Finding and copying files with python.

[gtb]

I wish to copy the highest version number of a file from directory \
\
\fileserver\D:\ scripts to C:\scripts where the file names are of the
form

filename_MM.NN. SS.zip, where MM, NN, and SS can be one to three
digits.

Example directory:
other.zip
dx_ver_1.1.63.z ip
dx_ver_1.2.01.z ip
dx_ver_1.12.7.z ip
temp.txt


Does python have string matching routines that would find the bottom
listed zip file and/or file copying routines?

A little pointer or two would be much appreciated.

Thanks,

jh

[oliver@obeattie.com]

Re: Finding and copying files with python.

Just sort them and then select the bottom one from a list by using a
negative indices. I.e.:

list[-1]

Would return the bottom result out of a list

On Apr 3, 2:21 pm, "gtb" <goodTweetieB.. .@hotmail.comwr ote:

I wish to copy the highest version number of a file from directory \
\
\fileserver\D:\ scripts to C:\scripts where the file names are of the
form
>
filename_MM.NN. SS.zip, where MM, NN, and SS can be one to three
digits.
>
Example directory:
other.zip
dx_ver_1.1.63.z ip
dx_ver_1.2.01.z ip
dx_ver_1.12.7.z ip
temp.txt
>
Does python have string matching routines that would find the bottom
listed zip file and/or file copying routines?
>
A little pointer or two would be much appreciated.
>
Thanks,
>
jh

[kyosohma@gmail.com]

Re: Finding and copying files with python.

On Apr 3, 8:21 am, "gtb" <goodTweetieB.. .@hotmail.comwr ote:

I wish to copy the highest version number of a file from directory \
\
\fileserver\D:\ scripts to C:\scripts where the file names are of the
form
>
filename_MM.NN. SS.zip, where MM, NN, and SS can be one to three
digits.
>
Example directory:
other.zip
dx_ver_1.1.63.z ip
dx_ver_1.2.01.z ip
dx_ver_1.12.7.z ip
temp.txt
>
Does python have string matching routines that would find the bottom
listed zip file and/or file copying routines?
>
A little pointer or two would be much appreciated.
>
Thanks,
>
jh

You could just use string slicing to cut off the first 7 characters
and have the numbers available to compare. There's also the os.stat
module to find the last modified date of the file. You might be able
to use the glob module to grab a list of the files and then sort the
list too.

Mike

[gtb]

Re: Finding and copying files with python.

On Apr 3, 8:31 am, kyoso...@gmail. com wrote:

On Apr 3, 8:21 am, "gtb" <goodTweetieB.. .@hotmail.comwr ote:
>
>
>
>
>
>
>

I wish to copy the highest version number of a file from directory \
\
\fileserver\D:\ scripts to C:\scripts where the file names are of the
form

>

filename_MM.NN. SS.zip, where MM, NN, and SS can be one to three
digits.

>

Example directory:
other.zip
dx_ver_1.1.63.z ip
dx_ver_1.2.01.z ip
dx_ver_1.12.7.z ip
temp.txt

>

Does python have string matching routines that would find the bottom
listed zip file and/or file copying routines?

>

A little pointer or two would be much appreciated.

>

Thanks,

>

jh

>
You could just use string slicing to cut off the first 7 characters
and have the numbers available to compare. There's also the os.stat
module to find the last modified date of the file. You might be able
to use the glob module to grab a list of the files and then sort the
list too.
>
Mike

Thanks for posting folks. I didn't make my question clear. Before I
sort the files I need to ensure that I am only sorting the files that
match the profile of "filename_MM.NN .SS.zip", where MM, NN, and SS can
be one to three
digits.

Thanks again,

jh

[kyosohma@gmail.com]

Re: Finding and copying files with python.

