Create dictionary from another dictionary

[GTXY20]

Hello;

I have the following dictionary:

d={1:[a,b,b], 2:[a,a,b,c], 3:[a,b,c], 4:[a,c]}

I am having trouble removing the duplicate values in each of the keys value list, I need it so that:

[CODE]d={1:[a,b], 2:[a,b,c], 3:[a,b,c], 4:[a,c]}{/CODE]

I was thinking of that I would need to import the sets module???

[bvdet]

Hello;

I have the following dictionary:

d={1:[a,b,b], 2:[a,a,b,c], 3:[a,b,c], 4:[a,c]}

I am having trouble removing the duplicate values in each of the keys value list, I need it so that:

d={1:[a,b], 2:[a,b,c], 3:[a,b,c], 4:[a,c]}{/CODE]

I was thinking of that I would need to import the sets module???

Are you in Python 2.3? Here is one way of doing it:[code=Python]dd = {1:['a','b','b'], 2:['a','a','b','c'], 3:['a','b','c'], 4:['a','c']}

for item in dd.items():
    # Python 2.3
    dd[item[0]] = [i for i in item[1] if i not in locals()['_[1]'].__self__]
    # Python 2.4
    # dd[item[0]] = [i for i in item[1] if i not in locals()['_[1]']]

print dd

# >>> {1: ['a', 'b'], 2: ['a', 'b', 'c'], 3: ['a', 'b', 'c'], 4: ['a', 'c']}

If you are in 2.3, import Set from sets like this:[code=Python]>>> from sets import Set as set[/code] ...and it will seem like you are in 2.4.

[GTXY20]

Thanks!

I am actually using PythonWin 2.5.1.

Will this cause any problems - I am away from my workstation.

[bvdet]

Thanks!

I am actually using PythonWin 2.5.1.

Will this cause any problems - I am away from my workstation.

Not that I am aware of. Try the 2.4 version. If that does not work or if you would prefer using set(), use list(set([a,a,b,c])) instead. set() is built-in - no need to import.

[GTXY20]

2.4 version works great!

Thank you.