shorten this: if char in "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz":

[cirfu]

if char in "ABCDEFGHIJKLMN OPQRSTUVWXYZabc defghijklmnopqr stuvwxyz":

cant i write something like:
if char in "[A-Za-z]":

?

[Brian Victor]

Re: shorten this: if char in

cirfu wrote:

if char in "ABCDEFGHIJKLMN OPQRSTUVWXYZabc defghijklmnopqr stuvwxyz":
>
cant i write something like:
if char in "[A-Za-z]":

Either of the following should do what you want, without resorting to
regular expressions:

import string
if char in string.letters:

or

if char.isalpha():

--
Brian

[bruno.desthuilliers@gmail.com]

Re: shorten this: if char in "ABCDEFGHI JKLMNOPQRSTUVWX YZabcdefghijklm nopqrstuvwxyz&q uot;:

On 24 juin, 20:32, cirfu <circularf...@y ahoo.sewrote:

if char in "ABCDEFGHIJKLMN OPQRSTUVWXYZabc defghijklmnopqr stuvwxyz":
>
cant i write something like:
if char in "[A-Za-z]":
>

Nope. But there are other solutions. Here are two:

# 1
import string

if char in string.letters:
print "yay"

# 2
import re
exp = re.compile(r'[A-Za-z]')

if exp.match(char) :
print "yay"

[Guilherme Polo]

Re: shorten this: if char in

On Tue, Jun 24, 2008 at 3:47 PM, bruno.desthuill iers@gmail.com
<bruno.desthuil liers@gmail.com wrote:

On 24 juin, 20:32, cirfu <circularf...@y ahoo.sewrote:

>if char in "ABCDEFGHIJKLMN OPQRSTUVWXYZabc defghijklmnopqr stuvwxyz":
>>
>cant i write something like:
>if char in "[A-Za-z]":
>>

>
Nope. But there are other solutions. Here are two:
>
# 1
import string
>
if char in string.letters:
print "yay"
>
# 2
import re
exp = re.compile(r'[A-Za-z]')
>
if exp.match(char) :
print "yay"
>

Let me post another one, and longer:

if ord(somechar) in range(ord('A'), ord('Z') + 1) + range(ord('a'),
ord('z') + 1):
...


--
-- Guilherme H. Polo Goncalves

[Walter Cruz]

Re: shorten this: if char in

another way:

import string

if char in string.ascii_le tters:
print('hello buddy!')

[]'s
- Walter

[MRAB]

Re: shorten this: if char in &quot;ABCDEFGHI JKLMNOPQRSTUVWX YZabcdefghijklm nopqrstuvwxyz&q uot;:

On Jun 24, 7:59 pm, "Guilherme Polo" <ggp...@gmail.c omwrote:

On Tue, Jun 24, 2008 at 3:47 PM, bruno.desthuill i...@gmail.com
>
>
>
<bruno.desthuil li...@gmail.com wrote:

On 24 juin, 20:32, cirfu <circularf...@y ahoo.sewrote:

if char in "ABCDEFGHIJKLMN OPQRSTUVWXYZabc defghijklmnopqr stuvwxyz":

>

cant i write something like:
if char in "[A-Za-z]":

>

Nope. But there are other solutions. Here are two:

>

# 1
import string

>

if char in string.letters:
  print "yay"

>

# 2
import re
exp = re.compile(r'[A-Za-z]')

>

if exp.match(char) :
  print "yay"

>
Let me post another one, and longer:
>
if ord(somechar) in range(ord('A'), ord('Z') + 1) + range(ord('a'),
ord('z') + 1):
    ...
>

And another:

if 'A' <= somechar <= 'Z' or 'a' <= somechar <= 'z':
...

[John Machin]

Re: shorten this: if char in &quot;ABCDEFGHI JKLMNOPQRSTUVWX YZabcdefghijklm nopqrstuvwxyz&q uot;:

On Jun 25, 4:32 am, cirfu <circularf...@y ahoo.sewrote:

if char in "ABCDEFGHIJKLMN OPQRSTUVWXYZabc defghijklmnopqr stuvwxyz":
>
cant i write something like:
if char in "[A-Za-z]":

You can write that if you want to, but it's equivalent to
if char in "zaZa]-[":
i.e. it doesn't do what you want.

This gives the same reuslt as your original code, unaffected by
locale:

if "A" <= char <= "Z" or "a" <= char <= "z":

[s0suk3@gmail.com]

Re: shorten this: if char in &quot;ABCDEFGHI JKLMNOPQRSTUVWX YZabcdefghijklm nopqrstuvwxyz&q uot;:

On Jun 24, 5:36 pm, John Machin <sjmac...@lexic on.netwrote:

On Jun 25, 4:32 am, cirfu <circularf...@y ahoo.sewrote:
>

if char in "ABCDEFGHIJKLMN OPQRSTUVWXYZabc defghijklmnopqr stuvwxyz":

>

cant i write something like:
if char in "[A-Za-z]":

>
You can write that if you want to, but it's equivalent to
if char in "zaZa]-[":
i.e. it doesn't do what you want.
>
This gives the same reuslt as your original code, unaffected by
locale:
>
if "A" <= char <= "Z" or "a" <= char <= "z":

But doesn't that rely on the underlying character set? It's like
performing math on C char's (maybe that's what the interpreter does
internally?). If that's the case, using 'char.isalpha() ' or 'char in
string.letters' or regex's would be better.

[John Machin]

Re: shorten this: if char in &quot;ABCDEFGHI JKLMNOPQRSTUVWX YZabcdefghijklm nopqrstuvwxyz&q uot;:

On Jun 25, 9:06 am, s0s...@gmail.co m wrote:

On Jun 24, 5:36 pm, John Machin <sjmac...@lexic on.netwrote:
>

On Jun 25, 4:32 am, cirfu <circularf...@y ahoo.sewrote:

>

if char in "ABCDEFGHIJKLMN OPQRSTUVWXYZabc defghijklmnopqr stuvwxyz":

>

cant i write something like:
if char in "[A-Za-z]":

>

You can write that if you want to, but it's equivalent to
if char in "zaZa]-[":
i.e. it doesn't do what you want.

>

This gives the same reuslt as your original code, unaffected by
locale:

>

if "A" <= char <= "Z" or "a" <= char <= "z":

>
But doesn't that rely on the underlying character set?

Unless there is a Python implementation using EBCDIC, different
underlying character set that differs from ASCII in A..Z and a..z is
*not* a practical concern.

It's like
performing math on C char's (maybe that's what the interpreter does
internally?). If that's the case, using 'char.isalpha() ' or 'char in
string.letters' or regex's would be better.

You should be asking the OP what he really wants ... precisely those
letters? alphabetic, in what locale?

[Nick Craig-Wood]

Re: shorten this: if char in

Guilherme Polo <ggpolo@gmail.c omwrote:

Let me post another one, and longer:
>
if ord(somechar) in range(ord('A'), ord('Z') + 1) + range(ord('a'),
ord('z') + 1):
...

That is very inefficient! Every time it is run it creates two lists
then joins them then throws the whole lot away!

--
Nick Craig-Wood <nick@craig-wood.com-- http://www.craig-wood.com/nick