Need to split the number

[psbasha]

Hi,

I have a number ,i have to split it into 3 digits

For Example num = 001001001001000 001

After the split it should be

001
001
001
001
000
001
Is there any better way to split it

num = '00100100100100 0001'
x1 = num[0:3]
x2 = num[3:6]
x3 = num[6:9]
x4 = num[9:12]
x5 = num[12:15]
x6 = num[15:18]

Thanks
PSB

[ghostdog74]

Have you read the references?

>>> s='001001001001000001'
>>> import textwrap
>>> textwrap.wrap(s,3)
['001', '001', '001', '001', '000', '001']

You should really spend time reading up on Python docs because after 400+ posts, you should really be able to grasp the essence of Python.

[psbasha]

Have you read the references?

>>> s='001001001001000001'
>>> import textwrap
>>> textwrap.wrap(s,3)
['001', '001', '001', '001', '000', '001']

You should really spend time reading up on Python docs because after 400+ posts, you should really be able to grasp the essence of Python.

Thanks for the solution.

I have read couple of books on Python
- Dive in python
- Core Python Programming

and gone thru the links in the Internet.Python is having so many concepts,that we cannot get everything within short duration.So as we keep programming ,then thier will be more chance of learning more concepts( based on our requirements) than reading.I really appreciapte for your suggestion.

Could you please suggest some of the books you have read,which really help me in understanding the concepts in still better manner.

Thanks
PSB

[ghostdog74]

Could you please suggest some of the books you have read,which really help me in understanding the concepts in still better manner.

I have already told you one of my replies to your earlier posts, the official Python documentation site is where you should go. Read the whole web site as if its a book.

[bvdet]

Hi,

I have a number ,i have to split it into 3 digits

For Example num = 001001001001000 001

After the split it should be

001
001
001
001
000
001
Is there any better way to split it

num = '00100100100100 0001'
x1 = num[0:3]
x2 = num[3:6]
x3 = num[6:9]
x4 = num[9:12]
x5 = num[12:15]
x6 = num[15:18]

Thanks
PSB

This is exactly what we did with re in another thread of yours:[code=Python]import re

patt = re.compile(r'\d {1,3}')
num = '00100100100100 000101'
print patt.findall(nu m)

# >>> ['001', '001', '001', '001', '000', '001'][/code]Remember pattnum?
Taking it one more step:[code=Python]def fixed_field(s, n=3):
return re.findall(r'\w {1,%s}' % n, s)

print fixed_field('00 100100100100000 101')
print fixed_field('00 100100100100000 10110007008abc' , 4)

>>> ['001', '001', '001', '001', '000', '001', '01']
['0010', '0100', '1001', '0000', '0101', '1000', '7008', 'abc']
>>> [/code]To assign list items to variables:[code=Python]
for i, item in enumerate(fixed _field(num)):
exec 'x%s = item' % (i+1)[/code]