script for seconds in given month?

**Jim** · Apr 16 '07, 04:55 PM

Re: script for seconds in given month?

On Apr 16, 12:22 pm, "edfialk" <edfi...@gmail. comwrote:

Hi, does anyone happen to know of a script that would return the
number of seconds in a month if I give it a month and a year?
>
My python is a little weak, but if anyone could offer some suggestions
I think I could handle it myself, or if anyone happens to know of a
script already written that performs this I would be extremely
grateful.

Probably there are sophisticated answers, but have you tried
something like:

monthDays={'Jan ':31,'Feb':28, ..}
secs=60*60*24*m onthDays[thisMonth]
if (thisMonth=='Fe b'
and isLeap(thisYear )):
secs+=60*60*24
return secs

?

**pythoncurious@gmail.com** · Apr 16 '07, 05:05 PM

Re: script for seconds in given month?

On Apr 16, 6:22 pm, "edfialk" <edfi...@gmail. comwrote:

Hi, does anyone happen to know of a script that would return the
number of seconds in a month if I give it a month and a year?
>

something like this might work, it should event handle DST correctly.
You could read up on mktime() if you want to make sure.

from time import mktime
def secondsInMonth( year, month):
s1 = mktime((year,mo nth,1,0,0,0,0,0 ,-1))
s2 = mktime((year,mo nth+1,1,0,0,0,0 ,0,-1))
return s2-s1

/Matt

**skip@pobox.com** · Apr 16 '07, 05:25 PM

Re: script for seconds in given month?

Mattfrom time import mktime
Mattdef secondsInMonth( year, month):
Matt s1 = mktime((year,mo nth,1,0,0,0,0,0 ,-1))
Matt s2 = mktime((year,mo nth+1,1,0,0,0,0 ,0,-1))
Matt return s2-s1

Probably won't work if month==12. ;-)

Skip

**Paul McGuire** · Apr 16 '07, 05:35 PM

Re: script for seconds in given month?

On Apr 16, 11:22 am, "edfialk" <edfi...@gmail. comwrote:

Hi, does anyone happen to know of a script that would return the
number of seconds in a month if I give it a month and a year?
>
My python is a little weak, but if anyone could offer some suggestions
I think I could handle it myself, or if anyone happens to know of a
script already written that performs this I would be extremely
grateful.
>
Thanks!
-Ed

Do you need to handle leap seconds too? (not a joke)

-- Paul

**edfialk** · Apr 16 '07, 05:55 PM

Re: script for seconds in given month?

Jim: I need years too, basically from 1960-2000. Don't want to
hardcode all those days :)

Matt: Thanks, I will try this out.

Paul: I don't believe we need leap seconds. Leap days definitely.

I'll let you know how Matt's code works. Any other suggestions feel
free to let me know.

Thanks all!
-Ed

**attn.steven.kuo@gmail.com** · Apr 16 '07, 06:15 PM

Re: script for seconds in given month?

On Apr 16, 10:18 am, s...@pobox.com wrote:

Mattfrom time import mktime
Mattdef secondsInMonth( year, month):
Matt s1 = mktime((year,mo nth,1,0,0,0,0,0 ,-1))
Matt s2 = mktime((year,mo nth+1,1,0,0,0,0 ,0,-1))
Matt return s2-s1
>
Probably won't work if month==12. ;-)
>
Skip

Actually, mktime as described in the C Standard does not
restrict members such as tm_mon of struct tm to the
range 0-11 (1-12 for the corresponding entry in the
time tuple in Python). So the underlying struct in
CPython may be normalized and return a perfectly valid
time even if month is 12.

--
Regards,
Steven

**Shane Geiger** · Apr 16 '07, 07:45 PM

Re: script for seconds in given month?

import datetime

def first_day_of_ne xt_month( year, month ):
"""returns the first day of the next month

>>first_day_of_ next_month(2007 ,5)

datetime.dateti me(2007, 6, 1, 0, 0)

>>first_day_of_ next_month(2007 ,12)

datetime.dateti me(2008, 1, 1, 0, 0)
"""
oneday = datetime.timede lta(days=1)
day = datetime.dateti me(year, month, 1)
if day.day == 1:
day += oneday
while day.day != 1:
day += oneday
return day

from time import mktime
def secondsInMonth( year, month):
s1 = mktime((year,mo nth,1,0,0,0,0,0 ,-1))
day = first_day_of_ne xt_month(year, month)
year = day.year
month = day.month
s2 = mktime((year,mo nth+1,1,0,0,0,0 ,0,-1))
return s2-s1

year = 2007
month = 2
print secondsInMonth( year, month)

skip@pobox.com wrote:

Mattfrom time import mktime
Mattdef secondsInMonth( year, month):
Matt s1 = mktime((year,mo nth,1,0,0,0,0,0 ,-1))
Matt s2 = mktime((year,mo nth+1,1,0,0,0,0 ,0,-1))
Matt return s2-s1
>
Probably won't work if month==12. ;-)
>
Skip
>

--
Shane Geiger
IT Director
National Council on Economic Education
sgeiger@ncee.ne t | 402-438-8958 | http://www.ncee.net

Leading the Campaign for Economic and Financial Literacy

**Paul McGuire** · Apr 16 '07, 11:05 PM

Re: script for seconds in given month?

