type classobj not defined?

[Wesley Brooks]

Dear Users,

I'm in the process of adding assert statements to a large piece of
code to aid with bug hunting and came across the following issue;

Using python in a terminal window you can do the following:

>type(False) == bool

True

I would like to check that an object is a class, here's an example:

>class b:

.....def __init__(self):
.........self.c = 1
.....def d(self):
.........print self.c

>type(b)

<type 'classobj'>

But the following fails:

>type(b) == classobj

Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'classobj' is not defined

For the time being I'll use b.__name__ == b to ensure I'm getting the
right class. Is there a reason why the other types such as bool are
defined but classobj isn't?

I'm running the following version of python:

Python 2.4.3 (#1, Jun 13 2006, 11:46:08)
[GCC 4.1.1 20060525 (Red Hat 4.1.1-1)] on linux2

Cheers,

Wesley Brooks

[Peter Otten]

Re: type classobj not defined?

Wesley Brooks wrote:

Dear Users,
>
I'm in the process of adding assert statements to a large piece of
code to aid with bug hunting and came across the following issue;
>
Using python in a terminal window you can do the following:
>

>>type(False) == bool

True
>
I would like to check that an object is a class, here's an example:
>

>>class b:

....def __init__(self):
........self.c = 1
....def d(self):
........print self.c
>

>>type(b)

<type 'classobj'>
>
But the following fails:
>

>>type(b) == classobj

Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'classobj' is not defined
>
For the time being I'll use b.__name__ == b to ensure I'm getting the
right class. Is there a reason why the other types such as bool are
defined but classobj isn't?

No idea. You can easily define it yourself, though:

>>class Classic: pass

....

>>classobj = type(Classic)
>>isinstance(Cl assic, classobj)

True

Note that "newstyle" classes (those deriving from object) are of type
'type', not 'classobj':

>>class Newstyle(object ): pass

....

>>isinstance(Ne wstyle, classobj)

False

>>isinstance(Ne wstyle, (classobj, type))

True

The inspect module wraps the functionality in a function:

>>import inspect
>>inspect.iscla ss(Newstyle)

True

>>inspect.iscla ss(Classic)

True

Peter

[=?ISO-8859-1?Q?=22Martin_v=2E_L=F6wis=22?=]

Re: type classobj not defined?

Wesley Brooks schrieb:

>type(b) == classobj

Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'classobj' is not defined
>
For the time being I'll use b.__name__ == b to ensure I'm getting the
right class. Is there a reason why the other types such as bool are
defined but classobj isn't?

In general, only those types which you also use as constructors are
builtin. I.e. you would write bool(foo) (where foo is a variable),
but you would not write classobj("bar") (to create a class named
"bar"). That you can also use it for a type test is a side-effect.

Some more types are available in the types module. In this case,
you can use types. In this case, types.ClassType would do the trick.

Regards,
Martin

[Denis Kasak]

Re: type classobj not defined?

Wesley Brooks wrote:

Dear Users,
>
I'm in the process of adding assert statements to a large piece of
code to aid with bug hunting and came across the following issue;
>
Using python in a terminal window you can do the following:
>

>type(False) == bool

True
>
I would like to check that an object is a class, here's an example:
>

>class b:

....def __init__(self):
........self.c = 1
....def d(self):
........print self.c
>

>type(b)

<type 'classobj'>
>
But the following fails:
>

>type(b) == classobj

Traceback (most recent call last):
File "<stdin>", line 1, in ?
NameError: name 'classobj' is not defined

You can compare it against the ClassType object located in the types module.

import types
class b:

.....def __init__(self):
.........self.c = 1
.....def d(self):
.........print self.c

type(b) == types.ClassType

True

--
Denis Kasak