Creating a standard log file that is accessible by all other files

[indiarocks]

Just a basic question, I want to create a standard log file API and want that API to be shared by all my other python files.
For eg. I have file1 which creates a file handle and hands it over to say log.py

Now say I have file2, and it needs to write into the same log file, how do I achieve this and what is the best way of doing it ?

-------
File1:
--------

log_file = file('out.log',"w")
log_obj = log.log(log_file)

log_obj.write("Hello world from File 1") 

----------
log.py 
----------
class log:
      def __init__(self,log):
         self.log = log 
       def write(self,message):
            self.log.write(message)
----------
File 2: 
----------

from log import * 
log.write("message from file2")

This obviously will not work because I am passing a str object instead of log instance.

Any tips ?

[indiarocks]

Tried implementing the following method and it seems to work. Not sure if it's a good way to do it.

<code>

file1.py 
# Declare a global list which can be accessible by other files 
log_list = []

def func1():
   global log_list 
   log_file = file('abc.out',"w")
   log_list.append(log_file)

</code>

<code> 
File2.py 
import log 
import file1 

file1.func1() 
log.write("Hello World ")
</code> 

<code> 
log.py 
from g import log_list 

def write(message):
       log_list[0].write(message) 
</code>

So basically what happens is that when you run file2, file1 creates a log file which can be shared by other files. This one worked because log_list is a list which is mutable and that is imported by log.py. I thought that even log file handlers where mutable, but that didn't work for some reason. And putting that log_file handle within a list seemed to solve the issue.

[bvdet]

Tried implementing the following method and it seems to work. Not sure if it's a good way to do it.

<code>

file1.py
# Declare a global list which can be accessible by other files
log_list = []

def func1():
global log_list
log_file = file('abc.out', "w")
log_list.append (log_file)

</code>

<code>
File2.py
import log
import file1

file1.func1()
log.write("Hell o World ")
</code>

<code>
log.py
from g import log_list

def write(message):
log_list[0].write(message)
</code>

So basically what happens is that when you run file2, file1 creates a log file which can be shared by other files. This one worked because log_list is a list which is mutable and that is imported by log.py. I thought that even log file handlers where mutable, but that didn't work for some reason. And putting that log_file handle within a list seemed to solve the issue.

I see you are trying to use code tags. Good, except use square brackets '[ ]' instead of '< >'.

Why not:

# file1.py

log_file_name = r'H:\TEMP\log.txt'

............................................................


# log_file.py

import file1

# open log file
f = open(file1.log_file_name, 'a')
.............................................

[ghostdog74]

actually you don't to create your own. Python has a logger module. Unless of course, you have other requirements.

[indiarocks]

I see you are trying to use code tags. Good, except use square brackets '[ ]' instead of '< >'.

Why not:

# file1.py

log_file_name = r'H:\TEMP\log.txt'

............................................................


# log_file.py

import file1

# open log file
f = open(file1.log_file_name, 'a')
.............................................

In this case if I have my program spread across 15 files, I need to explicitly open each of the files in these 15 files. To avoid that I created a general log function which can be imported by other files and they can directly use as log(msg)

[bvdet]

In this case if I have my program spread across 15 files, I need to explicitly open each of the files in these 15 files. To avoid that I created a general log function which can be imported by other files and they can directly use as log(msg)

Gotcha. For some reason I thought you were just needing the file name. Is it working well?

[bartonc]

In this case if I have my program spread across 15 files, I need to explicitly open each of the files in these 15 files. To avoid that I created a general log function which can be imported by other files and they can directly use as log(msg)

They're called 'tags', so (if you know HTML) in makes sense to use
<code>
</code>
But on this site, we use [CODE] and the next one has the forward slash (but if I put it here it will disappear. You can use the # button at the top of the editor.

[indiarocks]

Gotcha. For some reason I thought you were just needing the file name. Is it working well?

Yeah, seems to be working well.

Thanks