Overlapping matches

[Rehceb Rotkiv]

In the re documentation, it says that the matching functions return "non-
overlapping" matches only, but I also need overlapping ones. Does anyone
know how this can be done?

Regards,
Rehceb Rotkiv

[Ant]

Re: Overlapping matches

On Apr 1, 9:38 pm, Rehceb Rotkiv <reh...@no.spam .plzwrote:

In the re documentation, it says that the matching functions return "non-
overlapping" matches only, but I also need overlapping ones. Does anyone
know how this can be done?

Something like the following:

import re

s = "oooooooo"
p = re.compile("oo" )
out = []

while pos < endpos:
m = p.search(s, pos)
if not m:
break
out.append(m)
pos = m.start() + 1

[attn.steven.kuo@gmail.com]

Re: Overlapping matches

On Apr 1, 1:38 pm, Rehceb Rotkiv <reh...@no.spam .plzwrote:

In the re documentation, it says that the matching functions return "non-
overlapping" matches only, but I also need overlapping ones. Does anyone
know how this can be done?

Perhaps lookahead assertions are what you're
looking for?

import re
import string

non_overlap = re.compile(r'[0-9a-fA-F]{2}')
pairs = [ match.group(0) for match in
non_overlap.fin diter(string.he xdigits) ]
print pairs

overlap = re.compile(r'[0-9a-fA-F](?=([0-9a-fA-F]))')
pairs = [ match.group(0) + match.group(1) for match in
overlap.findite r(string.hexdig its) ]
print pairs

--
Hope this helps,
Steven

[Rehceb Rotkiv]

Re: Overlapping matches

Both methods work well, thank you!