using regexp

[s99999999s2003@yahoo.com]

hi
how can i use regexp to group these digits into groups of 3?

eg
line 123456789123456 789

i have :

pat = re.compile("lin e\s+(\d{3})" , re.M|re.DOTALL)

but this only gives the first 3. I also tried

"line\s+(\d{3}) +"
but also not working.
I need output to be ['123' ,'456','789', '123','456','78 9', .....]
thanks.

[Shane Geiger]

Re: using regexp

You don't even need regex.

def
split_seq(seq,s ize):

# this is sort of the inverse of
flatten

# Source:

http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/425044

return [seq[i:i+size] for i in range(0, len(seq),
size)]



line =
'12345678912345 6789'



print
split_seq(line, 3)



Will that work for you?



s99999999s2003@ yahoo.com wrote:

hi
how can i use regexp to group these digits into groups of 3?
>
eg
line 123456789123456 789
>
i have :
>
pat = re.compile("lin e\s+(\d{3})" , re.M|re.DOTALL)
>
but this only gives the first 3. I also tried
>
"line\s+(\d{3}) +"
but also not working.
I need output to be ['123' ,'456','789', '123','456','78 9', .....]
thanks.
>
>

--
Shane Geiger
IT Director
National Council on Economic Education
sgeiger@ncee.ne t | 402-438-8958 | http://www.ncee.net

Leading the Campaign for Economic and Financial Literacy

[Shane Geiger]

Re: using regexp


import re
line = '12345678912345 6789'
print re.findall('([0-9]{3})', line)



Shane Geiger wrote:

You don't even need regex.
>
def
split_seq(seq,s ize):
>
# this is sort of the inverse of
flatten
>
# Source:

http://aspn.activestate.com/ASPN/Cookbook/Python/Recipe/425044

>
return [seq[i:i+size] for i in range(0, len(seq),
size)]
>
>
>
line =
'12345678912345 6789'
>
>
>
print
split_seq(line, 3)
>
>
>
Will that work for you?
>
>
>
s99999999s2003@ yahoo.com wrote:

>hi
>how can i use regexp to group these digits into groups of 3?
>>
>eg
>line 123456789123456 789
>>
>i have :
>>
>pat = re.compile("lin e\s+(\d{3})" , re.M|re.DOTALL)
>>
>but this only gives the first 3. I also tried
>>
>"line\s+(\d{3} )+"
>but also not working.
>I need output to be ['123' ,'456','789', '123','456','78 9', .....]
>thanks.
>>
>>

>

--
Shane Geiger
IT Director
National Council on Economic Education
sgeiger@ncee.ne t | 402-438-8958 | http://www.ncee.net

Leading the Campaign for Economic and Financial Literacy

[s99999999s2003@yahoo.com]

Re: using regexp

On Mar 20, 1:57 pm, Shane Geiger <sgei...@ncee.n etwrote:

import re
line = '12345678912345 6789'
print re.findall('([0-9]{3})', line)
>
>
>
Shane Geiger wrote:

You don't even need regex.

>

def
split_seq(seq,s ize):

>

# this is sort of the inverse of
flatten

>

# Source:
http://aspn.activestate.com/ASPN/Coo.../Recipe/425044

>

return [seq[i:i+size] for i in range(0, len(seq),
size)]

>

line =
'12345678912345 6789'

>

print
split_seq(line, 3)

>

Will that work for you?

>

s99999999s2...@ yahoo.com wrote:

hi
how can i use regexp to group these digits into groups of 3?

>

eg
line 123456789123456 789

>

i have :

>

pat = re.compile("lin e\s+(\d{3})" , re.M|re.DOTALL)

>

but this only gives the first 3. I also tried

>

"line\s+(\d{3}) +"
but also not working.
I need output to be ['123' ,'456','789', '123','456','78 9', .....]
thanks.

>
--
Shane Geiger
IT Director
National Council on Economic Education
sgei...@ncee.ne t | 402-438-8958 | http://www.ncee.net
>
Leading the Campaign for Economic and Financial Literacy
>
sgeiger.vcf
1KDownload

hi
thanks.
I know it can be done without regexp, but its just for learning
purpose, i want to use regexp
eg
someword 123456789123456 789 #this is a line of a file. 'someword' is a
word before the digits
I need to get the digits into groups of 3 based on whether i found
'someword'.
so i use this pattern :
"someword\s+(\d {3})"
but this will on give me the first 3. I need to group them all.
hope i explain it clearly.

[attn.steven.kuo@gmail.com]

Re: using regexp

On Mar 19, 10:33 pm, s99999999s2...@ yahoo.com wrote:

hi
how can i use regexp to group these digits into groups of 3?
>
eg
line 123456789123456 789
>
i have :
>
pat = re.compile("lin e\s+(\d{3})" , re.M|re.DOTALL)
>
but this only gives the first 3. I also tried
>
"line\s+(\d{3}) +"
but also not working.
I need output to be ['123' ,'456','789', '123','456','78 9', .....]
thanks.

Try:

import re

target_string = """not 123456789 but
try this line 987654321"""

try:
digits = re.compile(r'li ne\s+(\d
+)').search(tar get_string).gro up(1)
except AttributeError:
digits = ''

three_at_a_time = re.compile(r'\d {3}').findall(d igits)
print three_at_a_time

--
Hope this helps,
Steven