Python Writing Output To Separate Files

[lqnt1981]

Following is the code in python that opens all files under a directories and puts a comma in place of whitespace, I can see the output on the command line, but I am not sure what to do in order to write the output of each file read in the directory into a separate file.
# whitespace by comma in every line

import fileinput, string, sys, os
from os.path import join


if len(sys.argv) != 2:
print "Enter: python %s input_directory " % os.path.basenam e(sys.argv[0])
sys.exit(0)

#Getting input from the command line
directory= sys.argv[1]

for root, dirs, files in os.walk(directo ry):
for name in files:
filename= os.path.join(ro ot,name)
file= open(filename, 'r')

#putting comma wherever there is occurence of whitespace in line
for line in file:
x= line.split()
str = ''
for i in x:
str+=(","+i)
str1= str.lstrip(',')

print( str1)
file.close()

Please make the changes to the above code so that if there r 3 files under the given directory it weill create 3 separate output files with the result stored in them.

[bvdet]

Please use code tags when posting code. The following will open a file, read each line, split each line into a list, rejoin the list with commas, then write the list to disk.
[code=Python]filename = 'input_file.txt '
outname = 'output_file.tx t'

f = open(filename)
lineList = [','.join(items) for items in [line.split() for line in f]]
f.close()

f = open(outname, 'w')
f.write('\n'.jo in(lineList))
f.close()[/code]