How to say $a=$b->{"A"} ||={} in Python?

[beginner]

Hi All.

I'd like to do the following in more succint code:

if k in b:
a=b[k]
else:
a={}
b[k]=a

a['A']=1


In perl it is just one line: $a=$b->{"A"} ||={}.

Thanks,
Geoffrey

[Lawrence Oluyede]

Re: How to say $a=$b->{"A&qu ot;} ||={} in Python?

beginner <zyzhu2000@gmai l.comwrote:

I'd like to do the following in more succint code:
>
if k in b:
a=b[k]
else:
a={}
b[k]=a

b.setdefault(k, a)

--
Lawrence, oluyede.org - neropercaso.it
"It is difficult to get a man to understand
something when his salary depends on not
understanding it" - Upton Sinclair

[beginner]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 5:43 pm, ra...@dot.com (Lawrence Oluyede) wrote:

beginner <zyzhu2...@gmai l.comwrote:

I'd like to do the following in more succint code:

>

if k in b:
a=b[k]
else:
a={}
b[k]=a

>
b.setdefault(k, a)
>
--
Lawrence, oluyede.org - neropercaso.it
"It is difficult to get a man to understand
something when his salary depends on not
understanding it" - Upton Sinclair

I am afraid it is not the same. b.setdefault(k, {}) will always create
an empty dict, even if k is in b, as demonstrated in the below code.

b={}
def f(i):
print "I am evaluated %d" % i
return i

b.setdefault('A ', f(1))
b.setdefault('A ', f(2))
b

[Carl Banks]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 6:35 pm, beginner <zyzhu2...@gmai l.comwrote:

Hi All.
>
I'd like to do the following in more succint code:
>
if k in b:
a=b[k]
else:
a={}
b[k]=a
>
a['A']=1
>
In perl it is just one line: $a=$b->{"A"} ||={}.
>
Thanks,
Geoffrey

Define b as a default dict:

b = defaultdict(dic t)
b[k]['A'] = l



Carl Banks

[Jonathan Gardner]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 3:35 pm, beginner <zyzhu2...@gmai l.comwrote:

>
In perl it is just one line: $a=$b->{"A"} ||={}.
>

a = b.setdefault('A ', {})

This combines all two actions together:
- Sets b['A'] to {} if it is not already defined
- Assigns b['A'] to a

More info on dict methods here:

http://docs.python.org/lib/typesmapping.html

[Paul McGuire]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 8:28 pm, Jonathan Gardner
<jgardner.jonat hangardner....@ gmail.comwrote:

On Aug 16, 3:35 pm, beginner <zyzhu2...@gmai l.comwrote:
>
>
>

In perl it is just one line: $a=$b->{"A"} ||={}.

>
a = b.setdefault('A ', {})
>
This combines all two actions together:
- Sets b['A'] to {} if it is not already defined
- Assigns b['A'] to a
>
More info on dict methods here:
>
http://docs.python.org/lib/typesmapping.html

No, this has already been proposed and discarded. The OP does NOT
want this, because it always generates an empty {} whether it is
needed or not. Not really a big hardship, but if the default value
were some expensive-to-construct container class, then you would be
creating one every time you wanted to reference a value, on the chance
that the key did not exist.

Carl Banks' post using defaultdict is the correct solution. The
raison d'etre for defaultdict, and the reason that it is the solution
to the OP's question, is that instead of creating a just-in-case
default value every time, the defaultdict itself is constructed with a
factory method of some kind (in practice, it appears that this factory
method is usually the list or dict class constructor). If a reference
to the defaultdict gives a not-yet-existing key, then the factory
method is called to construct the new value, that value is stored in
the dict with the given key, and the value is passed back to the
caller. No instances are created unless they are truly required for
initializing an entry for a never-before-seen key.

-- Paul

[Paul McGuire]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 6:03 pm, Carl Banks <pavlovevide... @gmail.comwrote :

On Aug 16, 6:35 pm, beginner <zyzhu2...@gmai l.comwrote:
>

Hi All.

>

I'd like to do the following in more succint code:

>

if k in b:
a=b[k]
else:
a={}
b[k]=a

>

a['A']=1

>

In perl it is just one line: $a=$b->{"A"} ||={}.

