Accepting text input

[Collin]

I'm pretty new to Python, but this has really bugged me. I can't find a
way around it.


The problem is that, when I use raw_input("sajf asjdf") whatever, or
input("dsjfadsj fa"), you can only have numerical values as answers.

Any help would be appreciated. Thanks.

[Collin]

Re: Accepting text input

Collin wrote:

I'm pretty new to Python, but this has really bugged me. I can't find a
way around it.
>
>
The problem is that, when I use raw_input("sajf asjdf") whatever, or
input("dsjfadsj fa"), you can only have numerical values as answers.
>
Any help would be appreciated. Thanks.

Oh, wow. I feel so stupid. Please disregard this message. <_<

I read the error message just now a bit more carefully, and I tried
something. I tried defining "yes" as some random numerical value. Then
when I did:
(example code)

yes = 123123983 #some number
test = input("Test test test ")
if test == yes:
print "It worked."
else:
print "failed"

(example code off)

Collin

[Gabriel Genellina]

Re: Accepting text input

En Mon, 12 May 2008 01:54:28 -0300, Collin <collinyeung@sh aw.caescribió:

Collin wrote:

>I'm pretty new to Python, but this has really bugged me. I can't find a
>way around it.
>>
>>
>The problem is that, when I use raw_input("sajf asjdf") whatever, or
>input("dsjfads jfa"), you can only have numerical values as answers.
>>
>Any help would be appreciated. Thanks.

>
>
Oh, wow. I feel so stupid. Please disregard this message. <_<

No need to apologize...

I read the error message just now a bit more carefully, and I tried
something. I tried defining "yes" as some random numerical value. Then
when I did:
(example code)
>
yes = 123123983 #some number
test = input("Test test test ")
if test == yes:
print "It worked."
else:
print "failed"
>
(example code off)

The usual way for Python<3.0 is:

answer = raw_input("Test test test ").lower()
if answer == "yes":
...

The input() function evaluates user input as an expression: if he types 2+5 the input() function returns the integer 7. I would never use input() in a program - it's way too unsafe; use always raw_input instead.

--
Gabriel Genellina

[Collin]

Re: Accepting text input

Gabriel Genellina wrote:

En Mon, 12 May 2008 01:54:28 -0300, Collin <collinyeung@sh aw.caescribió:
>

>Collin wrote:

>>I'm pretty new to Python, but this has really bugged me. I can't find a
>>way around it.
>>>
>>>
>>The problem is that, when I use raw_input("sajf asjdf") whatever, or
>>input("dsjfad sjfa"), you can only have numerical values as answers.
>>>
>>Any help would be appreciated. Thanks.

>>
>Oh, wow. I feel so stupid. Please disregard this message. <_<

>
No need to apologize...
>

>I read the error message just now a bit more carefully, and I tried
>something. I tried defining "yes" as some random numerical value. Then
>when I did:
>(example code)
>>
>yes = 123123983 #some number
>test = input("Test test test ")
>if test == yes:
> print "It worked."
>else:
> print "failed"
>>
>(example code off)

>
The usual way for Python<3.0 is:
>
answer = raw_input("Test test test ").lower()
if answer == "yes":
...
>
The input() function evaluates user input as an expression: if he types 2+5 the input() function returns the integer 7. I would never use input() in a program - it's way too unsafe; use always raw_input instead.
>

If I use it like that, do I have to import anything to have the .lower()
work? And if I do, what does the .lower() signify?

[Kam-Hung Soh]

Re: Accepting text input

On Wed, 14 May 2008 11:02:36 +1000, Collin <collinyeung@sh aw.cawrote:

Gabriel Genellina wrote:

>En Mon, 12 May 2008 01:54:28 -0300, Collin <collinyeung@sh aw.ca
>escribió:
>>

>>Collin wrote:
>>>I'm pretty new to Python, but this has really bugged me. I can't find
>>>a
>>>way around it.
>>>>
>>>>
>>>The problem is that, when I use raw_input("sajf asjdf") whatever, or
>>>input("dsjfa dsjfa"), you can only have numerical values as answers.
>>>>
>>>Any help would be appreciated. Thanks.
>>>
>>Oh, wow. I feel so stupid. Please disregard this message. <_<

> No need to apologize...
>>

>>I read the error message just now a bit more carefully, and I tried
>>something. I tried defining "yes" as some random numerical value. Then
>>when I did:
>>(example code)
>>>
>>yes = 123123983 #some number
>>test = input("Test test test ")
>>if test == yes:
>> print "It worked."
>>else:
>> print "failed"
>>>
>>(example code off)

> The usual way for Python<3.0 is:
> answer = raw_input("Test test test ").lower()
>if answer == "yes":
> ...
> The input() function evaluates user input as an expression: if he
>types 2+5 the input() function returns the integer 7. I would never use
>input() in a program - it's way too unsafe; use always raw_input
>instead.
>>

>
If I use it like that, do I have to import anything to have the .lower()
work? And if I do, what does the .lower() signify?
--

http://mail.python.org/mailman/listinfo/python-list

>

You don't need to import any module to use ".lower()"; it is a method ofa
string. raw_input() returns a string, so you can use methods of a string.

