Printing the digits of an integer

[verbtim]

I want to write a simple function that prints the digits of an integer in reverse.
I think it could be done with the while loop, but I am not so sure.
I have tried this, but it didn't work.

def print_digits(n):
	n = abs(n)
	while n > 0:
		n = n % 10
		print n,

[jlm699]

In python % is the modulo operator... I'm not sure what you are trying here...

Here's how to reverse the digits of an integer using list comprehension:
[code=python]>>> def print_digits(n) :
... new_n = [lett for lett in str(n)]
... new_n.reverse()
... print ''.join(new_n)
...
>>> print_digits(13 6)
631
>>> [/code]

[jlm699]

Oh wait.. now I see what you were trying to do...
[code=python]
>>> def print_n(n):
... while n > 0:
... print n % 10,
... n = n / 10
...
>>> print_n(492)
2 9 4
>>> [/code]
Modulus 10 will give you the remainder but you want to integer divide by 10 each time to reduce the number another digit.

[verbtim]

Well, I am new to Python and I am reading this:

http://openbookproject.net/thinkCSpy/ch06.xhtml#auto16

so the exercise is number 8

def print_digits(n):
    """
      >>> print_digits(13789)
      9 8 7 3 1
      >>> print_digits(39874613)
      3 1 6 4 7 8 9 3
      >>> print_digits(213141)
      1 4 1 3 1 2
    """

Hope this helps!

[verbtim]

Thanks for the quick reply. I can now sleep in peace.