simple UnZip

Collapse
This topic is closed.
X
X
Collapse
 
  • Page of 1
  • Time
  • Show
Clear All
new posts
Previous template Next
  • noydb
    #1

    simple UnZip

    Can someone help me with this script, which I found posted elsewhere?
    I'm trying to figure out what is going on here so that I can alter it
    for my needs, but the lack of descriptive names is making it
    difficult. And, the script doesn't quite do anything worthwhile -- it
    unzips one file from a zipfile, not all files in a zipfile.

    ***
    import zipfile, os, sys, glob

    os.chdir("C:\\T emp")
    zips = glob.glob('*.zi p')

    for fzip in zips:
    if zipfile.is_zipf ile(fzip):
    print fzip," is a zip"
    z = zipfile.ZipFile (fzip,'r')
    lstName = z.namelist()
    sHgt = lstName[0]
    print "Unpacking",sHg t
    hgt = z.read(sHgt)
    fHgt = open(sHgt,'wb')
    fHgt.write(hgt)
    # fHgt.flush
    fHgt.close
    print "Finished"
    ***

    I changed it somewhat to
    &&&
    import zipfile, os, sys

    event_zip = ("C:\\Temp\\dat a4event.zip")

    z = zipfile.ZipFile (event_zip, 'r')

    zList = z.namelist()

    for zItem in zList:
    print "Unpacking",zIt em
    zRead = z.read(zItem)
    z1File = open(zItem,'wb' )
    z1File.write(zR ead)
    z1File.close
    print "Finished"
    &&&

    This works, but I want to be able to specify a different output
    location.

    The scenario is that the zip file will always be the same (gets copied
    over daily), but it needs to be unzipped to a specific different
    directory.

    Can anyone help?

    Thanks!
    Tags: None
    • oj
      #2
      Re: simple UnZip

      On Jul 2, 2:39 pm, noydb <jenn.du...@gma il.comwrote:
      Can someone help me with this script, which I found posted elsewhere?
      I'm trying to figure out what is going on here so that I can alter it
      for my needs, but the lack of descriptive names is making it
      difficult.  And, the script doesn't quite do anything worthwhile -- it
      unzips one file from a zipfile, not all files in a zipfile.
      >
      ***
      import zipfile, os, sys, glob
      >
      os.chdir("C:\\T emp")
      zips = glob.glob('*.zi p')
      >
      for fzip in zips:
          if zipfile.is_zipf ile(fzip):
              print fzip," is a zip"
              z = zipfile.ZipFile (fzip,'r')
              lstName = z.namelist()
              sHgt = lstName[0]
              print "Unpacking",sHg t
              hgt = z.read(sHgt)
              fHgt = open(sHgt,'wb')
              fHgt.write(hgt)
              # fHgt.flush
              fHgt.close
      print "Finished"
      ***
      >
      I changed it somewhat to
      &&&
      import zipfile, os, sys
      >
      event_zip = ("C:\\Temp\\dat a4event.zip")
      >
      z = zipfile.ZipFile (event_zip, 'r')
      >
      zList = z.namelist()
      >
      for zItem in zList:
          print "Unpacking",zIt em
          zRead = z.read(zItem)
          z1File = open(zItem,'wb' )
          z1File.write(zR ead)
          z1File.close
      print "Finished"
      &&&
      >
      This works, but I want to be able to specify a different output
      location.
      >
      The scenario is that the zip file will always be the same (gets copied
      over daily), but it needs to be unzipped to a specific different
      directory.
      >
      Can anyone help?
      >
      Thanks!
      Firstly, I'd recommend just reading the documentation for the zipfile
      module, it's fairly straight forwards.

      To write the files to a different location, just change this line:

      z1File = open(zItem,'wb' )

      This is where you're opening a file to write to.

      Try something like:

      z1File = open( os.path.join(ou tput_dir, zItem), 'wb')

      to write the files into the path specified in output_dir.

      You don't even have to save the files with the same names they have in
      the zipfile; you don't have to save the files at all. In one project
      I'm working on, I just read files from a zip file into memory and
      process them there.

