Zipping and unzipping

[psychofish25]

I was wondering if there was a way that I could take a file and compress or take a file and unzip it. What would the code for that be like?

[ilikepython]

I was wondering if there was a way that I could take a file and compress or take a file and unzip it. What would the code for that be like?

I think there are a lot of modules to do this, like tarfile, zipfile, bz2, and some other.

[psychofish25]

I think there are a lot of modules to do this, like tarfile, zipfile, bz2, and some other.

Yes, but how? I looked up zipfile but didn't understand it.

[ilikepython]

Yes, but how? I looked up zipfile but didn't understand it.

Use a ZipFile object, particulary this page. Use the read and write, to unzip, and compress.

[Bierny]

Hi,
Some time ago i wrote a script that downloads a zip archive and unpacks it. Here is a part of code that was taking care of extracting all files from the archive.

# open an archive file
my_zipfile = zipfile.ZipFile(sampleZIPFilename,'r')

# unzip all files from an archive
for my_zippedfile in my_zipfile.namelist():
    f = open(my_zippedfile,'w')
    f.write(my_zipfile.read(my_zippedfile))
    f.close()

I hope this will be helpful ...

Best regards,

[bvdet]

Yes, but how? I looked up zipfile but didn't understand it.

Following is a simple application of zipfile.Zipfile :[code=Python]import zipfile, os

def makeArchive(fil eList, archive):
try:
# ZipFile will accept a file name or file object
a = zipfile.ZipFile (archive, 'w', zipfile.ZIP_DEF LATED)
for f in fileList:
print "archiving file %s" % (f)
a.write(f) # (f, os.path.basenam e(f))
a.close()
return True
except: return False

if __name__== '__main__':

fileList = ['H:/TEMP/temsys/abc1.txt',
'H:/TEMP/temsys/abc2.txt',
'H:/TEMP/temsys/abc2.txt',
'H:/TEMP/temsys/abc3.txt',
'H:/TEMP/temsys/abc4.txt'
]

arcfile_name = 'H:/TEMP/temsys/zipped_files.zi p'

if makeArchive(fil eList, arcfile_name):
print arcfile_name, "was created.\n"
# check the new archive file
f = zipfile.ZipFile (arcfile_name, 'r')
for info in f.infolist():
print info.filename, info.date_time, info.file_size, info.compress_s ize
f.close()
else:
print "There was an error"[/code]

[psychofish25]

Following is a simple application of zipfile.Zipfile :[code=Python]import zipfile, os

def makeArchive(fil eList, archive):
try:
# ZipFile will accept a file name or file object
a = zipfile.ZipFile (archive, 'w', zipfile.ZIP_DEF LATED)
for f in fileList:
print "archiving file %s" % (f)
a.write(f) # (f, os.path.basenam e(f))
a.close()
return True
except: return False

if __name__== '__main__':

fileList = ['H:/TEMP/temsys/abc1.txt',
'H:/TEMP/temsys/abc2.txt',
'H:/TEMP/temsys/abc2.txt',
'H:/TEMP/temsys/abc3.txt',
'H:/TEMP/temsys/abc4.txt'
]

arcfile_name = 'H:/TEMP/temsys/zipped_files.zi p'

if makeArchive(fil eList, arcfile_name):
print arcfile_name, "was created.\n"
# check the new archive file
f = zipfile.ZipFile (arcfile_name, 'r')
for info in f.infolist():
print info.filename, info.date_time, info.file_size, info.compress_s ize
f.close()
else:
print "There was an error"[/code]

Okay, thanks for the help.