How to get full path to script?

[kj]

How can a script know its absolute path? (__file__ only gives the
path it was used to invoke the script.)

Basically, I'm looking for the Python equivalent of Perl's FindBin.

The point of all this is to make the scripts location the reference
point for the location of other files, as part of a self-contained
distribution.

TIA!

Kynn

--
NOTE: In my address everything before the first period is backwards;
and the last period, and everything after it, should be discarded.

[Mark Tolonen]

Re: How to get full path to script?


"kj" <socyl@987jk.co m.invalidwrote in message
news:g2h3do$74t $1@reader2.pani x.com...

>
>
>
How can a script know its absolute path? (__file__ only gives the
path it was used to invoke the script.)
>
Basically, I'm looking for the Python equivalent of Perl's FindBin.
>
The point of all this is to make the scripts location the reference
point for the location of other files, as part of a self-contained
distribution.
>
TIA!
>
Kynn
>
--
NOTE: In my address everything before the first period is backwards;
and the last period, and everything after it, should be discarded.

import os
print os.path.abspath (__file__)

-Mark

[kj]

Re: How to get full path to script?

In <Bu2dnUy5AvRQtd HVnZ2dnUVZ_tqdn Z2d@comcast.com "Mark Tolonen" <M8R-yfto6h@mailinat or.comwrites:

>import os
>print os.path.abspath (__file__)

Great. Thanks!

Kynn

--
NOTE: In my address everything before the first period is backwards;
and the last period, and everything after it, should be discarded.

[bukzor]

Re: How to get full path to script?

On Jun 8, 12:52 pm, kj <so...@987jk.co m.invalidwrote:

In <Bu2dnUy5AvRQtd HVnZ2dnUVZ_tqdn ...@comcast.com "Mark Tolonen" <M8R-yft....@mailina tor.comwrites:
>

import os
print os.path.abspath (__file__)

>
Great.  Thanks!
>
Kynn
>
--
NOTE: In my address everything before the first period is backwards;
and the last period, and everything after it, should be discarded.

Note that this doesn't quite work for symbolic links or compiled
scripts, depending on your requirements.

[Mike Driscoll]

Re: How to get full path to script?

On Mon, Jun 9, 2008 at 12:37 AM, bukzor <workitharder@g mail.comwrote:

On Jun 8, 12:52 pm, kj <so...@987jk.co m.invalidwrote:

>In <Bu2dnUy5AvRQtd HVnZ2dnUVZ_tqdn ...@comcast.com "Mark Tolonen" <M8R-yft...@mailinat or.comwrites:
>>

>import os
>print os.path.abspath (__file__)

>>
>Great. Thanks!
>>
>Kynn
>>
>--
>NOTE: In my address everything before the first period is backwards;
>and the last period, and everything after it, should be discarded.

>
Note that this doesn't quite work for symbolic links or compiled
scripts, depending on your requirements.
--

http://mail.python.org/mailman/listinfo/python-list

>

For my compiled scripts, I usually use this variation:

path = os.path.abspath (os.path.join(o s.path.dirname( sys.argv[0])))

It's always worked for me.

Mike

[kj]

Re: How to get full path to script?

In <mailman.228.12 13022580.1044.p ython-list@python.org "Mike Driscoll" <kyosohma@gmail .comwrites:

>For my compiled scripts, I usually use this variation:

>path = os.path.abspath (os.path.join(o s.path.dirname( sys.argv[0])))

Thanks. But why the os.path.join()? (BTW, I did read the docs
before posting, but they make no sense to me; they say that
os.path.join joins "one or more path components intelligently",
but what does it mean to join *one* component?)

Kynn

--
NOTE: In my address everything before the first period is backwards;
and the last period, and everything after it, should be discarded.

[Mike Driscoll]

Re: How to get full path to script?

On Mon, Jun 9, 2008 at 11:07 AM, kj <socyl@987jk.co m.invalidwrote:

In <mailman.228.12 13022580.1044.p ython-list@python.org "Mike Driscoll" <kyosohma@gmail .comwrites:
>

>>For my compiled scripts, I usually use this variation:

>

>>path = os.path.abspath (os.path.join(o s.path.dirname( sys.argv[0])))

>
Thanks. But why the os.path.join()? (BTW, I did read the docs
before posting, but they make no sense to me; they say that
os.path.join joins "one or more path components intelligently",
but what does it mean to join *one* component?)
>
Kynn
>
--
NOTE: In my address everything before the first period is backwards;
and the last period, and everything after it, should be discarded.
--

http://mail.python.org/mailman/listinfo/python-list

>

The idea of the join method is to create the path in an OS agnostic
fashion. Linux uses forward slashes and Windows uses backward slashes
to join the parts. The join method does this for you so you don't have
to.

