Avoiding "invalid literal for int()" exception

[aine_canby@yahoo.com]

>>v = raw_input("Ente r: ")
Enter: kjjkj

>>int(v)

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: 'kjjkj'

In my program I need to be able to enter char strings or int strings on
the command line. Then I use an if-elif structure to establish which is
which. For example -

if uniList[0].lower() in ("e","exit") : # uniList stores a unicode
string origionally taken from stdin
return
elif uniList[0].lower() in ("h","help") :
verb.PrintVerb( )
elif uniList[0].lower() in ("p","pass") :
break
elif int(uniList[0]) in range(0,10):
verb.SetImporta nce(int(uniList[0]))
break
else:
verb.AddNewVerb ((uniList[0])

How could I avoid the ValueError exception if uniList[0] == "Åker"? I
was thinking of having something like -

formatError = False
try:
iVal = int(uniList[0])
if iVal not in range range(0,10):
formatError = True
catch ValueError:
iVal = -1

if uniList[0].lower() in ("e","exit") : # uniList stores a unicode
string origionally taken from stdin
return
elif uniList[0].lower() in ("h","help") :
verb.PrintVerb( )
elif uniList[0].lower() in ("p","pass") :
break
elif iVal != -1 and not formatError:
verb.SetImporta nce(iVal)
break
elif not formatError:
verb.VerbEntere d((uniList[0])
else:
print "Enter numbers between 0 and 10..."

Is this the correct way to do this in your opinion? Sorry, I'm totally
new to python and exceptions.

Thanks,

Aine.

[Marc 'BlackJack' Rintsch]

Re: Avoiding &quot;invali d literal for int()&quot; exception

In <1165832540.392 387.240550@j72g 2000cwa.googleg roups.com>, aine_canby
wrote:

elif uniList[0].lower() in ("p","pass") :
break
elif int(uniList[0]) in range(0,10):

Replace this line with:

elif uniList[0].isdigit() and 0 <= int(uniList[0]) < 10:

verb.SetImporta nce(int(uniList[0]))
break
else:
verb.AddNewVerb ((uniList[0])

You may want to give `uniList[0]` a name before entering the
``if``/``elif`` construct to avoid accessing the first element over and
over.

Ciao,
Marc 'BlackJack' Rintsch

[John Machin]

Re: Avoiding &quot;invali d literal for int()&quot; exception


aine_canby@yaho o.com wrote:

>v = raw_input("Ente r: ")

Enter: kjjkj

>int(v)

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: 'kjjkj'
>
In my program I need to be able to enter char strings or int strings on
the command line. Then I use an if-elif structure to establish which is
which. For example -
>
if uniList[0].lower() in ("e","exit") : # uniList stores a unicode
string origionally taken from stdin
return
elif uniList[0].lower() in ("h","help") :
verb.PrintVerb( )
elif uniList[0].lower() in ("p","pass") :
break
elif int(uniList[0]) in range(0,10):
verb.SetImporta nce(int(uniList[0]))
break
else:
verb.AddNewVerb ((uniList[0])
>
How could I avoid the ValueError exception if uniList[0] == "Åker"?I
was thinking of having something like -
>
formatError = False
try:
iVal = int(uniList[0])
if iVal not in range range(0,10):
formatError = True
catch ValueError:

Perhaps you meant
except ValueError:
:-)

iVal = -1
>

Consider using uniList[0].isdigit() -- see

http://docs.python.org/lib/string-methods.html

HTH,
John

[aine_canby@yahoo.com]

Re: Avoiding &quot;invali d literal for int()&quot; exception


John Machin skrev:

aine_canby@yaho o.com wrote:

>>v = raw_input("Ente r: ")

Enter: kjjkj

>>int(v)

Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: 'kjjkj'

In my program I need to be able to enter char strings or int strings on
the command line. Then I use an if-elif structure to establish which is
which. For example -

if uniList[0].lower() in ("e","exit") : # uniList stores a unicode
string origionally taken from stdin
return
elif uniList[0].lower() in ("h","help") :
verb.PrintVerb( )
elif uniList[0].lower() in ("p","pass") :
break
elif int(uniList[0]) in range(0,10):
verb.SetImporta nce(int(uniList[0]))
break
else:
verb.AddNewVerb ((uniList[0])

