regular expression for parsing an html element

[abcd]

I have some HTML such as....

<a href="...."><im g src="image/blah/a.jpg" id="ddddd">bla h blah blah</
a>....

I wnat to pull out the text that lies inside the quotes of the src
attribute. So in this example I would get image/blah/a.jpg

My regex so far is: src=\"(.*)\" ....however the group in this case
would end up being, image/blah/a.jpg" id="ddddd">bla h blah blah</
a>.....

how can I tell the regex group (.*) to end when it gets to the first
" ?

thanks

[=?ISO-8859-2?Q?Wojciech_Mu=B3a?=]

Re: regular expression for parsing an html element

abcd wrote:

My regex so far is: src=\"(.*)\" ....however the group in this case
would end up being, image/blah/a.jpg" id="ddddd">bla h blah blah</
a>.....
>
how can I tell the regex group (.*) to end when it gets to the first
" ?

Use non-greedy matching, i.e. src=\"(.*?)\" (question mark after *.)
See: http://docs.python.org/lib/re-syntax.html

w.

[abcd]

Re: regular expression for parsing an html element

thanks, forgot that.