>

Thanks,
Geoffrey

>
Define b as a default dict:
>
b = defaultdict(dic t)
b[k]['A'] = l
>
Carl Banks- Hide quoted text -
>
- Show quoted text -

I think the most direct translation of the OP's example to Python
would be:

# setup b as special flavor of dict, that creates a
# new dict for not-yet-created keys
b = defaultdict(dic t)

# actual python impl of $a=$b->{k}||={}
a = b[k]

# assign 1 to retrieved/created dict
a['A'] = 1

-- Paul

[Carsten Haese]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Fri, 2007-08-17 at 00:53 +0000, beginner wrote:

$b is supposed to be a hash-table of hash-table. If a key exists in
$b, it points to another hash table. The $a=$b->{"A"} ||={} pattern is
useful when you want to add records to the double hash table.
>
For example, if you have a series of records in the format of (K1, K2,
V), and you want to add them to the double hash-table, you can do
$a=$b->{K1} || ={}
$a->{K2}=V

What is the best solution in Perl need not be the best solution in
Python. In Python you should just use a tuple as your dict key, i.e.
a[k1,k2] = v, unless you have some other constraints you're not telling
us.

HTH,

--
Carsten Haese

http://informixdb.sourceforge.net

[beginner]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 9:32 pm, Carsten Haese <cars...@uniqsy s.comwrote:

On Fri, 2007-08-17 at 00:53 +0000, beginner wrote:

$b is supposed to be a hash-table of hash-table. If a key exists in
$b, it points to another hash table. The $a=$b->{"A"} ||={} pattern is
useful when you want to add records to the double hash table.

>

For example, if you have a series of records in the format of (K1, K2,
V), and you want to add them to the double hash-table, you can do
$a=$b->{K1} || ={}
$a->{K2}=V

>
What is the best solution in Perl need not be the best solution in
Python. In Python you should just use a tuple as your dict key, i.e.
a[k1,k2] = v, unless you have some other constraints you're not telling
us.
>
HTH,
>
--
Carsten Haesehttp://informixdb.sour ceforge.net

I use tuples this way all the time. It is indeed very neat. But it is
not a replacement for double hash-table. If I want to retrieve
information just by K1, it is not efficient to index on (K1, K2).

[beginner]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 5:35 pm, beginner <zyzhu2...@gmai l.comwrote:

Hi All.
>
I'd like to do the following in more succint code:
>
if k in b:
a=b[k]
else:
a={}
b[k]=a
>
a['A']=1
>
In perl it is just one line: $a=$b->{"A"} ||={}.
>
Thanks,
Geoffrey

It looks like defaultdict is the solution for this kind of thing.
Thanks all for your help.

[Carsten Haese]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Fri, 17 Aug 2007 03:15:10 -0000, beginner wrote

On Aug 16, 9:32 pm, Carsten Haese <cars...@uniqsy s.comwrote:

What is the best solution in Perl need not be the best solution in
Python. In Python you should just use a tuple as your dict key, i.e.
a[k1,k2] = v, unless you have some other constraints you're not telling
us.

HTH,

--
Carsten Haesehttp://informixdb.sour ceforge.net

>
I use tuples this way all the time. It is indeed very neat. But it
is not a replacement for double hash-table. If I want to retrieve
information just by K1, it is not efficient to index on (K1, K2).

If you have to look up all values associates with k1 and any k2, you're right,
that's not efficient. That would fall under "other constraints you're not
telling us." I'm not a mind reader.

-Carsten

[=?ISO-8859-1?Q?S=E9bastien_Buchoux?=]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

beginner a écrit :

Hi All.
>
I'd like to do the following in more succint code:
>
if k in b:
a=b[k]
else:
a={}
b[k]=a
>
a['A']=1
>
>
In perl it is just one line: $a=$b->{"A"} ||={}.
>
Thanks,
Geoffrey
>
>

One solution I often use in such cases:

try:
a = b[k]
except KeyError: #or except IndexError: if b is a list/tuple and not a dict
a = {}
b[k] = a

a['A'] = 1

Indeed, exceptions are handled faster than "if/else" loops. As it was
mentionned earlier, One neat solution in Perl may not be the perfect one
in Python.