        Comment

        • Chris
          #3
          Re: simple UnZip

          On Jul 2, 3:39 pm, noydb <jenn.du...@gma il.comwrote:
          Can someone help me with this script, which I found posted elsewhere?
          I'm trying to figure out what is going on here so that I can alter it
          for my needs, but the lack of descriptive names is making it
          difficult.  And, the script doesn't quite do anything worthwhile -- it
          unzips one file from a zipfile, not all files in a zipfile.
          >
          ***
          import zipfile, os, sys, glob
          >
          os.chdir("C:\\T emp")
          zips = glob.glob('*.zi p')
          >
          for fzip in zips:
              if zipfile.is_zipf ile(fzip):
                  print fzip," is a zip"
                  z = zipfile.ZipFile (fzip,'r')
                  lstName = z.namelist()
                  sHgt = lstName[0]
                  print "Unpacking",sHg t
                  hgt = z.read(sHgt)
                  fHgt = open(sHgt,'wb')
                  fHgt.write(hgt)
                  # fHgt.flush
                  fHgt.close
          print "Finished"
          ***
          >
          I changed it somewhat to
          &&&
          import zipfile, os, sys
          >
          event_zip = ("C:\\Temp\\dat a4event.zip")
          >
          z = zipfile.ZipFile (event_zip, 'r')
          >
          zList = z.namelist()
          >
          for zItem in zList:
              print "Unpacking",zIt em
              zRead = z.read(zItem)
              z1File = open(zItem,'wb' )
              z1File.write(zR ead)
              z1File.close
          print "Finished"
          &&&
          >
          This works, but I want to be able to specify a different output
          location.
          >
          The scenario is that the zip file will always be the same (gets copied
          over daily), but it needs to be unzipped to a specific different
          directory.
          >
          Can anyone help?
          >
          Thanks!
          Well, how is the output directory different ? Is it just a timestamp
          like 'YYYYMMDD' that obviously changes every day or is it named after
          the file used ? If it is timestamp style you can do

          import zipfile, os, sys, time

          folder_name = time.strftime(" %Y%m%d", time.localtime( time.time()))
          event_zip = ("C:\\Temp\\dat a4event.zip")

          z = zipfile.ZipFile (event_zip, 'r')

          zList = z.namelist()

          for zItem in zList:
          print "Unpacking",zIt em
          zRead = z.read(zItem)
          z1File = open(os.path.jo in(folder_name, zItem),'wb')
          z1File.write(zR ead)
          z1File.close
          print "Finished"

          That will create a folder in your current working directory with the
          name of todays date and unzip it there. This is just one example
          route.

            Comment

            • =?iso-8859-1?q?C=E9dric_Lucantis?=
              #4
              Re: simple UnZip

              Le Wednesday 02 July 2008 15:39:51 noydb, vous avez écrit :
              Can someone help me with this script, which I found posted elsewhere?
              I'm trying to figure out what is going on here so that I can alter it
              for my needs, but the lack of descriptive names is making it
              difficult. And, the script doesn't quite do anything worthwhile -- it
              unzips one file from a zipfile, not all files in a zipfile.
              >
              ***
              import zipfile, os, sys, glob
              >
              os.chdir("C:\\T emp")
              zips = glob.glob('*.zi p')
              >
              for fzip in zips:
              if zipfile.is_zipf ile(fzip):
              print fzip," is a zip"
              z = zipfile.ZipFile (fzip,'r')
              lstName = z.namelist()
              sHgt = lstName[0]
              print "Unpacking",sHg t
              hgt = z.read(sHgt)
              fHgt = open(sHgt,'wb')
              fHgt.write(hgt)
              # fHgt.flush
              fHgt.close
              print "Finished"
              ***
              >
              I changed it somewhat to
              &&&
              import zipfile, os, sys
              >
              event_zip = ("C:\\Temp\\dat a4event.zip")
              >
              z = zipfile.ZipFile (event_zip, 'r')
              >
              zList = z.namelist()
              >
              for zItem in zList:
              print "Unpacking",zIt em
              zRead = z.read(zItem)
              z1File = open(zItem,'wb' )
              z1File.write(zR ead)
              z1File.close
              namelist() returns a list of relative file names, so you can just put them
              anywhere you want with:

              zlFile = open(os.path.jo in(DESTDIR, zItem), 'wb')

              or change the current directory, but the first way should be preferred.
              print "Finished"
              &&&
              >
              This works, but I want to be able to specify a different output
              location.
              >
              --
              Cédric Lucantis

