'float' / 'int' object is not iterable

[ghostdog74]

import operator
def factorial(x):
   return reduce(operator.mul, xrange(2, x+1))
result = reduce(operator.add,[ factorial(x) for x in xrange(2,101) ])
print result

[python101]

I intended to use only for loop (without using while loop, conditional statement, def)

[code=python]
n=10
e=0
for k in range(1,n):
e=2+1.0/k*(k-1)

print e

[/code]
I got 2.88888888889 which wasn't closed to 2.7. What did I do wrong, how could I fix this without using while loop, conditional statement, def

[bartonc]

I intended to use only for loop (without using while loop, conditional statement, def)

[code=python]
n=10
e=0
for k in range(1,n):
e=2+1.0/k*(k-1)

print e

[/code]
I got 2.88888888889 which wasn't closed to 2.7. What did I do wrong

For one thing, you are assigning, not accumulating, as in:[CODE=python]#
e += 2+1.0/k*(k-1)[/CODE]But that won't make the formula that you have work.

[KaezarRex]

I intended to use only for loop (without using while loop, conditional statement, def)

[code=python]
n=10
e=0
for k in range(1,n):
e=2+1.0/k*(k-1)

print e

[/code]
I got 2.88888888889 which wasn't closed to 2.7. What did I do wrong, how could I fix this without using while loop, conditional statement, def

In your for loop, "k*(k-1)" isn't equivalent to factorial. Every time it multiplies only two numbers together instead of the correct amount. As a result, the fractions being added together aren't getting smaller fast enough.

[python101]

Is there any other way to accomplish this?