bools in python

[vajratkarviraj]

question from a newbie:
can somebody help me in converting this c++ code to python...
[CODE=c]
bool flag;
do{
flag=0;
for(int i=0;i<n;i++){
double s1=xold[i];
double s2=xnew[i];
e[i]= s1-s2;
if (e[i]<0) {e[i]=0-e[i];}
if(e[i]>prec){flag=1 ;}

for(int i=0;i<n;i++){
xold[i]=xnew[i];
}

}
}while (flag);
[/CODE]
basically the bool thing is a prob... also if i hav created a function(say solve(parameter s)) within a function(say display(paramet ers)).... then the python code goes sumwat like this:

def display(parameter1, parameter2):

{code of display}

solve(parameter3, parameter4):

{code of solve and it gives me output its output in the form of a number}

#now i want to return control to display

{remaining code of display continues...}

[bartonc]

question from a newbie:
can somebody help me in converting this c++ code to python...
[CODE=c]
bool flag;
do{
flag=0;
for(int i=0;i<n;i++){
double s1=xold[i];
double s2=xnew[i];
e[i]= s1-s2;
if (e[i]<0) {e[i]=0-e[i];}
if(e[i]>prec){flag=1 ;}

for(int i=0;i<n;i++){
xold[i]=xnew[i];
}

}
}while (flag);
[/CODE]<snip>

I'm not so hot with C, but it looks like the while will never execute due to flag=0, but (or maybe it executes once because while() is evaluated last) - I'll show the latter:[CODE=python]n = 4 # counter for for()
flag = 0
while True: # Note that python is indentation based
for i in range(n): # use xrange() for huge numbers
s1 = xold[i]
s2 = xnew[i]
e[i] = s1 - s2
if e[i] < 0: # colon starts a block, next de-dent ends it
e[i] = 0 - e[i]
if e[i] > prec:
flag=1
# comments can go on any indent level - etc...
if not flag:
break[/CODE]
That is, if I'm reading the C part correctly. Close, anyway

[bartonc]

I'm not so hot with C, but it looks like the while will never execute due to flag=0, but (or maybe it executes once because while() is evaluated last) - I'll show the latter:[CODE=python]n = 4 # counter for for()
flag = 0
while True: # Note that python is indentation based
for i in range(n): # use xrange() for huge numbers
s1 = xold[i]
s2 = xnew[i]
e[i] = s1 - s2
if e[i] < 0: # colon starts a block, next de-dent ends it
e[i] = 0 - e[i]
if e[i] > prec:
flag=1
# comments can go on any indent level - etc...
if not flag:
break[/CODE]
That is, if I'm reading the C part correctly. Close, anyway

Anything that has a non-zero value will evaluate as True.
bool is a subclass of int so you can do many things with python bools that other languages wouldn't dream of doing (including list indexing):[CODE=python]timeToStop = True
print ['still going', 'stopping'][timeToStop][/CODE]Kind of nifty, huh?

[Smygis]

question from a newbie:
can somebody help me in converting this c++ code to python...
[CODE=c]
bool flag;
do{
flag=0;
for(int i=0;i<n;i++){
double s1=xold[i];
double s2=xnew[i];
e[i]= s1-s2;
if (e[i]<0) {e[i]=0-e[i];}
if(e[i]>prec){flag=1 ;}

for(int i=0;i<n;i++){
xold[i]=xnew[i];
}

}
}while (flag);
[/CODE]
basically the bool thing is a prob... also if i hav created a function(say solve(parameter s)) within a function(say display(paramet ers)).... then the python code goes sumwat like this:

def display(parameter1, parameter2):

{code of display}

solve(parameter3, parameter4):

{code of solve and it gives me output its output in the form of a number}

#now i want to return control to display

{remaining code of display continues...}

First of, Only becouse C++ lets you make your code 100% unreadable does not mean you shuld do it.

[code=cpp]
bool flag;
do{
flag = 0;
for(int i = 0; i < n; i++)
{
double s1 = xold[i];
double s2 = xnew[i];

e[i] = s1 - s2;

if (e[i] < 0)
e[i] = 0 - e[i];

if(e[i] > prec)
flag = 1;

for(int i = 0; i < n; i++)
xold[i] = xnew[i];
}
}while(flag);[/code]

And as for your second Q,
[code=python]
def solver(arg1, arg2):
return arg1 ** arg2 # Ofcource you will replace this with whatever you want it to do

def display(no1, no2):
# Code
solvednum = solver(no2, no1)
# more code
[/code]

Simply create multiple functions.