Creating a double dimension array

[psbasha]

Hi,

I would like to create a dimensional array ( elements should be stored in a row wise and column wise).

I have the following details in that row of each elements

Row-1-> [ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag].......[ID,X,Y,Z,Flag]
Row-2-> [ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag].......[ID,X,Y,Z,Flag]
Row-3-> [ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag].......[ID,X,Y,Z,Flag]

............... ............... ............... .............
Row4-> [ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag].......[ID,X,Y,Z,Flag]

I have to store the elements in the order and retrieve them in order.Can anbody help me with sample code

Thanks
PSB

[psbasha]

Hi,

I would like to create a dimensional array ( elements should be stored in a row wise and column wise).

I have the following details in that row of each elements

Row-1-> [ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag].......[ID,X,Y,Z,Flag]
Row-2-> [ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag].......[ID,X,Y,Z,Flag]
Row-3-> [ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag].......[ID,X,Y,Z,Flag]

............... ............... ............... .............
Row4-> [ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag],[ID,X,Y,Z,Flag].......[ID,X,Y,Z,Flag]

I have to store the elements in the order and retrieve them in order.Can anbody help me with sample code

Thanks
PSB

I am getting the following error when I am trying

Sample
>>> l1 = [['id1',1,1,1,True],['id2',2,1,1,True],['id3',1,1,1,True]]
>>> l2[0].append(l1)
Traceback (most recent call last):
  File "<interactive input>", line 1, in ?
NameError: name 'l2' is not defined
>>> l2 =[][]
Traceback (  File "<interactive input>", line 1
    l2 =[][]
           ^
SyntaxError: invalid syntax
>>> l2 = []
>>> l2[0].append(l1)
Traceback (most recent call last):
  File "<interactive input>", line 1, in ?
IndexError: list index out of range
>>>

[bvdet]

I am getting the following error when I am trying

Sample
>>> l1 = [['id1',1,1,1,True],['id2',2,1,1,True],['id3',1,1,1,True]]
>>> l2[0].append(l1)
Traceback (most recent call last):
  File "<interactive input>", line 1, in ?
NameError: name 'l2' is not defined
>>> l2 =[][]
Traceback (  File "<interactive input>", line 1
    l2 =[][]
           ^
SyntaxError: invalid syntax
>>> l2 = []
>>> l2[0].append(l1)
Traceback (most recent call last):
  File "<interactive input>", line 1, in ?
IndexError: list index out of range
>>>

>>> l1 = [['id1',1,1,1,True],['id2',2,1,1,True],['id3',1,1,1,True]]
>>> l2 = [[]]
>>> l2[0].append(l1)
>>> l2
[[[['id1', 1, 1, 1, True], ['id2', 2, 1, 1, True], ['id3', 1, 1, 1, True]]]]
>>>

append() is a list method.

[psbasha]

>>> l1 = [['id1',1,1,1,True],['id2',2,1,1,True],['id3',1,1,1,True]]
>>> l2 = [[]]
>>> l2[0].append(l1)
>>> l2
[[[['id1', 1, 1, 1, True], ['id2', 2, 1, 1, True], ['id3', 1, 1, 1, True]]]]
>>>

append() is a list method.

Thanks for the reply.

The above approach looks good ,but accessing the data from list of list seems to be complex.Is there any simple method available ,to create and access the Double dimension array values.

-PSB

[psbasha]

How can I identify which is first row elemenst I am refering to ?.

Need a example for explaining the double dimension arrays using list.

-PSB

[bvdet]

Here's an exercise I did with a list of lists:

class Sarray(object):
    def __init__(self, cols, rows):
        self.cols = cols
        self.rows = rows
        # initialize array and fill with zeroes
        self.array = [[0 for i in range(cols)] for j in range(rows)]

    def setitem(self, col, row, v):
        try:
            self.array[row][col] = v
        except IndexError, e:
            print 'Valid column/row numbers are %s/%s\n' % (range(self.cols), range(self.rows))
            return None

    def getitem(self, col, row):
        try:
            return self.array[row][col]
        except IndexError, e:
            print 'Valid column/row numbers are %s/%s' % (range(self.cols), range(self.rows))
            return None

    def getcolumn(self, col):
        try:
            return [item[col] for item in self.array]
        except IndexError, e:
            print 'Valid column numbers are %s' % (range(self.cols))
            return None

    def getrow(self,row):
        try:
            return self.array[row]
        except IndexError, e:
            print 'Valid row numbers are %s' % (range(self.rows))
            return None

    def __iter__(self):
        for item in self.array:
            yield item

    def __repr__(self):
        outStr = ""
        for i, item in enumerate(self):
            outStr += 'Row %s = %s\n' % (i, self.array[i])
        return outStr


a = Sarray(4,5)
print a
a.setitem(3,4,55.75)
print a
a.setitem(2,3,19.1)

print a
print a.getitem(3,4)

print
for item in a:
    print item
    
print
x = 1.5
for item in a:
    print 'item =', item
    for i, val in enumerate(item):
        x = x*2.0
        print x
        item[i] = x

print a    
    
print a.getcolumn(4)
print a.getcolumn(2)
print a.getrow(4)
print a.getrow(2)

print a.getitem(4,4)
print a.getitem(3,3)

