return dictionary values as single list

[kdt]

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

>>> d['a']= [(45,6)]
>>> d['a'].append((56,4))
>>> d['a']
[(45, 6), (56, 4)]
>>> s =[]
>>> for i, j in enumerate(d['a']):
... 	for k, l in enumerate(j):
... 		s.append(l)
... 		
>>> s
[45, 6, 56, 4]
>>>

thanks

[ilikepython]

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

>>> d['a']= [(45,6)]
>>> d['a'].append((56,4))
>>> d['a']
[(45, 6), (56, 4)]
>>> s =[]
>>> for i, j in enumerate(d['a']):
... 	for k, l in enumerate(j):
... 		s.append(l)
... 		
>>> s
[45, 6, 56, 4]
>>>

thanks

[code=python]
s = [value for tup in d['a'] for value in tup]
[/code]
Hope that helps.

[bartonc]

Can anyone suggest a better way of returning the values in a dictionary as a single list. I have the following, but it uses a nested loop, not sure if there is a more efficient way.

>>> d['a']= [(45,6)]
>>> d['a'].append((56,4))
>>> d['a']
[(45, 6), (56, 4)]
>>> s =[]
>>> for i, j in enumerate(d['a']):
... 	for k, l in enumerate(j):
... 		s.append(l)
... 		
>>> s
[45, 6, 56, 4]
>>>

thanks

[CODE=python]
>>> aList = [(45, 6), (56, 4)]
>>> newList = []
>>> for tup in aList:
... newList.extend( tup)
...
>>> newList
[45, 6, 56, 4]
>>> [/CODE]

[kdt]

Sweet, thanks. Much better!

[bartonc]

Sweet, thanks. Much better!

You did see mine, right? One minute apart, maybe you were posting while I was.

[ilikepython]

[CODE=python]
>>> aList = [(45, 6), (56, 4)]
>>> newList = []
>>> for tup in aList:
... newList.extend( tup)
...
>>> newList
[45, 6, 56, 4]
>>> [/CODE]

Just for fun, you could do that with map:
[code=python]
>>> aList = [(45, 6), (56, 4)]
>>> newList = []
>>> map(newList.ext end, aList)
>>> newList
[45, 6, 56, 4]
[/code]

[bartonc]

Just for fun, you could do that with map:
[code=python]
>>> aList = [(45, 6), (56, 4)]
>>> newList = []
>>> map(newList.ext end, aList)
>>> newList
[45, 6, 56, 4]
[/code]

Bonus points to you, my friend! Two lines in one; very nicely done.