Building arguments for function calls

[dberg]

Hi all-

I have a function call that uses keyword arguments:

lib_routine( status=computed _value, hw_id=value[1], sw_id=value[2], \
something=value[3], something_else= value[4]...... )

There can be as many as 10 different keywords with the =value[n] construct. There can also be as few as 2 keywords passed to the function (status and one of the =value[n] constructs). Of course, anything between the 2 and 10 values are valid. Parsing a string of user-supplied text fills in the "value" list.

How do I construct an argument list for the function call that only contains keywords that contain data (i.e., if value[3] == "", I do not want to have the something=value[3] in the argument list).

Any hints/pointers would be greatly appreciated.

Thanks,
Dave

[bvdet]

Hi all-

I have a function call that uses keyword arguments:

lib_routine( status=computed _value, hw_id=value[1], sw_id=value[2], \
something=value[3], something_else= value[4]...... )

There can be as many as 10 different keywords with the =value[n] construct. There can also be as few as 2 keywords passed to the function (status and one of the =value[n] constructs). Of course, anything between the 2 and 10 values are valid. Parsing a string of user-supplied text fills in the "value" list.

How do I construct an argument list for the function call that only contains keywords that contain data (i.e., if value[3] == "", I do not want to have the something=value[3] in the argument list).

Any hints/pointers would be greatly appreciated.

Thanks,
Dave

This sounds like a job for a ..............D ICTIONARY!

>>> dd = {'value1': 12, 'value2': '', 'value3': 'a string', 'value4': ['a', 1, '5', 12.438]}
>>> dd1 = {}
>>> for key in dd:
... 	if dd[key] != '':
... 		dd1[key] = dd[key]
... 		
>>> def keyword_args(**kargs):
... 	for key in kargs:
... 		print key, kargs[key]
... 		
>>> keyword_args(**dd1)
value4 ['a', 1, '5', 12.438000000000001]
value3 a string
value1 12
>>>

[bartonc]

Hi all-

I have a function call that uses keyword arguments:

lib_routine( status=computed _value, hw_id=value[1], sw_id=value[2], \
something=value[3], something_else= value[4]...... )

There can be as many as 10 different keywords with the =value[n] construct. There can also be as few as 2 keywords passed to the function (status and one of the =value[n] constructs). Of course, anything between the 2 and 10 values are valid. Parsing a string of user-supplied text fills in the "value" list.

How do I construct an argument list for the function call that only contains keywords that contain data (i.e., if value[3] == "", I do not want to have the something=value[3] in the argument list).

Any hints/pointers would be greatly appreciated.

Thanks,
Dave

Use ** to "de-reference" any dict. My friend bvdet may be along shortly to show cool usage of zip to create dictionaries, but in the meantime:
>>> def funcWithKeyWord Args(**kwargs):
... print kwargs
...
>>> funcWithKeyWord Args(**{"keywor d":5})
{'keyword': 5}
>>>

[dberg]

Hi bvdet and bartonc-

Thank you very much for the help. Yes, the dictionary (and ** ) was exactly what I was looking for - and it worked perfectly.

Much thanks,
Dave

[bartonc]

Hi bvdet and bartonc-

Thank you very much for the help. Yes, the dictionary (and ** ) was exactly what I was looking for - and it worked perfectly.

Much thanks,
Dave

You are very welcome. Drop on in any ol' time.