno 22] Invalid argument
>
>
I tried using a variable for http path but still I'm getting the same
error
>
Please help.

You need to either escape the backslashes in your path using \\, or use
python raw string literals like this:

r"C:\foo"

or use forward-slashes, which windows accepts as well.

Diez