Output:>>> Row 0 = [0, 0, 0, 0]
Row 1 = [0, 0, 0, 0]
Row 2 = [0, 0, 0, 0]
Row 3 = [0, 0, 0, 0]
Row 4 = [0, 0, 0, 0]

Row 0 = [0, 0, 0, 0]
Row 1 = [0, 0, 0, 0]
Row 2 = [0, 0, 0, 0]
Row 3 = [0, 0, 0, 0]
Row 4 = [0, 0, 0, 55.75]

Row 0 = [0, 0, 0, 0]
Row 1 = [0, 0, 0, 0]
Row 2 = [0, 0, 0, 0]
Row 3 = [0, 0, 19.100000000000 001, 0]
Row 4 = [0, 0, 0, 55.75]

55.75

[0, 0, 0, 0]
[0, 0, 0, 0]
[0, 0, 0, 0]
[0, 0, 19.100000000000 001, 0]
[0, 0, 0, 55.75]

item = [0, 0, 0, 0]
3.0
6.0
12.0
24.0
item = [0, 0, 0, 0]
48.0
96.0
192.0
384.0
item = [0, 0, 0, 0]
768.0
1536.0
3072.0
6144.0
item = [0, 0, 19.100000000000 001, 0]
12288.0
24576.0
49152.0
98304.0
item = [0, 0, 0, 55.75]
196608.0
393216.0
786432.0
1572864.0
Row 0 = [3.0, 6.0, 12.0, 24.0]
Row 1 = [48.0, 96.0, 192.0, 384.0]
Row 2 = [768.0, 1536.0, 3072.0, 6144.0]
Row 3 = [12288.0, 24576.0, 49152.0, 98304.0]
Row 4 = [196608.0, 393216.0, 786432.0, 1572864.0]

Valid column numbers are [0, 1, 2, 3]
None
[12.0, 192.0, 3072.0, 49152.0, 786432.0]
[196608.0, 393216.0, 786432.0, 1572864.0]
[768.0, 1536.0, 3072.0, 6144.0]
Valid column/row numbers are [0, 1, 2, 3]/[0, 1, 2, 3, 4]
None
98304.0
>>>

[psbasha]

Here's an exercise I did with a list of lists:

class Sarray(object):
    def __init__(self, cols, rows):
        self.cols = cols
        self.rows = rows
        # initialize array and fill with zeroes
        self.array = [[0 for i in range(cols)] for j in range(rows)]

    def setitem(self, col, row, v):
        try:
            self.array[row][col] = v
        except IndexError, e:
            print 'Valid column/row numbers are %s/%s\n' % (range(self.cols), range(self.rows))
            return None

    def getitem(self, col, row):
        try:
            return self.array[row][col]
        except IndexError, e:
            print 'Valid column/row numbers are %s/%s' % (range(self.cols), range(self.rows))
            return None

    def getcolumn(self, col):
        try:
            return [item[col] for item in self.array]
        except IndexError, e:
            print 'Valid column numbers are %s' % (range(self.cols))
            return None

    def getrow(self,row):
        try:
            return self.array[row]
        except IndexError, e:
            print 'Valid row numbers are %s' % (range(self.rows))
            return None

    def __iter__(self):
        for item in self.array:
            yield item

    def __repr__(self):
        outStr = ""
        for i, item in enumerate(self):
            outStr += 'Row %s = %s\n' % (i, self.array[i])
        return outStr


a = Sarray(4,5)
print a
a.setitem(3,4,55.75)
print a
a.setitem(2,3,19.1)

print a
print a.getitem(3,4)

print
for item in a:
    print item
    
print
x = 1.5
for item in a:
    print 'item =', item
    for i, val in enumerate(item):
        x = x*2.0
        print x
        item[i] = x

print a    
    
print a.getcolumn(4)
print a.getcolumn(2)
print a.getrow(4)
print a.getrow(2)

print a.getitem(4,4)
print a.getitem(3,3)

Output:>>> Row 0 = [0, 0, 0, 0]
Row 1 = [0, 0, 0, 0]
Row 2 = [0, 0, 0, 0]
Row 3 = [0, 0, 0, 0]
Row 4 = [0, 0, 0, 0]

Row 0 = [0, 0, 0, 0]
Row 1 = [0, 0, 0, 0]
Row 2 = [0, 0, 0, 0]
Row 3 = [0, 0, 0, 0]
Row 4 = [0, 0, 0, 55.75]

Row 0 = [0, 0, 0, 0]
Row 1 = [0, 0, 0, 0]
Row 2 = [0, 0, 0, 0]
Row 3 = [0, 0, 19.100000000000 001, 0]
Row 4 = [0, 0, 0, 55.75]