On Apr 3, 8:47 am, "gtb" <goodTweetieB.. .@hotmail.comwr ote:

On Apr 3, 8:31 am, kyoso...@gmail. com wrote:
>
>
>

On Apr 3, 8:21 am, "gtb" <goodTweetieB.. .@hotmail.comwr ote:

>

I wish to copy the highest version number of a file from directory \
\
\fileserver\D:\ scripts to C:\scripts where the file names are of the
form

>

filename_MM.NN. SS.zip, where MM, NN, and SS can be one to three
digits.

>

Example directory:
other.zip
dx_ver_1.1.63.z ip
dx_ver_1.2.01.z ip
dx_ver_1.12.7.z ip
temp.txt

>

Does python have string matching routines that would find the bottom
listed zip file and/or file copying routines?

>

A little pointer or two would be much appreciated.

>

Thanks,

>

jh

>

You could just use string slicing to cut off the first 7 characters
and have the numbers available to compare. There's also the os.stat
module to find the last modified date of the file. You might be able
to use the glob module to grab a list of the files and then sort the
list too.

>

Mike

>
Thanks for posting folks. I didn't make my question clear. Before I
sort the files I need to ensure that I am only sorting the files that
match the profile of "filename_MM.NN .SS.zip", where MM, NN, and SS can
be one to three
digits.
>
Thanks again,
>
jh

Then you probably need to use the glob module and the re module. You
may even be able to just use the glob module by doing something like:

filenames = glob.glob(r'pat htofiles\*.*.*. *.zip')

and then sort that.

Mike

[Steve Holden]

Re: Finding and copying files with python.

gtb wrote:

On Apr 3, 8:31 am, kyoso...@gmail. com wrote:

>On Apr 3, 8:21 am, "gtb" <goodTweetieB.. .@hotmail.comwr ote:
>>
>>
>>
>>
>>
>>
>>

>>I wish to copy the highest version number of a file from directory \
>>\
>>\fileserver\D :\scripts to C:\scripts where the file names are of the
>>form
>>filename_MM.N N.SS.zip, where MM, NN, and SS can be one to three
>>digits.
>>Example directory:
>>other.zip
>>dx_ver_1.1.63 .zip
>>dx_ver_1.2.01 .zip
>>dx_ver_1.12.7 .zip
>>temp.txt
>>Does python have string matching routines that would find the bottom
>>listed zip file and/or file copying routines?
>>A little pointer or two would be much appreciated.
>>Thanks,
>>jh

>You could just use string slicing to cut off the first 7 characters
>and have the numbers available to compare. There's also the os.stat
>module to find the last modified date of the file. You might be able
>to use the glob module to grab a list of the files and then sort the
>list too.
>>
>Mike

>
Thanks for posting folks. I didn't make my question clear. Before I
sort the files I need to ensure that I am only sorting the files that
match the profile of "filename_MM.NN .SS.zip", where MM, NN, and SS can
be one to three
digits.
>
Thanks again,
>
jh
>

OK, well look at the glob module to get a list of the filenames.

You are going to have to be careful doing the sort, however, because a
simple string comparison won't work for numbers of differing lengths.

One way would be to define a function that extracts the numeric
components from a filename and produces a three-element tuple or list.
Then pass this function to sort() as the "key" argument.

regards
Steve
--
Steve Holden +44 150 684 7255 +1 800 494 3119
Holden Web LLC/Ltd http://www.holdenweb.com
Skype: holdenweb http://del.icio.us/steve.holden
Recent Ramblings http://holdenweb.blogspot.com

[Daniele Varrazzo]

Re: Finding and copying files with python.

I wish to copy the highest version number of a file from directory \

\
\fileserver\D:\ scripts to C:\scripts where the file names are of the
form

>

filename_MM.NN. SS.zip, where MM, NN, and SS can be one to three
digits.

>

Example directory:
other.zip
dx_ver_1.1.63.z ip
dx_ver_1.2.01.z ip
dx_ver_1.12.7.z ip
temp.txt

>

Does python have string matching routines that would find the bottom
listed zip file and/or file copying routines?