                Comment

                • noydb
                  #5
                  Re: simple UnZip

                  On Jul 2, 10:07 am, Cédric Lucantis <o...@no-log.orgwrote:
                  Le Wednesday 02 July 2008 15:39:51 noydb, vous avez écrit :
                  >
                  >
                  >
                  >
                  >
                  Can someone help me with this script, which I found posted elsewhere?
                  I'm trying to figure out what is going on here so that I can alter it
                  for my needs, but the lack of descriptive names is making it
                  difficult.  And, the script doesn't quite do anything worthwhile -- it
                  unzips one file from a zipfile, not all files in a zipfile.
                  >
                  ***
                  import zipfile, os, sys, glob
                  >
                  os.chdir("C:\\T emp")
                  zips = glob.glob('*.zi p')
                  >
                  for fzip in zips:
                      if zipfile.is_zipf ile(fzip):
                          print fzip," is a zip"
                          z = zipfile.ZipFile (fzip,'r')
                          lstName = z.namelist()
                          sHgt = lstName[0]
                          print "Unpacking",sHg t
                          hgt = z.read(sHgt)
                          fHgt = open(sHgt,'wb')
                          fHgt.write(hgt)
                          # fHgt.flush
                          fHgt.close
                  print "Finished"
                  ***
                  >
                  I changed it somewhat to
                  &&&
                  import zipfile, os, sys
                  >
                  event_zip = ("C:\\Temp\\dat a4event.zip")
                  >
                  z = zipfile.ZipFile (event_zip, 'r')
                  >
                  zList = z.namelist()
                  >
                  for zItem in zList:
                      print "Unpacking",zIt em
                      zRead = z.read(zItem)
                      z1File = open(zItem,'wb' )
                      z1File.write(zR ead)
                      z1File.close
                  >
                  namelist() returns a list of relative file names, so you can just put them
                  anywhere you want with:
                  >
                  zlFile = open(os.path.jo in(DESTDIR, zItem), 'wb')
                  >
                  or change the current directory, but the first way should be preferred.
                  >
                  print "Finished"
                  &&&
                  >
                  This works, but I want to be able to specify a different output
                  location.
                  >
                  --
                  Cédric Lucantis- Hide quoted text -
                  >
                  - Show quoted text -
                  Thanks everyone! I did read the help on zipfile. I know it was
                  simple, but for newbies, sometimes it just helps to see how it is done
                  and learn from that.

                    Comment

                    • MRAB
                      #6
                      Re: simple UnZip

                      On Jul 2, 3:07 pm, Cédric Lucantis <o...@no-log.orgwrote:
                      Le Wednesday 02 July 2008 15:39:51 noydb, vous avez écrit :
                      >
                      >
                      >
                      Can someone help me with this script, which I found posted elsewhere?
                      I'm trying to figure out what is going on here so that I can alter it
                      for my needs, but the lack of descriptive names is making it
                      difficult.  And, the script doesn't quite do anything worthwhile -- it
                      unzips one file from a zipfile, not all files in a zipfile.
                      >
                      ***
                      import zipfile, os, sys, glob
                      >
                      os.chdir("C:\\T emp")
                      zips = glob.glob('*.zi p')
                      >
                      for fzip in zips:
                          if zipfile.is_zipf ile(fzip):
                              print fzip," is a zip"
                              z = zipfile.ZipFile (fzip,'r')
                              lstName = z.namelist()
                              sHgt = lstName[0]
                              print "Unpacking",sHg t
                              hgt = z.read(sHgt)
                              fHgt = open(sHgt,'wb')
                              fHgt.write(hgt)
                              # fHgt.flush
                              fHgt.close
                      print "Finished"
                      ***
                      >
                      I changed it somewhat to
                      &&&
                      import zipfile, os, sys
                      >
                      event_zip = ("C:\\Temp\\dat a4event.zip")
                      >
                      z = zipfile.ZipFile (event_zip, 'r')
                      >
                      zList = z.namelist()
                      >
                      for zItem in zList:
                          print "Unpacking",zIt em
                          zRead = z.read(zItem)
                          z1File = open(zItem,'wb' )
                          z1File.write(zR ead)
                          z1File.close
                      It's not actually closing the file. It should be:

                      z1File.close()
                      >
                      namelist() returns a list of relative file names, so you can just put them
                      anywhere you want with:
                      >
                      zlFile = open(os.path.jo in(DESTDIR, zItem), 'wb')
                      >
                      or change the current directory, but the first way should be preferred.
                      >
                      print "Finished"
                      &&&
                      >
                      This works, but I want to be able to specify a different output
                      location.
                      >
                      --
                      Cédric Lucantis

                        Comment

                        Previous template Next
                        Working...