Try the following statement to see what happens:
"ABCDE".low er()

--
Kam-Hung Soh <a href="http://kamhungsoh.com/blog">Software Salariman</a>

[Collin]

Re: Accepting text input

Kam-Hung Soh wrote:

On Wed, 14 May 2008 11:02:36 +1000, Collin <collinyeung@sh aw.cawrote:
>

>Gabriel Genellina wrote:

>>En Mon, 12 May 2008 01:54:28 -0300, Collin <collinyeung@sh aw.ca>
>>escribió:
>>>
>>>Collin wrote:
>>>>I'm pretty new to Python, but this has really bugged me. I can't
>>>>find a
>>>>way around it.
>>>>>
>>>>>
>>>>The problem is that, when I use raw_input("sajf asjdf") whatever, or
>>>>input("dsjf adsjfa"), you can only have numerical values as answers.
>>>>>
>>>>Any help would be appreciated. Thanks.
>>>>
>>>Oh, wow. I feel so stupid. Please disregard this message. <_<
>> No need to apologize...
>>>
>>>I read the error message just now a bit more carefully, and I tried
>>>something. I tried defining "yes" as some random numerical value. Then
>>>when I did:
>>>(example code)
>>>>
>>>yes = 123123983 #some number
>>>test = input("Test test test ")
>>>if test == yes:
>>> print "It worked."
>>>else:
>>> print "failed"
>>>>
>>>(example code off)
>> The usual way for Python<3.0 is:
>> answer = raw_input("Test test test ").lower()
>>if answer == "yes":
>> ...
>> The input() function evaluates user input as an expression: if he
>>types 2+5 the input() function returns the integer 7. I would never
>>use input() in a program - it's way too unsafe; use always raw_input
>>instead.
>>>

>>
>If I use it like that, do I have to import anything to have the
>.lower() work? And if I do, what does the .lower() signify?
>--
>http://mail.python.org/mailman/listinfo/python-list
>>

>
You don't need to import any module to use ".lower()"; it is a method of
a string. raw_input() returns a string, so you can use methods of a
string.
>
Try the following statement to see what happens:
"ABCDE".low er()
>

So the .lower() string method is just to convert the string to lowercase
letters so that you don't have to type a bunch of if - then statements
in both cases, I'm assuming?

[John Salerno]

Re: Accepting text input

On Thu, 15 May 2008 02:36:29 GMT
Collin <collinyeung@sh aw.cawrote:

So the .lower() string method is just to convert the string to lowercase
letters so that you don't have to type a bunch of if - then statements
in both cases, I'm assuming?

You can also type:

dir(str)

to get a list of all the methods you can call on a string object. If you see anything interesting, then type:

help(str.<metho d_name>) # e.g. help(str.split)

to find out how it works. :)

[Kam-Hung Soh]

Re: Accepting text input

On Thu, 15 May 2008 12:36:29 +1000, Collin <collinyeung@sh aw.cawrote:

Kam-Hung Soh wrote:

>On Wed, 14 May 2008 11:02:36 +1000, Collin <collinyeung@sh aw.cawrote:
>>

>>Gabriel Genellina wrote:
>>>En Mon, 12 May 2008 01:54:28 -0300, Collin <collinyeung@sh aw.ca
>>>escribió:
>>>>
>>>>Collin wrote:
>>>>>I'm pretty new to Python, but this has really bugged me. I can't
>>>>>find a
>>>>>way around it.
>>>>>>
>>>>>>
>>>>>The problem is that, when I use raw_input("sajf asjdf") whatever, or
>>>>>input("dsj fadsjfa"), you can only have numerical values as answers.
>>>>>>
>>>>>Any help would be appreciated. Thanks.
>>>>>
>>>>Oh, wow. I feel so stupid. Please disregard this message. <_<
>>> No need to apologize...
>>>>
>>>>I read the error message just now a bit more carefully, and I tried
>>>>something . I tried defining "yes" as some random numerical value.
>>>>Then
>>>>when I did:
>>>>(example code)
>>>>>
>>>>yes = 123123983 #some number
>>>>test = input("Test test test ")
>>>>if test == yes:
>>>> print "It worked."
>>>>else:
>>>> print "failed"
>>>>>
>>>>(example code off)
>>> The usual way for Python<3.0 is:
>>> answer = raw_input("Test test test ").lower()
>>>if answer == "yes":
>>> ...
>>> The input() function evaluates user input as an expression: if he
>>>types 2+5 the input() function returns the integer 7. I would never
>>>use input() in a program - it's way too unsafe; use always raw_input
>>>instead.
>>>>
>>>
>>If I use it like that, do I have to import anything to have the
>>.lower() work? And if I do, what does the .lower() signify?
>>-- http://mail.python.org/mailman/listinfo/python-list
>>>

> You don't need to import any module to use ".lower()"; it is a method
>of a string. raw_input() returns a string, so you can use methods ofa
>string.
> Try the following statement to see what happens:
>"ABCDE".lower( )
>>

>
So the .lower() string method is just to convert the string to lowercase
letters so that you don't have to type a bunch of if - then statements
in both cases, I'm assuming?
--

http://mail.python.org/mailman/listinfo/python-list

>

That's right. If you normalize your input to all lower case or upper
case, you make it easier to process user input.

Regards,

--
Kam-Hung Soh <a href="http://kamhungsoh.com/blog">Software Salariman</a>