Question about recurssion

**bvdet** · Apr 2 '07, 09:27 PM

Originally posted by Deathwing

Hi everyone,

I have just programmed a very very simple calculator program, I am actually rather pleased. I would just like to know how I can make it so that every time the user has entered their input and an output has been returned by the program, the program jumps back to the start and ask the user to choose another option. Here is the code for my very very simple calculator program.

Code:

# my first very simple calculator
# this program only does basic arithmatic

print\
    """
                              #-------------#
                              # MYCALC 1.0  #
                              #-------------#

WELCOME TO MYCALC 1.0 This is a command line program that you can use
as a calculator just incase you don't have one installed on your
desk top. Using it is pretty self explanitory.
    """
print " You have the following options:\n"
options = ('addition = 1','subtraction = 2', 'division = 3', 'multiplication = 4',)

print "\nHere are ur options:\n", options


choice = int(raw_input("Plese enter your operation choice: "))

if choice == 1:
    a = int(raw_input("enter value a: "))
    b = int(raw_input("enter value b: "))
    total = a+b
    print "\nThe total is:", total


elif choice == 2:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a-b
    print "\nThe total is:", total

    
elif choice == 3:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a/b
    print "\nThe total is:", total
  

elif choice == 4:
    a = int(raw_input("\nenter value a: "))
    b = int(raw_input("\nenter value b: "))
    total = a*b
    print "\nThe total is:", total

else:
    print "\nYour choice is invalid"

        

raw_input("\nPres enter to exit.")

Thanks, -Deathwing

You do not need recursion - you need a while loop:

Code:

# my first very simple calculator
# this program only does basic arithmatic

print\
    """
                              #-------------#
                              # MYCALC 1.0  #
                              #-------------#

WELCOME TO MYCALC 1.0 This is a command line program that you can use
as a calculator just incase you don't have one installed on your
desk top. Using it is pretty self explanitory.
    """
print " You have the following options:\n"
options = ('addition = 1','subtraction = 2', 'division = 3', 'multiplication = 4', 'exit = 5')

print "\nHere are ur options:\n", options

while True:
    choice = int(raw_input("Plese enter your operation choice: "))

    if choice == 1:
        a = int(raw_input("enter value a: "))
        b = int(raw_input("enter value b: "))
        total = a+b
        print "\nThe total is:", total


    elif choice == 2:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a-b
        print "\nThe total is:", total

        
    elif choice == 3:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a/b
        print "\nThe total is:", total
      

    elif choice == 4:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a*b
        print "\nThe total is:", total

    elif choice == 5:
        break

    else:
        print "\nYour choice is invalid"

raw_input("\nPress enter to exit.")

If the user enters '5', the code 'breaks' out of the loop.

**Deathwing** · Apr 2 '07, 09:33 PM

Originally posted by bvdet

You do not need recursion - you need a while loop:

Code:

# my first very simple calculator
# this program only does basic arithmatic

print\
    """
                              #-------------#
                              # MYCALC 1.0  #
                              #-------------#

WELCOME TO MYCALC 1.0 This is a command line program that you can use
as a calculator just incase you don't have one installed on your
desk top. Using it is pretty self explanitory.
    """
print " You have the following options:\n"
options = ('addition = 1','subtraction = 2', 'division = 3', 'multiplication = 4', 'exit = 5')

print "\nHere are ur options:\n", options

while True:
    choice = int(raw_input("Plese enter your operation choice: "))

    if choice == 1:
        a = int(raw_input("enter value a: "))
        b = int(raw_input("enter value b: "))
        total = a+b
        print "\nThe total is:", total


    elif choice == 2:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a-b
        print "\nThe total is:", total

        
    elif choice == 3:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a/b
        print "\nThe total is:", total
      

    elif choice == 4:
        a = int(raw_input("\nenter value a: "))
        b = int(raw_input("\nenter value b: "))
        total = a*b
        print "\nThe total is:", total

    elif choice == 5:
        break

    else:
        print "\nYour choice is invalid"

raw_input("\nPress enter to exit.")

If the user enters '5', the code 'breaks' out of the loop.

ah... ic ic okay, I'll take a look and see what happens gracias.

Question about recurssion

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