Getting a extension of a given filename

[psbasha]

Hi,

I need to extract the filename extension from the given filename at a particular location

I/P:
say 'C:\Sample\Samp le1.txt'

O/P :
The file etension is '.txt'

Thanks
PSB

[Motoma]

[code=python]
def findExt(filenam e):
return filename.rparti tion(".")[2]
[/code]

[psbasha]

[code=python]
def findExt(filenam e):
return filename.rparti tion(".")[2]
[/code]

Is it a filepointer or a Filename path?

[bvdet]

>>> import os
>>> p = r'C:\SDS2_7.0\macro\Zip\tem_v1.00.txt'
>>> os.path.splitext(p)
('C:\\SDS2_7.0\\macro\\Zip\\tem_v1.00', '.txt')
>>>

[Motoma]

Is it a filepointer or a Filename path?

The filename variable is a string.

[ghostdog74]

Is it a filepointer or a Filename path?

you should also note that rpartition is available in Python 2.5. if earlier, use bv's method, or use the usual split way:

"c:\\test.txt.txt".split(".")[-1]

[Motoma]

>>> import os
>>> p = r'C:\SDS2_7.0\macro\Zip\tem_v1.00.txt'
>>> os.path.splitext(p)
('C:\\SDS2_7.0\\macro\\Zip\\tem_v1.00', '.txt')
>>>

Thanks bvdet. This would be the preferable way of doing it, in my opinion, as it is built into the language.

[ghostdog74]

Thanks bvdet. This would be the preferable way of doing it, in my opinion, as it is built into the langage.

hmm..I cannot say if its "built in" (as in really built in , like str(), int) because to use os.path.splitex t, we need to import os. but to use rpartition, as its a string method, just need "path".rpartiti on("") , much like split() method :)

[Motoma]

hmm..I cannot say if its "built in" (as in really built in , like str(), int) because to use os.path.splitex t, we need to import os. but to use rpartition, as its a string method, just need "path".rpartiti on("") , much like split() method :)

I agree with what you are saying; I guess what I was getting at is that the os.path.splitex t was designed specifically for this purpose, whilst rpartition has a variety of uses.

[pyarticles]

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