making a variable available in a function from decorator

[rkmr.em@gmail.com]

Hi
I create a variable in a decorator. i want to be able to access that
variable in the function to be decorated. How to do this?
thanks

[Marc 'BlackJack' Rintsch]

Re: making a variable available in a function from decorator

On Sun, 29 Jul 2007 15:22:47 -0700, rkmr.em@gmail.c om wrote:

I create a variable in a decorator. i want to be able to access that
variable in the function to be decorated. How to do this?

Pass it as argument to the function:

def deco(func):
eggs = 42
def decorated(*args , **kwargs):
kwargs['spam'] = eggs
func(*args, **kwargs)
return decorated

@deco
def test(parrot, spam):
print parrot, spam

Ciao,
Marc 'BlackJack' Rintsch

[rkmr.em@gmail.com]

Re: making a variable available in a function from decorator

is it possible to do this without passing it as a function argument?

On 30 Jul 2007 06:17:25 GMT, Marc 'BlackJack' Rintsch <bj_666@gmx.net wrote:

On Sun, 29 Jul 2007 15:22:47 -0700, rkmr.em@gmail.c om wrote:
>

I create a variable in a decorator. i want to be able to access that
variable in the function to be decorated. How to do this?

>
Pass it as argument to the function:
>
def deco(func):
eggs = 42
def decorated(*args , **kwargs):
kwargs['spam'] = eggs
func(*args, **kwargs)
return decorated
>
@deco
def test(parrot, spam):
print parrot, spam
>
Ciao,
Marc 'BlackJack' Rintsch
--

http://mail.python.org/mailman/listinfo/python-list

>

[Bruno Desthuilliers]

Re: making a variable available in a function from decorator

rkmr.em@gmail.c om a écrit :
(top-post corrected)

>
On 30 Jul 2007 06:17:25 GMT, Marc 'BlackJack' Rintsch <bj_666@gmx.net wrote:

>On Sun, 29 Jul 2007 15:22:47 -0700, rkmr.em@gmail.c om wrote:
>>

>>I create a variable in a decorator. i want to be able to access that
>>variable in the function to be decorated. How to do this?

>

>Pass it as argument to the function:
>>
>def deco(func):
> eggs = 42
> def decorated(*args , **kwargs):
> kwargs['spam'] = eggs
> func(*args, **kwargs)
> return decorated
>>
>@deco
>def test(parrot, spam):
> print parrot, spam

is it possible to do this without passing it as a function argument?

What's your use case, exactly ? Having a function depending on a name
being set by a decorator is not exactly pythonic, and arguments are
meant to pass variables to functions...

[Evan Klitzke]

Re: making a variable available in a function from decorator

On 7/30/07, rkmr.em@gmail.c om <rkmr.em@gmail. comwrote:

is it possible to do this without passing it as a function argument?
>

Sort of. Functions are objects in python, so you can set attribute on them. E.g.

def foo():
return foo.c

foo.c = 1
print foo()

Which will print 1. Of course, it would generally be better to write
your own class for this sort of thing, so that you can set the
variable in the instance scope.

--
Evan Klitzke <evan@yelp.co m>

[Bruno Desthuilliers]

Re: making a variable available in a function from decorator

Evan Klitzke a écrit :

On 7/30/07, rkmr.em@gmail.c om <rkmr.em@gmail. comwrote:
>

>>is it possible to do this without passing it as a function argument?
>>

Sort of. Functions are objects in python, so you can set attribute on them. E.g.
>
def foo():
return foo.c
>
foo.c = 1
print foo()

>>def foo():

.... print foo.c
....

>>foo.c = 1
>>bar = foo
>>del foo
>>bar()

Traceback (most recent call last):
File "<stdin>", line 1, in ?
File "<stdin>", line 2, in foo
NameError: global name 'foo' is not defined

>>>

Which will print 1. Of course, it would generally be better to write
your own class for this sort of thing, so that you can set the
variable in the instance scope.

Indeed. But even with OO, explicit is better than implicit.