How do you find the days before a date with time() (RE-VISIT)

[raubana]

I tried making a program that tells me the time before a specifide date, but it's really hard! I tried one of the ways that a person sent me, but it doesn't work...

[jlm699]

You really need to read the posting guidelines (particularly 'How to Ask a Question'), as you consistently violate them.

What "doesn't work"? What did you try? You need to provide some semblance of information if you expect us to help you.

[kaarthikeyapreyan]

Hey try this if it suits your requirement
This will compute the number of days that has passed if the number of seconds or the date in dd/mm/yyyy format is given

import time
import string ,sys

class findtime:
    
    def __init__(self):

        self.secperday=86400
        self.uinput=raw_input("Enter the number of seconds or the format dd/mm/yyyy: ")
        
    def checktime(self):
        """
        Computations with epoch time working with dates after 1970
        """
        self.presentsec = time.time()
        self.pform= time.localtime()
        
        if '/' in self.uinput :
            frdate=string.split(self.uinput,'/')
            consdate = tuple([int(frdate[2]),int(frdate[1]),int(frdate[0]),self.pform[3],self.pform[4],self.pform[5],self.pform[6],self.pform[7],self.pform[8]])
            diff =   self.presentsec - (time.mktime(consdate))
            print "Number of seconds Passed %d" %diff
            print "Number of days passed %d"  % (diff/self.secperday)

        else :
            self.uinput =float(self.uinput)
            print ("Computation for %s seconds from present date" %self.uinput)
            self.expectedsec = self.presentsec - self.uinput
            self.expectedday=time.localtime(self.expectedsec)
            print ("Expected %d/%d/%d"%(self.expectedday[2],self.expectedday[1],self.expectedday[0]))
            diffdays =  int(round(self.uinput / self.secperday))
            print "Number of days passed %d"  % (diffdays)
            
if __name__=='__main__':
    
    obj = findtime()
    obj.checktime()

[bvdet]

It seems like I posted this before. It uses time and datetime.
[code=Python]import datetime, time

def convert_seconds (seconds):
hours = int(seconds/3600)
mins = int((seconds-hours*3600)/60)
secs = seconds-hours*3600-mins*60
return hours, mins, secs

present = datetime.dateti me.now()

print '''Calculate the difference between the present time and another
date, either past or future (present - other date).'''

dateStr = raw_input('Ente r the date (mm/dd/yyyy)')
timeObj = time.strptime(d ateStr, '%m/%d/%Y')
datetimeObj = datetime.dateti me(*timeObj[:6])
delta = present-datetimeObj
hours, mins, secs = convert_seconds (delta.seconds)

print 'The difference is %d day%s, %d hour%s, %d minute%s, and %d second%s.' % \
(delta.days, ['s', ''][abs(delta.days) ==1 or 0],\
hours, ['s', ''][abs(hours)==1 or 0],\
mins, ['s', ''][abs(mins)==1 or 0],\
secs, ['s', ''][abs(secs)==1 or 0])[/code]
[code=Python]>>> Calculate the difference between the present time and another
date, either past or future (present - other date).
The difference is -29 days, 8 hours, 35 minutes, and 19 seconds.
[/code]

[jlm699]

I tried one of the ways that a person sent me, but it doesn't work...

@bvdet: Yes you did provide him with this previously... He failed to elaborate why it didn't work however.

[raubana]

Yeah, I didn't explain why it didn't work before because I'm not sure why it didn't work... I do know, however, that the '('s, ')'s, '[' and the ']' may have been missing in some places.

Anyway, thanks for your help, guys! I'll try it out as soon as I can.