You could just use string slicing to cut off the first 7 characters
and have the numbers available to compare. There's also the os.stat
module to find the last modified date of the file. You might be able
to use the glob module to grab a list of the files and then sort the
list too.

Comparing the version strings is not enough: you have to convert the
parts into integers, because else:

>>"dx_ver_1.12. 7.zip" < "dx_ver_1.2.1.z ip"

True

Thanks for posting folks. I didn't make my question clear. Before I
sort the files I need to ensure that I am only sorting the files that
match the profile of "filename_MM.NN .SS.zip", where MM, NN, and SS can
be one to three
digits.

Match the file names against the pattern "dx_ver_(\d+).( \d+).(\d
+).zip". You may also use the glob function, but then you will have to
parse the version number from the file name anyway: with the regexp
you can use match.groups() to get the version number.

You can do:

import re
ver_re = re.compile(r"dx _ver_(\d+).(\d+ ).(\d+).zip")

def getVer(fn):
"""Return a *comparable* file version, None for bad file names"""
m = ver_re.match(fn )
return m and map(int, m.groups())

print sorted(os.listd ir('/path/to/wherever'), key=getVer)[-1]

--Daniele

P.S. I guess in Obfuscated Python one would write something like:

>>print sorted((pair for pair in ((re.match(r"dx _ver_(\d+).(\d+ ).(\d+).zip", fn), fn) for fn in os.listdir('/path/to/wherever')) if pair[0]), key=lambda _: map(int, _[0].groups()))[-1][1]

dx_ver_1.12.7.z ip

[gtb]

Re: Finding and copying files with python.

On Apr 3, 9:42 am, "Daniele Varrazzo" <daniele.varra. ..@gmail.com>
wrote:

I wish to copy the highest version number of a file from directory \
\
\fileserver\D:\ scripts to C:\scripts where the file names are of the
form

>

filename_MM.NN. SS.zip, where MM, NN, and SS can be one to three
digits.

>

Example directory:
other.zip
dx_ver_1.1.63.z ip
dx_ver_1.2.01.z ip
dx_ver_1.12.7.z ip
temp.txt

>

Does python have string matching routines that would find the bottom
listed zip file and/or file copying routines?
You could just use string slicing to cut off the first 7 characters
and have the numbers available to compare. There's also the os.stat
module to find the last modified date of the file. You might be able
to use the glob module to grab a list of the files and then sort the
list too.

>
Comparing the version strings is not enough: you have to convert the
parts into integers, because else:
>

>"dx_ver_1.12.7 .zip" < "dx_ver_1.2.1.z ip"

>
True
>

Thanks for posting folks. I didn't make my question clear. Before I
sort the files I need to ensure that I am only sorting the files that
match the profile of "filename_MM.NN .SS.zip", where MM, NN, and SS can
be one to three
digits.

>
Match the file names against the pattern "dx_ver_(\d+).( \d+).(\d
+).zip". You may also use the glob function, but then you will have to
parse the version number from the file name anyway: with the regexp
you can use match.groups() to get the version number.
>
You can do:
>
import re
ver_re = re.compile(r"dx _ver_(\d+).(\d+ ).(\d+).zip")
>
def getVer(fn):
"""Return a *comparable* file version, None for bad file names"""
m = ver_re.match(fn )
return m and map(int, m.groups())
>
print sorted(os.listd ir('/path/to/wherever'), key=getVer)[-1]
>
--Daniele
>
P.S. I guess in Obfuscated Python one would write something like:
>

>print sorted((pair for pair in ((re.match(r"dx _ver_(\d+).(\d+ ).(\d+).zip", fn), fn) for fn in os.listdir('/path/to/wherever')) if pair[0]), key=lambda _: map(int, _[0].groups()))[-1][1]

>
dx_ver_1.12.7.z ip

Thanks all. Much to learn, but you have certainly helped me get
started.

jh