I try to learn python thru solving some interisting problem, found
google trasure hunt,
write first program ( but cant find whats wrong).
# Unzip the archive, then process the resulting files to obtain a
numeric result. You'll be taking the sum of lines from files matching
a certain description, and multiplying those sums together to obtain a
final result. Note that files have many different extensions, like
'.pdf' and '.js', but all are plain text files containing a small
number of lines of text.
#
#Sum of line 5 for all files with path or name containing abc and
ending in .js
#Sum of line 5 for all files with path or name containing HIJ and
ending in .js
#Hint: If the requested line does not exist, do not increment the sum.
#
#Multiply all the above sums together and enter the product below.
#(Note: Answer must be an exact, decimal representation of the
number.)
import fnmatch
import os
def zbrojipl(patter n):
rootPath = ''
sum1=0
for root, dirs, files in os.walk(rootPat h):
for filename in files:
path=os.path.jo in(root, filename)
if fnmatch.fnmatch (path, pattern):
#print path
f=open(path)
redovi=f.readli nes()
#print len(redovi),red ovi
if len(redovi)>=5:
#print redovi[4] # index od 0 kao C
sum1=sum1+int(r edovi[4])
return sum1
print zbrojipl('*[abc]*.js')*zbrojipl ('*[HIJ]*.js')
google trasure hunt,
write first program ( but cant find whats wrong).
# Unzip the archive, then process the resulting files to obtain a
numeric result. You'll be taking the sum of lines from files matching
a certain description, and multiplying those sums together to obtain a
final result. Note that files have many different extensions, like
'.pdf' and '.js', but all are plain text files containing a small
number of lines of text.
#
#Sum of line 5 for all files with path or name containing abc and
ending in .js
#Sum of line 5 for all files with path or name containing HIJ and
ending in .js
#Hint: If the requested line does not exist, do not increment the sum.
#
#Multiply all the above sums together and enter the product below.
#(Note: Answer must be an exact, decimal representation of the
number.)
import fnmatch
import os
def zbrojipl(patter n):
rootPath = ''
sum1=0
for root, dirs, files in os.walk(rootPat h):
for filename in files:
path=os.path.jo in(root, filename)
if fnmatch.fnmatch (path, pattern):
#print path
f=open(path)
redovi=f.readli nes()
#print len(redovi),red ovi
if len(redovi)>=5:
#print redovi[4] # index od 0 kao C
sum1=sum1+int(r edovi[4])
return sum1
print zbrojipl('*[abc]*.js')*zbrojipl ('*[HIJ]*.js')
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