SimpleXMLRPCServer - revisited

[Jan Danielsson]

Hello all,

I want to be able to determine the IP address of the client making an
XMPRPC call.

I got the tip to use this:
-------------------------------
class RPCServer(Simpl eXMLRPCServer):

def _dispatch(self, method, params):
"""Extend dispatch, adding client info to some parameters."""
if method in ({my list of methods I needed client address}):
return SimpleXMLRPCSer ver._dispatch(s elf, method,
params+(self.cl ient_address,))
return SimpleXMLRPCSer ver._dispatch(s elf, method, params);
-------------------------------

But it complains that it can not find 'client_address '.

It may be relevant to point out that I am using this:

-------------------------------
class AsyncXMLRPCServ er(SocketServer .ThreadingMixIn ,SimpleXMLRPCSe rver):
pass
-------------------------------

If anyone has any hints or tips.. Please share them.

--
Kind regards,
Jan Danielsson