I think in this case, if I had my program installed to

C:\Program Files\MyProgram

It would put the slashes in correctly for Windows. However, there are
ways to get the default program directory in Linux and then have the
os.path.join create the path correctly there too. That's the idea
anyway. Hopefully that isn't more confusing than what you read.

Mike

[Sebastian \lunar\ Wiesner]

Re: How to get full path to script?

Mike Driscoll <kyosohma@gmail .comat Montag 09 Juni 2008 18:20:

On Mon, Jun 9, 2008 at 11:07 AM, kj <socyl@987jk.co m.invalidwrote:

>In <mailman.228.12 13022580.1044.p ython-list@python.org "Mike Driscoll"
><kyosohma@gmai l.comwrites:
>>

>>>For my compiled scripts, I usually use this variation:

>>

>>>path = os.path.abspath (os.path.join(o s.path.dirname( sys.argv[0])))

>>
>Thanks. But why the os.path.join()? (BTW, I did read the docs
>before posting, but they make no sense to me; they say that
>os.path.join joins "one or more path components intelligently",
>but what does it mean to join *one* component?)
>>
>Kynn
>>
>--
>NOTE: In my address everything before the first period is backwards;
>and the last period, and everything after it, should be discarded.
>--
>http://mail.python.org/mailman/listinfo/python-list
>>

>
The idea of the join method is to create the path in an OS agnostic
fashion. Linux uses forward slashes and Windows uses backward slashes
to join the parts. The join method does this for you so you don't have
to.

I guess, you didn't get his point. He seems to be aware that os.path.join
creates a path from _multiple_ strings by joining them with the correct
separator used by the underlying platform.

But he was asking why one would invoke os.path.join on a _single_ string, as
you did in your example. I'm wondering about this, too. It doesn't make
sense to me. os.path.join doesn't convert existing separators to the
platform-specific ones. And even if it would, sys.argv[0] already contains
a correct path, so there is nothing that needs conversion. So why use it
with a _single_ argument? I'd appreciate an example, illustrating the use
of this ;)


--
Freedom is always the freedom of dissenters.
(Rosa Luxemburg)

[Mike Driscoll]

Re: How to get full path to script?

On Mon, Jun 9, 2008 at 12:42 PM, Sebastian lunar Wiesner
<basti.wiesner@ gmx.netwrote:

Mike Driscoll <kyosohma@gmail .comat Montag 09 Juni 2008 18:20:
>

>On Mon, Jun 9, 2008 at 11:07 AM, kj <socyl@987jk.co m.invalidwrote:

>>In <mailman.228.12 13022580.1044.p ython-list@python.org "Mike Driscoll"
>><kyosohma@gma il.comwrites:
>>>
>>>>For my compiled scripts, I usually use this variation:
>>>
>>>>path = os.path.abspath (os.path.join(o s.path.dirname( sys.argv[0])))
>>>
>>Thanks. But why the os.path.join()? (BTW, I did read the docs
>>before posting, but they make no sense to me; they say that
>>os.path.joi n joins "one or more path components intelligently",
>>but what does it mean to join *one* component?)
>>>
>>Kynn
>>>
>>--
>>NOTE: In my address everything before the first period is backwards;
>>and the last period, and everything after it, should be discarded.
>>--
>>http://mail.python.org/mailman/listinfo/python-list
>>>

>>
>The idea of the join method is to create the path in an OS agnostic
>fashion. Linux uses forward slashes and Windows uses backward slashes
>to join the parts. The join method does this for you so you don't have
>to.

>
I guess, you didn't get his point. He seems to be aware that os.path.join
creates a path from _multiple_ strings by joining them with the correct
separator used by the underlying platform.
>
But he was asking why one would invoke os.path.join on a _single_ string, as
you did in your example. I'm wondering about this, too. It doesn't make
sense to me. os.path.join doesn't convert existing separators to the
platform-specific ones. And even if it would, sys.argv[0] already contains
a correct path, so there is nothing that needs conversion. So why use it
with a _single_ argument? I'd appreciate an example, illustrating the use
of this ;)
>
>
--
Freedom is always the freedom of dissenters.
(Rosa Luxemburg)
--

http://mail.python.org/mailman/listinfo/python-list

>

Okay, basically the answer is that I'm kind of stupid. Months ago, the
users on the wxPython group were discussing this issue and one of them
posted that snippet of code to show how they worked around the issue.
I thought I'd try it and it worked great, although I couldn't really
follow what was happening at the time.

Looking at it now, there doesn't appear to be any reason for the
os.path.join part. I tried running one of my simple scripts with and
without it and they return the same string.

I apologize for propagating erroneous code.

Mike