How could I avoid the ValueError exception if uniList[0] == "Åker"? I
was thinking of having something like -

formatError = False
try:
iVal = int(uniList[0])
if iVal not in range range(0,10):
formatError = True
catch ValueError:

>
Perhaps you meant
except ValueError:
:-)
>
>

iVal = -1

>
Consider using uniList[0].isdigit() -- see

http://docs.python.org/lib/string-methods.html

HTH,
John

Yes, thanks for your help.

[Gabriel Genellina]

Re: Avoiding &quot;invali d literal for int()&quot; exception

At Monday 11/12/2006 07:22, aine_canby@yaho o.com wrote:

>elif int(uniList[0]) in range(0,10):

Either of these will work to avoid an unneeded conversion:

elif uniList[0] in "0123456789 ":

elif uniList[0] in string.digits:

elif uniList[0].isdigit():


--
Gabriel Genellina
Softlab SRL

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[Marc 'BlackJack' Rintsch]

Re: Avoiding &quot;invali d literal for int()&quot; exception

In <mailman.1415.1 165879866.32031 .python-list@python.org >, Gabriel
Genellina wrote:

At Monday 11/12/2006 07:22, aine_canby@yaho o.com wrote:
>

>>elif int(uniList[0]) in range(0,10):

>
Either of these will work to avoid an unneeded conversion:
>
elif uniList[0] in "0123456789 ":
>
elif uniList[0] in string.digits:
>
elif uniList[0].isdigit():

The last does not work. Not only that it accepts numbers greater than 9
because it checks if the whole string consists of digits, it also accepts
u'²₂' and other unicode digits.

Ciao,
Marc 'BlackJack' Rintsch

[Peter Otten]

Re: Avoiding &quot;invali d literal for int()&quot; exception

Marc 'BlackJack' Rintsch wrote:

In <mailman.1415.1 165879866.32031 .python-list@python.org >, Gabriel
Genellina wrote:
>

>At Monday 11/12/2006 07:22, aine_canby@yaho o.com wrote:
>>

>>>elif int(uniList[0]) in range(0,10):

>>
>Either of these will work to avoid an unneeded conversion:
>>
>elif uniList[0] in "0123456789 ":
>>
>elif uniList[0] in string.digits:
>>
>elif uniList[0].isdigit():

>
The last does not work. Not only that it accepts numbers greater than 9
because it checks if the whole string consists of digits, it also accepts
u'²?' and other unicode digits.

By the way, if you require an implicit 0 <= int(s) < 10 check, none of the
above work with the newer Pythons:

>>s = "23"
>>s in "0123456789 "

True

>>s in set("0123456789 ")

False

Peter

[Gabriel Genellina]

Re: Avoiding &quot;invali d literal for int()&quot; exception

Marc 'BlackJack' Rintsch ha escrito:

In <mailman.1415.1 165879866.32031 .python-list@python.org >, Gabriel
Genellina wrote:
>

elif uniList[0].isdigit():

>
The last does not work. Not only that it accepts numbers greater than 9
because it checks if the whole string consists of digits, it also accepts
u'²₂' and other unicode digits.

Oh, I didn't know that last part! Thanks.
I get a bit confused by the [0], thinking it was checking a single
character.

--
Gabriel Genellina

[Fredrik Lundh]

Re: Avoiding &quot;invali d literal for int()&quot; exception

Gabriel Genellina wrote:

>>elif uniList[0].isdigit():

>>

>The last does not work. Not only that it accepts numbers greater than 9
>because it checks if the whole string consists of digits, it also accepts
>u'²₂' and other unicode digits.

>
Oh, I didn't know that last part! Thanks.
I get a bit confused by the [0], thinking it was checking a single
character.

if you really want to use isdigit(), writing

uniList[0].encode("ascii" , "ignore").isdig it()

should solve the unicode issue, I think.

</F>