Cheers,

Sébastien

[beginner]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 17, 2:35 am, Sébastien Buchoux <seb.buch...@gm ail.comwrote:

beginner a écrit :
>
>
>

Hi All.

>

I'd like to do the following in more succint code:

>

if k in b:
a=b[k]
else:
a={}
b[k]=a

>

a['A']=1

>

In perl it is just one line: $a=$b->{"A"} ||={}.

>

Thanks,
Geoffrey

>
One solution I often use in such cases:
>
try:
a = b[k]
except KeyError: #or except IndexError: if b is a list/tuple and not a dict
a = {}
b[k] = a
>
a['A'] = 1
>
Indeed, exceptions are handled faster than "if/else" loops. As it was
mentionned earlier, One neat solution in Perl may not be the perfect one
in Python.
>
Cheers,
>
Sébastien- Hide quoted text -
>
- Show quoted text -

Wow. This solution is interesting. I'll try this. Thanks.

[beginner]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 11:02 pm, "Carsten Haese" <cars...@uniqsy s.comwrote:

On Fri, 17 Aug 2007 03:15:10 -0000, beginner wrote
>

On Aug 16, 9:32 pm, Carsten Haese <cars...@uniqsy s.comwrote:

What is the best solution in Perl need not be the best solution in
Python. In Python you should just use a tuple as your dict key, i.e.
a[k1,k2] = v, unless you have some other constraints you're not telling
us.

>

HTH,

>

--
Carsten Haesehttp://informixdb.sour ceforge.net

>

I use tuples this way all the time. It is indeed very neat. But it
is not a replacement for double hash-table. If I want to retrieve
information just by K1, it is not efficient to index on (K1, K2).

>
If you have to look up all values associates with k1 and any k2, you're right,
that's not efficient. That would fall under "other constraints you're not
telling us." I'm not a mind reader.
>
-Carsten

Yeah, I should have mentioned that I actually want to group the data
by K1 and then by K2.

[Carl Banks]

Re: How to say $a=$b-&gt;{&quot;A&qu ot;} ||={} in Python?

On Aug 16, 10:01 pm, Paul McGuire <pt...@austin.r r.comwrote:

On Aug 16, 8:28 pm, Jonathan Gardner
>
>
>
<jgardner.jonat hangardner....@ gmail.comwrote:

On Aug 16, 3:35 pm, beginner <zyzhu2...@gmai l.comwrote:

>

In perl it is just one line: $a=$b->{"A"} ||={}.

>

a = b.setdefault('A ', {})

>

This combines all two actions together:
- Sets b['A'] to {} if it is not already defined
- Assigns b['A'] to a

>

More info on dict methods here:

>

http://docs.python.org/lib/typesmapping.html

>
No, this has already been proposed and discarded. The OP does NOT
want this, because it always generates an empty {} whether it is
needed or not. Not really a big hardship, but if the default value
were some expensive-to-construct container class, then you would be
creating one every time you wanted to reference a value, on the chance
that the key did not exist.
>
Carl Banks' post using defaultdict is the correct solution. The
raison d'etre for defaultdict, and the reason that it is the solution
to the OP's question, is that instead of creating a just-in-case
default value every time, the defaultdict itself is constructed with a
factory method of some kind (in practice, it appears that this factory
method is usually the list or dict class constructor). If a reference
to the defaultdict gives a not-yet-existing key, then the factory
method is called to construct the new value, that value is stored in
the dict with the given key, and the value is passed back to the
caller. No instances are created unless they are truly required for
initializing an entry for a never-before-seen key.

When I made my response, it occurred to me that Python could be
improved (maybe) if one could overload dict.get() to use a factory,
like so:

b = {}
a = b.get(k,factory =dict)
a['A'] = 1

That's a slight improvement (maybe) over defaultdict since it would
still allow the same dict to have the membership check in other
places. I'm not so sure overloading get to let it modify the dict is
a good idea, though.

Actually, it'd probably be fairly uncontroversial to add a factory
keyword to dict.setdefault (). At least insofar as setdefault is
uncontroversial .


Carl Banks