C function in a Python context

Re: C function in a Python context

#include <string>

#include <vector>

This modification required:

compilercommand = 'c:/programs/mingw/bin/g++'

and

strctypes= { 'i': 'int', 's': 'const char*',
'O': 'PyObject*' }

The output is:

#include <c:/programs/python/include/Python.h>

[ user code ]

static PyObject *
extcode_enumfac tors(PyObject *self, PyObject *args) {
PyObject* result;
int arg0;
const char* arg1;
PyArg_ParseTupl e(args, "is", &arg0, &arg1 );
result= enumfactors( arg0, arg1 );
return Py_BuildValue( "O", result );
}

static PyMethodDef ExtcodeMethods[] = {
{ "enumfactor s", extcode_enumfac tors, METH_VARARGS, "" },
{NULL, NULL, 0, NULL}
};

PyMODINIT_FUNC
initextcode(voi d) {
(void) Py_InitModule(" extcode", ExtcodeMethods) ;
}

The benefits are automatic parameter parsing and automatic method
table construction. The costs are portability and parameter parsing
flexibility. Add up.

To write quick C things that Python won't do up to speed. So it's got
a redundancy.

import ext
extA= ext.Ext()
extA[ 'enumfactors' ]= r"""
int enumfactors( int a, const char* sep ) {
int ret= 0, i;
for( i= 1; i<= a; i++ ) {
if( a% i== 0 ) {
ret+= 1;
if( i1 ) {
printf( "%s", sep );
}
printf( "%i", i );
}
}
printf( "\n" );
return ret;
}
""", ("i","i","s" )

factorsn= extA.enumfactor s( 209677683, ', ' )
print( "%i factors total."% factorsn )

import sys
sys.exit()


1, 3, 23, 69, 131, 393, 3013, 9039, 23197, 69591, 533531, 1600593,
3038807, 9116
421, 69892561, 209677683
16 factors total.