On Apr 16, 12:49 pm, "edfialk" <edfi...@gmail. comwrote:

Jim: I need years too, basically from 1960-2000. Don't want to
hardcode all those days :)
>
Matt: Thanks, I will try this out.
>
Paul: I don't believe we need leap seconds. Leap days definitely.
>
I'll let you know how Matt's code works. Any other suggestions feel
free to let me know.
>
Thanks all!
-Ed

I googled for "NIST leap second" and found this table online of leap
seconds, if you do in fact need them: http://tf.nist.gov/pubs/bulletin/leapsecond.htm

-- Paul

**Alex Martelli** · Apr 17 '07, 04:45 AM

Re: script for seconds in given month?

edfialk <edfialk@gmail. comwrote:

Hi, does anyone happen to know of a script that would return the
number of seconds in a month if I give it a month and a year?
>
My python is a little weak, but if anyone could offer some suggestions
I think I could handle it myself, or if anyone happens to know of a
script already written that performs this I would be extremely
grateful.

import calendar

def seconds_in_mont h(month, year):
nomatter, daysinmonth = calendar.monthr ange(year, month)
return daysinmonth * 24 * 60 * 60

Alex

**Hendrik van Rooyen** · Apr 17 '07, 06:05 AM

Re: script for seconds in given month?

"Paul McGuire" <pt...g@austin. rr.comwrote:

On Apr 16, 11:22 am, "edfialk" <edfi...@gmail. comwrote:

Hi, does anyone happen to know of a script that would return the
number of seconds in a month if I give it a month and a year?

My python is a little weak, but if anyone could offer some suggestions
I think I could handle it myself, or if anyone happens to know of a
script already written that performs this I would be extremely
grateful.

Thanks!
-Ed

>
Do you need to handle leap seconds too? (not a joke)
>
-- Paul

>From some assembler, here are some values.

Stick them in a two dicts for normal and leap year.
the first one is a cumulative table, I included it in
case you can use it...

; SECONDS TABLES (LITTLE ENDIAN)

MSECTAB_NORM:

DB 080H,033H,0E1H, 001H ;MONTH ZERO HAS FULL YEAR SECONDS
DB 000H,000H,000H, 000H ;JANUARY
DB 080H,0DEH,028H, 000H ;FEBRUARY
DB 080H,0C8H,04DH, 000H ;MARCH
DB 000H,0A7H,076H, 000H ;APRIL
DB 000H,034H,09EH, 000H ;MAY
DB 080H,012H,0C7H, 000H ;JUNE
DB 080H,09FH,0EEH, 000H ;JULY
DB 000H,07EH,017H, 001H ;AUGUST
DB 080H,05CH,040H, 001H ;SEPTEMBER
DB 080H,0E9H,067H, 001H ;OCTOBER
DB 000H,0C8H,090H, 001H ;NOVEMBER
DB 000H,055H,0B8H, 001H ;DECEMBER

MSECTAB_LEAP:

DB 000H,085H,0E2H, 001H ;MONTH ZERO HAS FULL LEAP YEAR SECONDS
DB 000H,000H,000H, 000H ;JANUARY
DB 080H,0DEH,028H, 000H ;FEBRUARY
DB 000H,01AH,04FH, 000H ;MARCH
DB 080H,0F8H,077H, 000H ;APRIL
DB 080H,085H,09FH, 000H ;MAY
DB 000H,064H,0C8H, 000H ;JUNE
DB 000H,0F1H,0EFH, 000H ;JULY
DB 080H,0CFH,018H, 001H ;AUGUST
DB 000H,0AEH,041H, 001H ;SEPTEMBER
DB 000H,03BH,069H, 001H ;OCTOBER
DB 080H,019H,092H, 001H ;NOVEMBER
DB 080H,0A6H,0B9H, 001H ;DECEMBER

; NUMBER OF SECONDS IN MONTH (LITTLE ENDIAN)

MSTAB_NORM:

DB 000H,000H,000H, 000H ;MONTH ZERO HAS NO SECONDS
DB 080H,0DEH,028H, 000H ;JANUARY
DB 000H,0EAH,024H, 000H ;FEBRUARY
DB 080H,0DEH,028H, 000H ;MARCH
DB 000H,08DH,027H, 000H ;APRIL
DB 080H,0DEH,028H, 000H ;MAY
DB 000H,08DH,027H, 000H ;JUNE
DB 080H,0DEH,028H, 000H ;JULY
DB 080H,0DEH,028H, 000H ;AUGUST
DB 000H,08DH,027H, 000H ;SEPTEMBER
DB 080H,0DEH,028H, 000H ;OCTOBER
DB 000H,08DH,027H, 000H ;NOVEMBER
DB 080H,0DEH,028H, 000H ;DECEMBER

MSTAB_LEAP:

DB 000H,000H,000H, 000H ;MONTH ZERO HAS NO SECONDS
DB 080H,0DEH,028H, 000H ;JANUARY
DB 080H,03BH,026H, 000H ;FEBRUARY
DB 080H,0DEH,028H, 000H ;MARCH
DB 000H,08DH,027H, 000H ;APRIL
DB 080H,0DEH,028H, 000H ;MAY
DB 000H,08DH,027H, 000H ;JUNE
DB 080H,0DEH,028H, 000H ;JULY
DB 080H,0DEH,028H, 000H ;AUGUST
DB 000H,08DH,027H, 000H ;SEPTEMBER
DB 080H,0DEH,028H, 000H ;OCTOBER
DB 000H,08DH,027H, 000H ;NOVEMBER
DB 080H,0DEH,028H, 000H ;DECEMBER

; *************** *************** *************** *************** *****

hth - Hendrik

**pythoncurious@gmail.com** · Apr 17 '07, 07:55 AM

Re: script for seconds in given month?

On Apr 17, 6:41 am, a...@mac.com (Alex Martelli) wrote:

edfialk <edfi...@gmail. comwrote:

Hi, does anyone happen to know of ascriptthat would return the
number ofsecondsin amonthif I give it amonthand a year?

>

My python is a little weak, but if anyone could offer some suggestions
I think I could handle it myself, or if anyone happens to know of a
scriptalready written that performs this I would be extremely
grateful.

>
import calendar
>
def seconds_in_mont h(month, year):
nomatter, daysinmonth = calendar.monthr ange(year,month )
return daysinmonth * 24 * 60 * 60
>
Alex

That works if you define the number of seconds in a month a the number
of days * 24 * 60 * 60.
If you have DST then that's not always the truth. The difference in
seconds (clock time) is according to your example, but the number of
seconds that passed during the month differs.
Not sure which one was requested in the original post though.

**pythoncurious@gmail.com** · Apr 17 '07, 07:55 AM

Re: script for seconds in given month?

On Apr 16, 7:49 pm, "edfialk" <edfi...@gmail. comwrote:

Jim: I need years too, basically from 1960-2000. Don't want to
hardcode all those days :)
>
Matt: Thanks, I will try this out.
>
Paul: I don't believe we need leapseconds. Leap days definitely.
>
I'll let you know how Matt's code works. Any other suggestions feel
free to let me know.
>
Thanks all!
-Ed

There's one thing I forgot to mention: mktime (like most things using
the standard C functions) will work reliably from 1970 to 2038 or so.
Also, I think posix explicitly says that leap seconds are ignored, so
those are not covered.

/Matt

**edfialk** · Apr 23 '07, 08:35 PM

Re: script for seconds in given month?

Alex, very nice. That should be good enough for me.
The rest of you as well, thanks for all the help.

I, unfortunately, failed to realize the actual platform the script is
for is IronPython. When trying to import calendar in IronPython, I
get:

SyntaxError: future feature is not defined: with_statement (c:
\Python25\Lib\c alendar.py, line 8)

so, incompatible. I have moved my question over to the IronPython
group, but if anyone is familiar with IronPython and knows how to
perform the same function, that's what I'm looking for now. :)

Thanks again!
-Ed

**Carsten Haese** · Apr 23 '07, 08:45 PM

Re: script for seconds in given month?

On Mon, 2007-04-23 at 13:28 -0700, edfialk wrote:

Alex, very nice. That should be good enough for me.
The rest of you as well, thanks for all the help.
>
I, unfortunately, failed to realize the actual platform the script is
for is IronPython. When trying to import calendar in IronPython, I
get:
>
SyntaxError: future feature is not defined: with_statement (c:
\Python25\Lib\c alendar.py, line 8)
>
so, incompatible. I have moved my question over to the IronPython
group, but if anyone is familiar with IronPython and knows how to
perform the same function, that's what I'm looking for now. :)

Try this on for size:

def seconds_in_mont h(mo,yr):
import datetime
start_date = datetime.date(y r,mo,1)
mo += 1
if mo==13: mo=1; yr += 1
end_date = datetime.date(y r,mo,1)
delta = end_date - start_date
return 24*60*60*delta. days

-Carsten

script for seconds in given month?

script for seconds in given month?

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