55.75

[0, 0, 0, 0]
[0, 0, 0, 0]
[0, 0, 0, 0]
[0, 0, 19.100000000000 001, 0]
[0, 0, 0, 55.75]

item = [0, 0, 0, 0]
3.0
6.0
12.0
24.0
item = [0, 0, 0, 0]
48.0
96.0
192.0
384.0
item = [0, 0, 0, 0]
768.0
1536.0
3072.0
6144.0
item = [0, 0, 19.100000000000 001, 0]
12288.0
24576.0
49152.0
98304.0
item = [0, 0, 0, 55.75]
196608.0
393216.0
786432.0
1572864.0
Row 0 = [3.0, 6.0, 12.0, 24.0]
Row 1 = [48.0, 96.0, 192.0, 384.0]
Row 2 = [768.0, 1536.0, 3072.0, 6144.0]
Row 3 = [12288.0, 24576.0, 49152.0, 98304.0]
Row 4 = [196608.0, 393216.0, 786432.0, 1572864.0]

Valid column numbers are [0, 1, 2, 3]
None
[12.0, 192.0, 3072.0, 49152.0, 786432.0]
[196608.0, 393216.0, 786432.0, 1572864.0]
[768.0, 1536.0, 3072.0, 6144.0]
Valid column/row numbers are [0, 1, 2, 3]/[0, 1, 2, 3, 4]
None
98304.0
>>>

Thanks BV,
But my requirement is I need to retrieve the list data from the double dimension array

Sample

Input : Say GridMat

                     Col 0           Col 1                  Col 2
Row 0  [ 'ID1','1','1','1','0'], [ 'ID2','2','1','1','0'] [ 'ID3','3','1','1','0']
Row 1  [ 'ID4','1','2','1','0'], [ 'ID5','2','2','1','0'] [ 'ID6','3','2','1','0']
Row 2  [ 'ID7','1','3','1','0'], [ 'ID8','2','3','1','0'] [ 'ID9','3','3','1','0']

Output :
---------------

GridMat [0][1] gives [ 'ID2','2','1','1','0'] it is Row-0 and Col-1
                        or 

if I say GridMat [0],then I have to get the Row-0 elements
 [ 'ID1','1','1','1','0'], [ 'ID2','2','1','1','0'] [ 'ID3','3','1','1','0']

Similarly

GridMat [2] should give the output as 

Row 2  [ 'ID7','1','3','1','0'], [ 'ID8','2','3','1','0'] [ 'ID9','3','3','1','0']

-PSB

[psbasha]

Thanks BV,
But my requirement is I need to retrieve the list data from the double dimension array

Sample

Input : Say GridMat

                     Col 0           Col 1                  Col 2
Row 0  [ 'ID1','1','1','1','0'], [ 'ID2','2','1','1','0'] [ 'ID3','3','1','1','0']
Row 1  [ 'ID4','1','2','1','0'], [ 'ID5','2','2','1','0'] [ 'ID6','3','2','1','0']
Row 2  [ 'ID7','1','3','1','0'], [ 'ID8','2','3','1','0'] [ 'ID9','3','3','1','0']

Output :
---------------

GridMat [0][1] gives [ 'ID2','2','1','1','0'] it is Row-0 and Col-1
                        or 

if I say GridMat [0],then I have to get the Row-0 elements
 [ 'ID1','1','1','1','0'], [ 'ID2','2','1','1','0'] [ 'ID3','3','1','1','0']

Similarly

GridMat [2] should give the output as 

Row 2  [ 'ID7','1','3','1','0'], [ 'ID8','2','3','1','0'] [ 'ID9','3','3','1','0']

-PSB

I dont now the size of the Matrix ( Rows and Columns) .Dynamically has to insert the data,from the output as I get.

[bvdet]

You can add new methods to the Sarray class to do whatever you want.

[bvdet]

Maybe you should look into Numpy. Unfortunately, I don't have any experience with it, but it should handle your arrays well. The Sarray class was an exercise I did a few months ago.

[bvdet]

PSB,

Just curious - did you find a solution? These methods will add rows and columns:

    def addrow(self, row):
        self.array.append(row)
        return self.array

    def addcol(self, col):
        for i, item in enumerate(self):
            try:
                item.append(col[i])
            except:
                item.append(None)
        return self.array

[psbasha]

PSB,

Just curious - did you find a solution? These methods will add rows and columns:

    def addrow(self, row):
        self.array.append(row)
        return self.array

    def addcol(self, col):
        for i, item in enumerate(self):
            try:
                item.append(col[i])
            except:
                item.append(None)
        return self.array

I have implemented in the following way

[CODE]

>>> l = [[[1,2,3],[2,1,2]],[[1,1,1],[2,1,3]]]
#First Row
>>> l[0]
[[1, 2, 3], [2, 1, 2]]
#Second Row
>>> l[1]
[[1, 1, 1], [2, 1, 3]]
#First Row,First Column

>>> l[0][0]
[1, 2, 3]
#First Row,Second Column

>>> l[0][1]
[2, 1, 2]
>>>